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2 years ago

Is there only one way to create a factor tree? Explain

Mathematics

2 answers:

tatyana61 [14]2 years ago

6 0

No, there are many ways

Zigmanuir [339]2 years ago

3 0

There are different ways to create a factor tree. You could do the normal one that looks something like this:
72
/. \
36. 2
Or this one: 2x2x2x3x3

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housing prices in a certain neighborhood average at 97.86 per square foot. If one house in this neighborhood is 1400 square feet

Arturiano [62]

The average price of such a house is
(97.86/ft²)×(1400 ft²) = 97.86×1400 = 137,004

8 0

2 years ago

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What is the most precise name for quadrilateral ABCD with vertices A(-2,4), B(5,6), C(12,4) and D(5,2)?

Dmitry_Shevchenko [17]

I think its going to be around B or D

6 0

2 years ago

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sarah invests £9600 at a simple interest rate of 8% per year. Work out the value of the investment after 3 years

andre [41]

Answer:

the value of the investment after 3 years= £11,904

Step-by-step explanation:

sarah invests £9600 at a simple interest rate of 8% per year

number of years = 3

Formula for simple interest

I = P*n* r

P is the initial amount invested= 9600

r is the rate of interest = 8% = 0.08

n = number of years = 3

Now we find interest using formula

I = 9600 * 0.08 * 3= 2304

Interest amount is 2,304

Now we add the interest with the initial amount to get the value of investment after 3 years

9600 + 2304= 11904

6 0

2 years ago

A textbook has 500 pages on which typographical errors could occur. Suppose that there are exactly 10 such errors randomly locat

DiKsa [7]

Answer:

The probability of a selection of 50 pages will contain no errors is 0.368

The probability that the selection of the random pages will contain at least two errors is 0.2644

Step-by-step explanation:

From the information given:

Let q represent the no of typographical errors.

Suppose that there are exactly 10 such errors randomly located on a textbook of 500 pages. Let $\mu$ be the random variable that follows a Poisson distribution, then mean $\mu = \dfrac{10}{500}= 0.02$

and the mean that the random selection of 50 pages will contain no error is $\lambda = 50 \times 0.02 =1$

∴

$Pr(q= 0) = \dfrac{e^{-1} (1)^0}{0!}$

Pr(q =0) = 0.368

The probability of a selection of 50 pages will contain no errors is 0.368

The probability that 50 randomly page contains at least 2 errors is computed as follows:

P(X ≥ 2) = 1 - P( X < 2)

P(X ≥ 2) = 1 - [ P(X = 0) + P (X =1 )] since it is less than 2

$P(X \geq 2) = 1 - [ \dfrac{e^{-1} 1^0}{0!} +\dfrac{e^{-1} 1^1}{1!} ]$

$P(X \geq 2) = 1 - [0.3678 +0.3678]$

$P(X \geq 2) = 1 -0.7356$

P(X ≥ 2) = 0.2644

The probability that the selection of the random pages will contain at least two errors is 0.2644

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2 years ago

Select the graph of the solution. Click until the correct graph appears.<br><br> |x| + 3 > 7

JulijaS [17]

Answer:

Graph 3.

Step-by-step explanation:

|x| + 3 > 7

|x| > 4

This means x > 4 or x < -4,

which is the third graph.

5 0

2 years ago

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