If a carton contains 6 eggs, how many eggs are there in 13 cartons? would it be 6x13?? which is equal to 78 I'm not sure.

Find the values of y = r(x) = ∛x for x = –2.197, –1.331, 0, 1.331, 2.197, 3.375, 4.913 Then plot the corresponding points on a g

lions [1.4K]

The cube root values and a graph of them are shown in the attachment.

_____

The cube root of a negative number is negative. These all have exact (rational) cube roots.

8 0

2 years ago

Ice cream usually comes in 1.5-quart boxes (48 fluid ounces), and ice cream scoops hold about 2 ounces. However, there is some v

Troyanec [42]

Answer:

(a) The expected value and standard deviation of the amount of ice cream served at the party are 54 ounces and 1.25 ounces respectively.

(b) The expected value and standard deviation of the amount of ice cream left in the box after scooping out one scoop are 46 ounces and 1.031 ounces respectively.

(c) Because the variance of each variable is dependent on the other.

Step-by-step explanation:

The random variable <em>X</em> and <em>Y</em> are defined as follows:

<em>X</em> = amount of ice cream in the box

<em>Y</em> = amount of ice cream scooped out

The information provided is:

E (X) = 48

SD (X) = 1

V (X) = 1

E (Y) = 2

SD (Y) = 0.25

V (Y) = 0.0625

(a)

The total amount of ice-cream served at the party can be expressed as:

<em>X</em> + 3<em>Y</em>.

Compute the expected value of (<em>X</em> + 3<em>Y</em>) as follows:

$E(X+3Y)=E(X)+3E(Y)\\= 48+(3\times2)\\=48+6\\=54$

Compute the variance of (<em>X</em> + 3<em>Y</em>) as follows:

$V(X+3Y) = V (X)+3^{2}V(Y)+2\times 3Cov (X,Y)\\=1+(9\times0.0625)+0\\=1.5625$

Then the standard deviation of (<em>X</em> + 3<em>Y</em>) is:

$SD(X + 3Y) =\sqrt{V(X + 3Y)}\\\sqrt{1.5625}\\=1.25$

Thus, the expected value and standard deviation of the amount of ice cream served at the party are 54 ounces and 1.25 ounces respectively.

(b)

The amount of ice-cream left in the box after scooping out one scoop is represented as follows:

<em>X</em> - <em>Y</em>.

Compute the expected value of (<em>X</em> - <em>Y</em>) as follows:

$E(X-Y)=E(X)-E(Y)\\=48-2\\=46$

Compute the variance of (<em>X</em> - <em>Y</em>) as follows:

$V(X - Y) =V(X)+V(Y)-2Cov(X,Y)\\=1+0.0625-0\\=1.0625$

Then the standard deviation of (<em>X</em> - <em>Y</em>) is:

$SD(X-Y) =\sqrt{V(X -Y)}\\\sqrt{1.0625}\\=1.031$

Thus, the expected value and standard deviation of the amount of ice cream left in the box after scooping out one scoop are 46 ounces and 1.031 ounces respectively.

(c)

The variance of the sum or difference of two variables is computed by adding the individual variances. This is because the variance of each variable is dependent on the others.

7 0

2 years ago

Each time Kristine gets paid, she spends $20 and saves the rest. If the amount Kristine earns is represented by x and the amount

faust18 [17]

We are given that Kristine spends $20 and saves the rest each time she get paid.

We can use slope-intercept form y=mx+b to represent the equation.

Where x represents the amount Kristine earns and y represents the amount she saves.

Kristine spends $20. Therefore b= -20.

Plugging mx as just x and b=-20.

<h3>y = x-20.</h3><h3>If we plug y=0, we get </h3><h3>0 = x-20</h3><h3>x=20.</h3><h3>We can see in 4th option we have x-intercept =20.</h3><h3>Therefore, correct option is 4th option. </h3><h3 />

4 0

2 years ago

Read 2 more answers

A random survey was taken in Centerville. People in twenty-five homes were asked how many cars were registered to their househol

Ulleksa [173]

In order to find the mean, you first count how many numbers are there. Then, you add all numbers together and divide them by the total of numbers. In this case, you would add (1+2+1+0+3+4+0+1+1+1+2+2+3+2+3+2+1+4+0+0+2+2+1+1+1), which equals to 40. The total of numbers is 25. You divide 40 by 25, and it would get you 1.6. Therefore, your mean is 1.6.

To calculate the median, you list the numbers from least to greatest, and find the middle number. The list for this survey would be 0, 0, 0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 2, 2, 2, 2, 2, 2, 2, 3, 3, 3, 4, 4. The middle number of this list is 1, therefore, your median is 1.

The mode is simply the number that appears the most in this list. There are 4 zeroes, 9 ones, 7 twos, 3 threes, and 2 fours. The most in this list would be 1, because there are 9 of them. Your mode is 1.

Mean - 1.6
Median - 1
Mode - 1

Answer: A. 1.6, 1, 1

8 0

2 years ago

Read 2 more answers

A candy maker produces mints that have a label weight of 20.4 grams. Assume that the distribution of the weights of these mints

Sliva [168]

Answer:

a)0.099834

b) 0

Step-by-step explanation:

To solve for this question we would be using , z.score formula.

The formula for calculating a z-score is is z = (x-μ)/σ, where x is the raw score, μ is the population mean, and σ is the population standard deviation.

A candy maker produces mints that have a label weight of 20.4 grams. Assume that the distribution of the weights of these mints is normal with mean 21.37 and variance 0.16.

a) Find the probability that the weight of a single mint selected at random from the production line is less than 20.857 grams.

Standard Deviation = √variance

= √0.16 = 0.4

Standard deviation = 0.4

Mean = 21.37

x = 20.857

z = (x-μ)/σ

z = 20.857 - 21.37/0.4

z = -1.2825

P-value from Z-Table:

P(x<20.857) = 0.099834

b) During a shift, a sample of 100 mints is selected at random and weighed. Approximate the probability that in the selected sample there are at most 5 mints that weigh less than 20.857 grams.

z score formula used = (x-μ)/σ/√n

x = 20.857

Standard deviation = 0.4

Mean = 21.37

n = 100

z = 20.857 - 21.37/0.4/√100

= 20.857 - 21.37/ 0.4/10

= 20.857 - 21.37/ 0.04

= -12.825

P-value from Z-Table:

P(x<20.857) = 0

c) Find the approximate probability that the sample mean of the 100 mints selected is greater than 21.31 and less than 21.39.

5 0

2 years ago