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2 years ago

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Mark and his friends order two pizzas of the same size the first pizza is cut into 6 slices of equal size the second pizza is cu

t into 4 slices of equal size each person plans to take 2 slices of pizza Mark concludes that he would get more pizza by taking 1 slice from each pizza instead of 2 slices from the first pizza explain why mark is correct

1 answer:

Anettt [7]2 years ago

3 0

Answer:

The first pizza is 6 slices, so each slice is 1/6 of a pizza. The second pizza is 4 slices, so each slice is 1/4 of a pizza. If you were to take one slice of each, you would get 1/6 +1/4 slice, which would be 5/12 of a pizza, as opposed to if you took 2 slices of the first pizza, which would only be 4/12 of a pizza.

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If you add 12 marshmallows to each of 5 bags of marshmallows, and each bag started with the same number of marshmallows, the tot

aev [14]

Answer:

The expression that is equivalent to the given expression is:

5x+60

Step-by-step explanation:

It is given that:

if you add 12 marshmallows to each of 5 bags of marshmallows, and each bag started with the same number of marshmallows.

so, let x be the initial number of marshmallows in each bag and now 12 are added to each bag this means that the number of marshmallows in each bag is:

x+12

Hence, total number of marshmallows in 5 bags is:

5(x+12)=5×x+5×12

5(x+12)=5x+60

Hence, the answer is:

5x+60

8 0

2 years ago

The base of an aquarium with given volume V is made of slate and the sides are made of glass. If the slate costs seven times as

lubasha [3.4K]

Answer:

$l = \sqrt[3]{\frac{2V}{7}}$ $b = \sqrt[3]{\frac{2V}{7}}$ $h = \sqrt[3]{\frac{49V}{4}}$

Step-by-step explanation:

Represent the volume of the box with V and the dimensions with l, b and h.

The volume (V) is:

$V = l * b * h$

Make h the subject of the formula

$h = \frac{V}{lb}$

The surface area (S) of the aquarium is:

$S = lb + 2(lh + bh)$

Where lb represents the area of the base (i.e. slate):

The cost (C) of the surface area is:

$C = 7 * lb + 1 * 2(lh + bh)$

$C = 7lb + 2(lh + bh)$

$C = 7lb + 2h(l + b)$

Substitute $\frac{V}{lb}$ for h in the above equation

$C = 7lb + 2*\frac{V}{lb}(l + b)$

$C = 7lb + \frac{2V}{lb}(l + b)$

$C = 7lb + \frac{2V}{b} + \frac{2V}{l}$

Differentiate with respect to l and with respect to b

$C_l=7b - \frac{2V}{l^2}$ $=0$

$C_b=7l - \frac{2V}{b^2}$ $=0$

To solve for b and l, we equate both equations and set l to b (to minimize the cost)

$7b - \frac{2V}{l^2}=7l - \frac{2V}{b^2}$

$7l - \frac{2V}{l^2}=7b - \frac{2V}{b^2}$

By comparison:

$l =b$

$C_l=7b - \frac{2V}{l^2}$ $=0$ becomes

$7l - \frac{2V}{l^2}=0$

$7l = \frac{2V}{l^2}$

Cross Multiply

$7l^3 = 2V$

Solve for l

$l^3 = \frac{2V}{7}$

$l = \sqrt[3]{\frac{2V}{7}}$

Recall that: $l =b$

$b = \sqrt[3]{\frac{2V}{7}}$

Also recall that:

$h = \frac{V}{lb}$

$h = \frac{V}{\sqrt[3]{\frac{2V}{7}}*\sqrt[3]{\frac{2V}{7}}}$

$h = \frac{V}{\sqrt[3]{\frac{4V^2}{49}}}$

Apply law of indices

$h = \sqrt[3]{\frac{49V^3}{4V^2}}$

$h = \sqrt[3]{\frac{49V}{4}}$

The dimension that minimizes the cost of material of the aquarium is:

$l = \sqrt[3]{\frac{2V}{7}}$ $b = \sqrt[3]{\frac{2V}{7}}$ $h = \sqrt[3]{\frac{49V}{4}}$

8 0

2 years ago

Shannon graphed the system of equations. 7x – 4y= –8 y = x – 3 What is the closest approximate solution to the system of equatio

Butoxors [25]

The graph shows the solution of your equations is
.. (x, y) = (-6 2/3, -9 2/3)

The closest point to that of the choices offered is (-5, -7.2).

___
The offered "approximations" are not very good approximations.

5 0

2 years ago

Read 2 more answers

Andrei has a job in the circus walking on stilts. Andrei is 11/10 meters tall. The foot supports of his stilts are 23/10 meters

vovangra [49]

First, add. 11/10 + 23/10 = 34/10
You can then simplify by finding the greatest common factor (2)
34/2, 10/2 = 17/5, or 3 and 2/5
Andrei is 3 and 2/5 meters tall

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2 years ago

The triangles shown below must be congruent.

timofeeve [1]

Answer: True

Step-by-step explanation: The angles given are the same AND the side given us the same. The triangle has been reflected, but the reflection is still congruent.

7 0

2 years ago