<h2>Answer</h2>
0.43
<h2>Explanation</h2>
Remember that 
Since the problem is telling us "Among tenth graders", we must focus on the 10th graders row only. From the row, we can infer that the frequency is the number of 10th graders who prefer going to sporting events, so 
. Now, the sum of all frequencies will be the sum of all the 10th graders, so 
. Let's replace the values:
And rounded to the nearest hundredth:
27
Multiply 10 and 3 because thats how much each book is worth.
Then divide 810 by 30
The answer is 27
Answer:hey bro you got a picture of it?
Step-by-step explanation:
OK So this is how u do this:-
0.048*30=1.44
Hope I helped:D
Use formula
![\sqrt[3]{27(\cos{330^o}+i\sin{330^o})} \\\sqrt[3]{27e^{i330^o} } \\ \sqrt[3]{27} \sqrt[3]{e^{i330^o}} \\ \sqrt[3]{3^3} \sqrt[3]{e^{i110^o\times 3}} \\ \sqrt[3]{3^3} \sqrt[3]{(e^{i110^o})^ 3}} \\ 3e^{i110^o} \\3(\cos{110^o}+i\sin{110^o})](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B27%28%5Ccos%7B330%5Eo%7D%2Bi%5Csin%7B330%5Eo%7D%29%7D%20%0A%5C%5C%5Csqrt%5B3%5D%7B27e%5E%7Bi330%5Eo%7D%20%7D%0A%5C%5C%20%20%5Csqrt%5B3%5D%7B27%7D%20%20%5Csqrt%5B3%5D%7Be%5E%7Bi330%5Eo%7D%7D%20%0A%5C%5C%20%5Csqrt%5B3%5D%7B3%5E3%7D%20%5Csqrt%5B3%5D%7Be%5E%7Bi110%5Eo%5Ctimes%203%7D%7D%20%0A%5C%5C%20%5Csqrt%5B3%5D%7B3%5E3%7D%20%5Csqrt%5B3%5D%7B%28e%5E%7Bi110%5Eo%7D%29%5E%203%7D%7D%20%0A%5C%5C%203e%5E%7Bi110%5Eo%7D%0A%5C%5C3%28%5Ccos%7B110%5Eo%7D%2Bi%5Csin%7B110%5Eo%7D%29)
Since
and
there are two more solutions:
1.
2.
