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snow_lady [41]
2 years ago
13

WILL MARK AS BRAINLIEST!!!The chart below lists the original and sale prices of items at a clothing store. Clothing Prices Origi

nal price Sale price $7.99 $5.59 $10.99 $7.69 $12.99 $9.09 $15.99 $11.19 $24.99 $17.49 $29.99 $20.99 Which statement best describes why the sale price is a function of the original price? As the original price increases, the sale price also increases. The sale price is always less than the original price. For every original price, there is exactly one sale price. The sales price is never less than zero.
Mathematics
2 answers:
Elena L [17]2 years ago
5 0
<span>
$7.99 > $5.59
$10.99 </span>> <span>$7.69
$12.99 </span>> <span>$9.09
$15.99 </span>> <span>$11.19
$24.99 </span>> <span>$17.49
$29.99 </span>> $20.99


Anestetic [448]2 years ago
3 0
Answer: B -  <span>The sale price is always less than the original price.</span><span>

$7.99 > $5.59
$10.99 </span>> <span>$7.69
$12.99 </span>> <span>$9.09
$15.99 </span>> <span>$11.19
$24.99 </span>> <span>$17.49
$29.99 </span>> $20.99
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Answer:

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Step-by-step explanation:

Fe^{2+} (aq) +2e^{-}\rightarrow Fe(s); ​E​° = - 0.41 V

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Iron having negative value of reduction potential .So ,that means that it will loose electron easily and get oxidized.Hence, will be at anode.

E^{o}_{cell}=Reduction potential of cathode - Reduction potential of anode

E^{o}_{cell}=E^{o}_c-E^{o}_a

=0.80 V-(-0.41 V)=1.21 V

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n = 2

To calculate equilibrium constant, we use the relation between Gibbs free energy, which is:

\Delta G^o=-nfE^o_{cell}

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\Delta G^o=-RT\ln K_{eq}

Equating these two equations, we get:

nfE^o_{cell}=RT\ln K_{eq}

where,

n = number of electrons transferred = 2

F = Faraday's constant = 96500 C

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R = Gas constant = 8.314 J/K.mol

T = temperature of the reaction = 25^oC=[273+25]=298K

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\ln K_{eq}=9.3478

\log K_{eq}=\frac{9.3478}{2.303}=4.0921

4.0921 is the logarithm of the equilibrium constant.

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Answer:

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The answer is C.

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After this step, the answer SHOULD HAVE been:

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Let me know if you need any clarifications, thanks!

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