<u>Answer:</u>
Solving for x in 12x − 39 ≤ 9 and −4x + 3 < −6 we get 2.25 < x ≤ 4
<u>Solution</u>:
Need to find the value of x which satisfies following two given expressions
12x − 39 ≤ 9 ------(1)
−4x + 3 < −6 ------ (2)
Lets first solve expression (1)
12x − 39 ≤ 9
Adding 39 on both sides , we get
12x−39 + 39 ≤ 9 +39
=>12x ≤ 48
=> x ≤ 48/12
=> x ≤ 4
Now solving expression (2)
−4x+3<−6
=> -4x < -6 – 3
=> -4x < -9
=> 4x > 9
=> x > 9/4
=> x > 2.25
So from solution of expression (1) and (2) , we get x ≤ 4 and x > 2.25
Hence required value of x is 2.25 < x ≤ 4.
Answer:
Yes, between 0.84 seconds and 0.85 seconds after the shot is launched.
Step-by-step explanation:
But, the shot is made before two tenths of a second or 0.2 seconds therefore modified equation for ball height is :
Now for the shot to be blocked,the height of shot blocker must be greater than the height of the ball which is shot before 0.2 seconds :
Hence, the shot was blocked between 0.84 and 0.85 seconds after the shot is launched.
This situation can be represented by a step function.If Jalyn purchases 60 shirts the total cost will be $600.At these prices it is cheaper to buy 76 shirts than it is to buy 75 shirts.
Volume of a Right circular cylinder=πr²h
Using "Cavaliers principle" or Just pire logic... it can be understood that...
if we were to cut of the base and top of the cylinder such that it will make up to be a right circular cylinder and join the other two pieces on top; We would obtain a Right circular cylinder With The same radius and height as the Given cylinder.
So;
Given. Base area B=81πcm²
also Base area =πr²
=>πr²=81π cm²
=>r=√81=9cm
Also Given;
Height h=3r
=>Height,h=3×9=27cm
So;Volume of cylinder V=πr²h ;(r²=81,h=27)
=>V=(81×27×22)/7
=>V=6867.18cm³ (approx.)
So,Required Volume =6867.18cm³(approx.)
Hope it helps...
Regards,
Leukonov/Olegion.
