Question

Calculate the equation of the line if two points are (1,6) and (5,0) Hint, you will have to find the slope of the line and then sub it into the equation y=mx+b
PLEASE ANSWER

Answer 1

Answer:

The equation is $y=\frac{-3}{2} x-9$

Step-by-step explanation:

First, you will have to find the slope of the two points.To do that, you will have to use the formula : $m=\frac{y_{2}-y_{1} }{x_{2} -x_{1} }$

Our points are $(1,6)$ and $(5,0)$

We will have to substitute the points into the formula.

$m=\frac{0-6}{5-1}$

Then, we will simplify

$m= \frac{-6}{4}$

We could simplify that fraction into $\frac{-3}{2}$

So, our slope is $\frac{-3}{2}$

We will have to pick a coordinate point, and choose. I chose $(1,6)$

We will substitute the x-value and the y-value of the coordinate point, including our slope, to calculate the y-intercept.

The formula we will be using is $y=mx+b$

We will substitute in our values which will make it look like:

$6=\frac{-3}{2} (1)+b$

We will then multiply $\frac{-3}{2}$ by $1$ which will stay the same.

Then, we will multiply $\frac{-3}{2}$ by $6$ which will equal $-9$

$-9=b$

Hence, the equation for our line is $y=\frac{-3}{2} x-9$

Hope it helped:D

-Jazz