12.012 divided by 5.6

hmu also What is the sum and classification of Two-fifths + StartRoot 88 EndRoot? 9.78083151..., irrational 9.78083151..., ratio

schepotkina [342]

Answer:

9.78083151 irrational

Step-by-step explanation:

Here, we want to sum 2/5 + √(88) and check if it is rational or irrational

2/5 = 0.4

√88 = 2 √22

So 0.4 + 2 √22

So what we want to do here is add a rational number to an irrational number. Kindly recall that surds are irrational numbers.

Mathematically, adding a rational number to an irrational one gives an irrational result

so we have;

9.780831519647 irrational

4 0

2 years ago

Read 2 more answers

[Q71 Suppose that the height, in inches, of a 25-year-old man is a normal random variable with parameters g = 71 inch and 02 = 6

viktelen [127]

Answer: (a) Percentage of 25 year old men that are above 6 feet 2 inches is 11.5%.

(b) Percentage of 25 year old men in the 6 footer club that are above 6 feet 5 inches are 2.4%.

Step-by-step explanation:

Given that,

Height (in inches) of a 25 year old man is a normal random variable with mean $g=71$ and variance $o^{2} =6.25$ .

To find: (a) What percentage of 25 year old men are 6 feet, 2 inches tall

(b) What percentage of 25 year old men in the 6 footer club are over 6 feet. 5 inches.

Now,

(a) To calculate the percentage of men, we have to calculate the probability

P[Height of a 25 year old man is over 6 feet 2 inches]= P[X> $74in$ ]

P[X>74] = P[ $\frac{X-g}{o}$ > $\frac{74-71}{2.5}$ ]

= P[Z > 1.2]

= 1 - P[Z ≤ 1.2]

= 1 - Ф (1.2)

= 1 - 0.8849

= 0.1151

Thus, percentage of 25 year old men that are above 6 feet 2 inches is 11.5%.

(b) P[Height of 25 year old man is above 6 feet 5 inches gives that he is above 6 feet] = P[X, $6ft$ $5in$ - X, $6ft$ ]

P[X > $6ft$ $5in$ I X > $6ft$ ] = P[X > 77 I X > 72]

= $\frac{P[X > 77]}{P[ X > 72]}$

= $\frac{P[\frac{X - g}{o}>\frac{77-71}{2.5}] }{P[\frac{X-g}{o} >\frac{72-71}{2.5}] }$

= $\frac{P[Z >2.4]}{P[Z>0.4]}$

= $\frac{1-P[Z\leq2.4] }{1-P[Z\leq0.4] }$

= $\frac{1-0.9918}{1-0.6554}$

= $\frac{0.0082}{0.3446}$

= 0.024

Thus, Percentage of 25 year old men in the 6 footer club that are above 6 feet 5 inches are 2.4%.

4 0

2 years ago

A recent survey of 8,000 high school students found that the mean price of a prom dress was $195.00 with a standard deviation of

KiRa [710]

To calculate the z-statistic, we must first calculate the standard error.

Standard error is standard deviation divided by the square root of the population. In this case, it is equal to 2.68.

The z-score is defined the distance from the sample to the population mean in units of standard error.

z = (195 – 208)/2.68 = -4.86

5 0

1 year ago

A basketball with a diameter of 9.5 in. is placed in a cubic box with sides 15 in. long. How many cubic inches of packing foam a

Doss [256]

Answer:

The volume of foam needed to fill the box is approximately 2926.1 cubic inches.

Step-by-step explanation:

To calculate the amount of foaming that is needed to fill the rest of the box we first need to calculate the volume of the box and the volume of the ball. Since the box is cubic it's volume is given by the formula below, while the formula for the basketball, a sphere, is also shown.

Vcube = a³

Vsphere = (4*pi*r³)/3

Where a is the side of the box and r is the radius of the box. The radius is half of the diameter. Applying the data from the problem to the expressions, we have:

Vcube = 15³ = 3375 cubic inches

Vsphere = (4*pi*(9.5/2)³)/3 = 448.921

The volume of foam there is needed to complete the box is the subtraction between the two volumes above:

Vfoam = Vcube - Vsphere = 3375 - 448.921 = 2926.079 cubic inches

The volume of foam needed to fill the box is approximately 2926.1 cubic inches.

4 0

2 years ago

A cell phone tower at point A receives a cell phone signal from the southeast. A cell phone tower at point B receives a signal f

never [62]

Answer: Postulate 1: -4,-4

Postulate 2: D. The postulates guarantee that unique lines can be draw that they will meet at a unique point.

Step-by-step explanation:

7 0

1 year ago