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djverab [1.8K]
1 year ago
11

Which decimals written in expanded form are greater than 5.3? Check all that apply. 5 + 0.3 + 0.00 5 + 0.3 + 0.001 (5 × 1) + (2

× 0.1) + (9 × 0.01) (5 × 1) + (3 × 0.1) + (3 × 0.01) (6 × 1) + (2 × 0.1) + (1 × 0.01)
Mathematics
1 answer:
Ksenya-84 [330]1 year ago
3 0

Answer:

Any number in form of x.y = x (1) + 1/10 (y)

where x = 5 & y > 3 , or x > 5

Step-by-step explanation:

Expanded form of 5.3 = 5 (1) + 3 (1/10)

Some decimals written in expanded form that are greater than 5.3    :

5 (1) + 4 (1/10) = 5.4

6 (1) + 2 (1/10) = 6.2  

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Mary weighs n kg while her sister weighs 15 kg less. How many times is Mary heavier than her sister?
kari74 [83]

Answer:

Mary is  \frac{n}{n-15}  times heavier than her sister

Step-by-step explanation:

Mary's Weight = n

Sister's Weight = n - 15

To find how many times mary is heavier, we need to multiply "that many time" [let it be x] with sister's weight to get Mary's weight.

<u>e.g. </u>If someone weighs 100 and another person 50, 50 * 2 = 100, thus, 100 kg person is 2 times heaving. We do same for this:

(n - 15) * x = n

x = n/(n - 15)

3 0
2 years ago
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Thirty-two percent of fish in a large lake are bass. Imagine scooping out a simple random sample of 15 fish from the lake and ob
klio [65]

Answer:

Thirty-two percent of fish in a large lake are bass. Imagine scooping out a simple random sample of 15 fish from the lake and observing the sample proportion of bass. What is the standard deviation of the sampling distribution? Determine whether the 10% condition is met.

A.  The standard deviation is 0.8795. The 10% condition is met because it is very likely there are more than 150 bass in the lake.

B. The standard deviation is 0.8795. The 10% condition is not met because there are less than 150 bass in the lake.

C. The standard deviation is 0.1204. The 10% condition is met because it is very likely there are more than 150 bass in the lake.

D. The standard deviation is 0.1204. The 10% condition is not met because there are less than 150 bass in the lake.

E. We are unable to determine the standard deviation because we do not know the sample mean. The 10% condition is met because it is very likely there are more than 150 bass in the lake

The answer is E.

6 0
2 years ago
On a certain​ route, an airline carries 7000 passengers per​ month, each paying ​$30. A market survey indicates that for each​ $
KengaRu [80]

Answer:

The ticket price that maximizes revenue is $50.

The maximum monthly revenue is $250,000.

Step-by-step explanation:

We have to write a function that describes the revenue of the airline.

We know one point of this function: when the price is $30, the amount of passengers is 7000.

We also know that for an increase of $1 in the ticket price, the amount of passengers will decrease by 100.

Then, we can write the revenue as the multiplication of price and passengers:

R=p\cdot N=(30+x)(7000-x)

where x is the variation in the price of the ticket.

Then, if we derive R in function of x, and equal to 0, we will have the value of x that maximizes the revenue.

R(x)=(30+x)(7000-100x)=30\cdot7000-30\cdot100x+7000x-100x^2\\\\R(x)=-100x^2+(7000-3000)x+210000\\\\R(x)=-100x^2+4000x+210000\\\\\\\dfrac{dR}{dx}=100(-2x)+4000=0\\\\\\200x=4000\\\\x=4000/200=20

We know that the increment in price (from the $30 level) that maximizes the revenue is $20, so the price should be:

p=30+x=30+20=50

The maximum monthly revenue is:

R(x)=(30+x)(7000-100x)\\\\R(20)=(30+20)(7000-100\cdot20)\\\\R(20)=50\cdot5000\\\\R(20)=250000

3 0
2 years ago
A pet store has 10 ​puppies, including 3 ​poodles, 4 ​terriers, and 3 retrievers. if rebecka and​ aaron, in that​ order, each se
olganol [36]
P(both poodle) = (3/10)(3/10) = 9/100

Answer: The probability of choosing the same puppy is 9/100
6 0
2 years ago
The true average diameter of ball bearings of a certain type is supposed to be 0.5 in. A one-sample t test will be carried out t
Naily [24]

Answer:

Option C - Do not reject the null hypothesis. There is not sufficient evidence that the true diameter differs from 0.5 in

Step-by-step explanation:

We are given;

n = 15

t-value = 1.66

Significance level;α = 0.05

So, DF = n - 1 = 15 - 1 = 14

From the one-sample t - table attached, we can see that the p - value of 0.06 at a t-value of 1.66 and a DF of 14

Now, since the P-value is 0.06,it is greater than the significance level of 0.05. Thus we do not reject the null hypothesis. We conclude that there is not sufficient evidence that the true diameter differs from 0.5 in.

8 0
1 year ago
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