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givi [52]
1 year ago
13

Tim ran a quarter mile five times yesterday the table above shows the time of each run in minutes and seconds. For example the t

ime 1:07 represents 1 minute and 7 seconds. What is the range in seconds, of the times of times five runs ?
A. 4
B. 6
C. 8
D. 11
Mathematics
2 answers:
monitta1 year ago
3 0
Honestly im not even sure lol
marin [14]1 year ago
3 0

Answer:

See Explanation Below

Step-by-step explanation:

The question is incomplete as the table is missing.

I'll give you a guide to solve questions that look like this.

To calculate the Range of an observation, you only need the highest and the lowest values.

I.e Range = Highest Value - Lowest Value.

Suppose that the table is as follows

Observation --- Time

1 ------ 1:07

2 ------- 1:00

3 ------- 1;11

4 -------- 1:05

5 -------- 1:01

The highest and the least values in the above observation are

1;11 and 1:00 respectively.

Hence, the range is calculated as;

Range = Highest - Lowest

Range = 1:11 - 1:00

Range = 11 seconds

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Of 560 samples of seafood purchased from various kinds of food stores in different regions of a country and genetically compared
frutty [35]

Answer:

a) (0.5256,0.5944)  

c) Criticism is invalid

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 560

Proportion of mislabeled = 56%

\hat{p} = 0.56

a) 90% Confidence interval:

\hat{p}\pm z_{stat}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}

z_{critical}\text{ at}~\alpha_{0.05} = \pm 1.64

Putting the values, we get:

0.56\pm 1.64(\sqrt{\dfrac{0.56(1-0.56)}{560}}) = 0.56\pm 0.0344\\\\=(0.5256,0.5944)

b) Interpretation of confidence interval:

We are 90% confident that the true proportion of all seafood in the country that is mislabeled or misidentified is between 0.5256 and 0.5944 that is 52.56% and 59.44%.

c) Validity of criticism

Conditions for validity:

np > 10\\n(1-p)>10

Verification:

560\times 0.56 = 313.6>10\\560(1-0.56) = 246.4>10

Both the conditions are satisfied. This, the criticism is invalid.

8 0
2 years ago
A government official is in charge of allocating social programs throughout the city of Vancouver. He will decide where these so
otez555 [7]

Answer: (0.132132, 0.274368)

Step-by-step explanation:

Given : A simple random sample of 123 people living in Gastown and finds that 25 have an annual income that is below the poverty line.

i.e. n= 123

\hat{p}=\dfrac{25}{123}\approx0.203252

Critical value for 95% confidence interval : z_{\alpha/2}=1.96

Confidence interval for population :

\hat{p}\pm z_{\alpha/2}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}

i.e. 0.203252\pm (1.96)\sqrt{\dfrac{0.203252(1-0.203252)}{123}}

0.203252\pm (1.96)\sqrt{\dfrac{0.203252(1-0.203252)}{123}}\\\\\0.203252\pm0.071118\\\\=(0.20325-0.071118,\ 0.203252+0.071118)\\\\=(0.132132,\ 0.274368)

Hence, the 95% confidence interval for the true proportion of Gastown residents living below the poverty line : (0.132132, 0.274368)

5 0
2 years ago
∠E and ∠F are vertical angles with m∠E=5x+10 and m∠F=7x−12 .<br><br> What is the value of x?
In-s [12.5K]
Vertical angles are equal...so set ur angles equal to each other and solve for x

5x + 10 = 7x - 12
12 + 10 = 7x - 5x
22 = 2x
22/2 = x
11 = x <==
6 0
2 years ago
a box contains 2 purple marbles, 9 orange marble and seven yellow marble. if you pick 2 without looking wha is the probability t
Ulleksa [173]

Angood job

swer:

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
The average sea level in 1900 at London bridge was 33 feet. In 1990 it was 33.08 feet. Use linear interpolation or extrapolation
eduard

Answer:

In 1956, the height will be 33.05 ft

Step-by-step explanation:

Let +x+ = number of years after 1900

Calll 1900 +x+=+0+

Then 1990 is +x+=+90+

Let +y+ = height in feet

--------------------------

You are gven the points

( 0, 33 )

( 90, 33.08 )

Use general point-slope formula

+%28+y+-+33+%29+%2F+%28+x+-+0+%29+=+%28+33.08+-+33+%29+%2F+%28+90+-+0+%29+

Multiply both sides by +90x+

+90%2A%28+y+-+33+%29+=+.08x+

+90y+-+2970+=+.08x+

+90y+=+.08x+%2B+2970+

+y+=+.000889x+%2B+33+ ( equation to use )

--------------------------

Check:

does it go through ( 90, 33.08 ) ?

+33.08+=+.000889%2A90+%2B+33+

+33.08+=+.08001+%2B+33+

+33.08+=+33.08001+

close enough

-------------------------------

(a)

+x+=+61%0D%0A%7B%7B%7B+y+=+.000889x+%2B+33+

+y+=+.000889%2A61+%2B+33+

+y+=+.0542+%2B+33+

+y+=+33.0542+

In 1961, the height will be 33.05 ft

8 0
2 years ago
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