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2 years ago

If a carton contains 6 eggs, how many eggs are there in 13 cartons? would it be 6x13?? which is equal to 78 I'm not sure.

Mathematics

2 answers:

dalvyx [7]2 years ago

7 0

Answer:

Yes it would be 6x13=78

Step-by-step explanation:

cross multiplication and divide:

1 cartoon = 6 eggs

13 cartoons = x

qwelly [4]2 years ago

6 0

Answer:

Step-by-step explanation:

13 × 6 = 78 eggs

Hope this helps! :)

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Triangle ABC and triangle CDE are similar right triangles. Which proportion can be used to show that the slope of AC is equal to

shusha [124]

Answer:

Option C is the correct option.

Step-by-step explanation:

Considering the triangle ABC, the slope of the line CA is given by $\frac{AB}{BC} = \frac{6 - 3}{-3 - (- 1)}$

Again, considering the triangle CDE, the slope of the line EC is given by

$\frac{CD}{DE} = \frac{3 - (- 3)}{- 1 - 3 }$

Since CA and EC represents the same straight line so, we can write

$\frac{6 - 3}{-3 - (- 1)} = \frac{3 - (- 3)}{- 1 - 3 }$

Therefore, option C is the correct option. (Answer)

8 0

2 years ago

Decrease £19064.67 by 9.5%<br>Give your answer rounded to 2 DP.<br>

Advocard [28]

Answer:

£17253.53 to the nearest hundredth.

Step-by-step explanation:

Decreasing by 9,5% is equivalent to multiplying by 1 - 0.095 = 0.905.

19064.67 * 0.905

= £17253.52635.

8 0

2 years ago

Read 2 more answers

What is 2 hundreds + 15 tens + 6 ones

qwelly [4]

Two one hundred is 200.
15 tens is 150.
Six ones is the same.
$200 + 150 + 6 = 456$

5 0

2 years ago

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Jordan used the distributive property to write an expression that is equivalent to 6c – 48. 6c - 48 is equivalent to 6(c - 48) I

Katyanochek1 [597]

It’s incorrect.

The correct answer is 6(c - 8)

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2 years ago

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The first term of a finite geometric series is 6 and the last term is 4374. The sum of all the term os 6558. find the common rat

Oliga [24]

A geometric series is written as $ar^n$ , where $a$ is the first term of the series and $r$ is the common ratio.

In other words, to compute the next term in the series you have to multiply the previous one by $r$ .

Since we know that the first time is 6 (but we don't know the common ratio), the first terms are

$6, 6r, 6r^2, 6r^3, 6r^4, 6r^5, \ldots$ .

Let's use the other information, since the last term is $4374 > 6$ , we know that $r>1$ , otherwise the terms would be bigger and bigger.

The information about the sum tells us that

$\displaystyle \sum_{i=0}^n 6r^i = 6\sum_{i=0}^n r^i = 6558$

We have a formula to compute the sum of the powers of a certain variable, namely

$\displaystyle \sum_{i=0}^n r^i = \cfrac{r^{n+1}-1}{r-1}$

So, the equation becomes

$6\cfrac{r^{n+1}-1}{r-1} = 6558$

The only integer solution to this expression is $n=6, r=3$ .

If you want to check the result, we have

$6+6*3+6*3^2+6*3^3+6*3^4+6*3^5+6*3^6 = 6558$

and the last term is

$6*3^6 = 4374$

7 0

2 years ago