This problem can be expressed through the equation:
x+3x+10= 90
To solve it we subtract 10 on both sides
→x+3x=80
Add x and 3x
→4x=80
And divide each side by 4
→x=80/4
→x=20
ANSWER:
20
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A sphere. It is a perfectly circular and even shape, so all cross sections would be circles.
well, if the expression is simply 12-2, then you would do simple subtraction and your answer would be 10. that would be simplest form. you cannot take it any simpler because there is nothing else left now. your answer would be 10.
Answer:
x^2/12 - y^2/4 = 1
Step-by-step explanation:
As the diretrices have simetrical values of x and have y = 0, the center is located at (0,0)
The formula for the diretrices is:
x1 = -a/e and x2 = a/e
And the foci is located at (a*e, 0) and (-a*e, 0)
So we have that:
a/e = 3
a*e = 4
From the first equation, we have a = 3e. Using this in the second equation, we have:
3e*e = 4
e^2 = 4/3
e = 1.1547
Now finding the value of a, we have:
a = 3*1.1547 = 3.4641
Now, as we have that b^2 = a^2*(e^2 - 1), we can find the value of b:
b^2 = 3.4641^2 * (1.1547^2 - 1) = 4
b = 2
So the equation of the hyperbola (with vertical diretrices and center in (0,0)) is:
x^2/a^2 - y^2/b^2 = 1
x^2/12 - y^2/4 = 1