Answer:
The graph attached has a solution. As you can see, the parabolic function DOES intercept the line at (0, 3). Therefore, the solution to that sytem of equation is the point (0, 3).
A system of equations has no solutions when their graphs do NOT meet at any point.
<em><u>Your answer: </u></em> a reflection across the y-axis followed by a clockwise rotation 90° about the origin. A clockwise rotation 90° about the origin followed by a reflection across the x-axis. A counter-clockwise rotation 90° about the origin followed by a reflection across the y-axis. A reflection across the x-axis followed by a counter-clockwise rotation 90° about the origin.
Hope this helps <3
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Ps. It would mean a lot if you marked this brainliest
Answer:
ai) n(E⋂C) = ∅ = null
n(E⋂G) = 4
aii) see attachment
bi) n(C⋂G) = x = 1
bii) n(G) only = 3
Step-by-step explanation:
Let chemistry = C
Economic = E
Government = G
n(E) = 12
n(G) = 8
n(C) = 7
ai) number of pupils for economics and chemistry = 0
number of pupils for economics and government = 4
The set notation for both:
n(E⋂C) = ∅ = null
n(E⋂G) = 4
aii) find attached the Venn diagram
bi) n(C⋂G) = ?
Let number of n(C⋂G) = x
From the Venn diagram
n(C) only = 12-4 = 8
n(G) only = 8-(4+x) = 4-x
n(E) only = 7-x
n(E⋂C⋂G) = 0
n(E⋂C) = 0
n(E⋂G) = 4
Total: 8+ 4-x + 7-x + x + 0+0+4 = 22
23 -x = 22
23-22 = x
x = 1
n(C⋂G) = x = 1
Number of pupils that take both chemistry and government = 1
(bii) government only = n(G) only = 4-x
n(G) only = 4-1 = 3
Number of students that take government only = 3
First we multiply 50 and 13 and 3/4
13 and 3/4 could also = 13.75
sooo lets multiply
50 x 13.75 = 687.50
so $687.50 was spent on the stock
now lets fund out how much they sold them for
we multiply 12 and 50
50 x 12 = 600
now we need to find out the loss by subtracting
$687.50 - $600 =$ 87.50
so that means this company lost $87.50 :(
hope this helps :)
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Answer:
this isn’t a 100% guaranteed correct answer but maybe the second option saying “PQ and P’G’ are parallel”
(i’m doing the test rn)
