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pav-90 [236]
2 years ago
9

Bill wants to rent a car. Rental company A charges $35 per day plus $0.10 per mile driven. Rental company B charges $25 per day

plus $0.15 per mile driven. After how many miles driven will the price charged by each company be the same?
Mathematics
2 answers:
Llana [10]2 years ago
7 0
35 + 0.10m = 25 + 0.15m
35 - 25 = 0.15m - 0.10m
10 = 0.05m
10 / 0.05 = m
200 = m.....the price will be the same at 200 miles...they will both cost : $ 55
luda_lava [24]2 years ago
6 0

Answer:

200 miles.

Step-by-step explanation:

Let m represent number of miles.

We have been given that rental company A charges $35 per day plus $0.10 per mile driven. So total cost of m miles by company A would be 0.10m+35.

We are also told that rental company B charges $25 per day plus $0.15 per mile driven. So total cost of m miles by company B would be 0.15m+25.

To find the number of miles that will result in same rental, we will equate both expressions and solve for m.

0.15m+25=0.10m+35

0.15m-0.10m+25=0.10m-0.10m+35

0.05m+25=35

0.05m+25-25=35-25

0.05m=10

\frac{0.05m}{0.05}=\frac{10}{0.05}

m=200

Therefore, after 200 miles the prices charged by each company would be the same.

Guest
1 year ago
thank you
Guest
1 year ago
for helping me with this
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