TOGETHER , TWO PEOPLE EARN $28,000. ONE EARNS $2,000 MORE THAN THE OTHER. HOW MUCH IS SMALLER INCOME?

Without using technology, describe the end behavior of f(x) = −3x38 + 7x3 − 12x + 13.

Vedmedyk [2.9K]

Second option: down on the left, down on the right.

Clearly when x is bigger than one the term -x^38 will dominate the result.

When absolute value of x grows, x^38 becomes a larger positive number and - x^38 a larger negative number. Then both ends of the function tend to negative infinity.

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2 years ago

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From Statistics and Data Analysis from Elementary to Intermediate by Tamhane and Dunlop, pg 265. A thermostat used in an electri

Leviafan [203]

Answer:

$t=\frac{201.77-200}{\frac{2.41}{\sqrt{10}}}=2.32$

The degrees of freedom are given by:

$df=n-1=10-1=9$

The p value for this case is given by:

$p_v =2*P(t_{(9)}>2.32)=0.0455$

For this case since the p value is lower than the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly different from 200 F.

Step-by-step explanation:

Information given

data: 202.2 203.4 200.5 202.5 206.3 198.0 203.7 200.8 201.3 199.0

We can calculate the sample mean and deviation with the following formulas:

$\bar X= \frac{\sum_{i=1}^n X_i}{n}$

$\sigma=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

$\bar X=201.77$ represent the sample mean

$s=2.41$ represent the sample standard deviation

$n=10$ sample size

$\mu_o =200$ represent the value that we want to test

$\alpha=0.05$ represent the significance level for the hypothesis test.

t would represent the statistic

$p_v$ represent the p value for the test

Hypothesis to test

We want to determine if the true mean is equal to 200, the system of hypothesis are :

Null hypothesis: $\mu = 200$

Alternative hypothesis: $\mu = 200$

The statistic for this case is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

The statistic is given by:

$t=\frac{201.77-200}{\frac{2.41}{\sqrt{10}}}=2.32$

The degrees of freedom are given by:

$df=n-1=10-1=9$

The p value for this case is given by:

$p_v =2*P(t_{(9)}>2.32)=0.0455$

For this case since the p value is lower than the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly different from 200 F.

4 0

2 years ago

Ellen can spend at most $8.25 on snacks for a party. Carrots cost $2 per pack and grapes cost 0.75 per bag. Write a linear inequ

UkoKoshka [18]

2c + .75g less than or equal to 8.25

c being how many packs of carrot

g being how many bags of grapes

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2 years ago

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This diagram shows triangles ABC and PQR. ABC is mapped to PQR by combining two single transformations. The first is a rotation

dedylja [7]