Question 9 of 10

For every problem-solving activity it's crucial that no less than five alternatives be considered.

matrenka [14]

Yes this is true. For every problem-solving activity it's crucial that no less than five alternatives be considered.

4 0

2 years ago

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Adante begins to evaluate the expression 3 and one-third times 5 and one-fourth using the steps below. 3 and one-third times 5 a

goldenfox [79]

Answer:

(3)(5) + (1/3)(5) + (3)(1/4) + (1/3)(1/4)

Step-by-step explanation:

(3 1/3)(5 1/4) =

= (3 1/3)(5 + 1/4)

= (3 1/3)(5) + (3 1/3)(1/4)

= (3 + 1/3)(5) + (3 + 1/3)(1/4)

= (3)(5) + (1/3)(5) + (3)(1/4) + (1/3)(1/4)

7 0

2 years ago

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There are 20 identical sticks lined up in a row occupying 20 distinct places as follows: 11111111111111111111· Six of them are t

Serga [27]

Answer:

a)38760

b)5005

c)210

Step-by-step explanation:

Given that

20 identical sticks

We have to 6 of them

a)

The number of choice will be $_{6}^{20}\textrm{c}$ .

$_{6}^{20}\textrm{c}=\dfrac{20!}{6!.14!}$

$_{6}^{20}\textrm{c}=38760$

b)

The number of choices if no two of the chosen sticks can be consecutive will be $_{6}^{15}\textrm{c}$ .

$_{6}^{15}\textrm{c}=\dfrac{15!}{6!9!}$

$_{6}^{15}\textrm{c}=5005$

c)

|xx|xx|xx|xx|xx|

Total seven positions are available

So

4-0-0-0-0-0-0 7!/6!=7

3-1-0-0-0-0-0 7!/5!=42

2-2-0-0-0-0-0 7!/2!5!=21

2-1-1-0-0-0-0 7!/2!4!=105

1-1-1-1-0-0-0 7!/4!3!=35

Now by adding all 7+42+21+105+35=210

4 0

2 years ago

Jennifer has a bag of chips that contains 2 red chips and 1 black chips. If she also has a fair die, what is the probability tha

borishaifa [10]

Find each probability separately and then multiply the two together

Probability for even number is 3/6 or 1/2 because their are 3 even numbers out of 6 numbers

Probability to get a black chip is 1 black chip out of 3 totals so 1/3

Multiply 1/3 by 1/2

Answer 1/6

5 0

2 years ago

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Lionel computed the average rate of change in the depth of a pool over a two-week interval to be zero. Which statement must be t

gayaneshka [121]

Answer:The pool must have been the same depth at the start of the interval as it was at the end of the interval.

Step-by-step explanation:

The average rate of change is calculated as:

[final value - initial value] / time interval.

Then, the average rate of change does not take into account intermediates values, and you cannot draw any conclusion about such intermediate values.

In the given case you have:

average rate of change in depth = [final depth - initial depth] / 2 weeks.

0 = [final depth - initial depth] / 2 weeks.

⇒ 0 = final depth - initial depth

⇒ final depth = initial depth.

That is why the conclusion is the second statement of the answer choices: the pool must have been the same depth at the start of the interval as it was at the end of the interval.

In between the pool might have been deeper, more shallow, empty or change in any form, since the average rate of change does not tell the full history but only the net change.

4 0

2 years ago