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TEA [102]
1 year ago
6

Flying fish use their pectoral fins like airplane wings to glide through the air. Suppose a flying fish reaches a maximum height

of 5 ft after flying a horizontal distance of 33 ft. Write a quadratic function y=a(x-h)^2+k that models the flight path assuming the fish leaves the water at (0,0). Describe how the changing value of a,h, or k affects the flight path

Mathematics
2 answers:
GrogVix [38]1 year ago
7 0

The flight is in the shape of a parabola with a vertex 5 feet above the water and  1/2 * 33 = 16.5 feet horizontally from the point of leaving the water

y = a(x - h)^2 + k

where  (h,k)  is the vertex of the  parabola and here it is (5 , 16.5), so we have the function:-

y = a(x - 16.5)^2 + 5

when x = 0 y = 0  so

0 = a(-16.5)^2 + 5

which gives a = -0.018365

So our function for the flight path is

y = -0.018365(x - 16.5)^2 + 5     Answer



Vlad [161]1 year ago
3 0

Answer:

Equation: y= -0.00459*(x-33)^{2} + 5

Step-by-step explanation:

Using the value as height in axis y, and horizontal distance in axis x

y=a*(x-h)^{2}+k\\  h=33\\k=5\\y=a*(x-33)^{2}+5

X=0, Y=0

y=a*(x-33)^{2}+5\\ 0=a*(0-33)^{2}+5\\a=-\frac{5}{33^{2} } =-0.00459

In the figure can see the motion of the fish while flying like airplane

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John's commute to work is 20kmhr while Sheri's commute is 500mmin. Who has the fastest commute to work in mihrif 1.61km=1mi? A S
Andreyy89

Answer:

A) Sheri has the faster commute by 6.2 miles/hr.

Step-by-step explanation:

Given

John's commute to work =20\ km/hr

Sheri's commute to work  =500\ m/min

1.61\ km = 1\ mile

John's commute to work in miles per hour = \frac{20\ km}{1 hr}\times \frac{1\ mile}{1.61\ km}= 12.42\ miles/hr

Sheri's commute to work in miles per hour =\frac{500\ m}{1\ min}\times \frac{1\ km}{1000\ m}\times \frac{1\ mile}{1.61\ km}\times \frac{60\ min}{1\ hr}= 18.63\ miles/ hr

We can see that Sheri has a faster commute.

Difference between the rates =18.63\ miles/ hr-12.42\ miles/hr=6.21\ miles/hr\approx 6.2\ miles/hr

∴ Sheri has the faster commute by 6.2 miles/hr.

3 0
2 years ago
A businessman bought a car dealership that is incurring a loss of $500,000 a year. He decided to strategize in order to turn the
UkoKoshka [18]
The correct answer would be choice A: 1.

When 3 coins are flipped, there are 8 possible outcomes.

0 Tails = 1 ways
1 Tails = 3 ways
2 Tails = 3 ways
3 Tails = 1 ways

If you add up all the different tails, you could get 12 tails. Divide 12 by 8 and you have 1.5 which is the average number of tails you could expect to get by flipping 3 coins.
4 0
2 years ago
The batting Wang Xiu Ying uses to fill quilts has a thermal conductivity rate of 0.030.030, point, 03 watts (\text{W})(W)left pa
alexgriva [62]

Answer:

0.0003W/cm°C

Step-by-step explanation:

The question is not properly written. Here is the correct question.

The batting wang xiu ying uses to fill quilts has a thermal conductivity rate of 0.03 watts (W) per meter(m) per degree celsius. what is the batting thermal conductivity when w/cm•c

Given the thermal conductivity in W/m°C to be 0.03W/m°C

We are to rewrite the value in W/cm°C

The difference is the unit. The only thing we need to do is to simply convert the unit (metres) in W/m°C to centimeters (cm)

Since 100cm = 1m, 0.03W/m°C can be expressed as shown below;

= 0.03W/m°C

= 0.03 × W/1m×°C

Note that 1m = 100cm, substituting this conversion into the expression, it will become;

= 0.03 × W/100cm × °C

= 0.03/100 × W/cm°C

= 0.0003W/cm°C

Hence the battling thermal conductivity in W/cm°C is 0.0003W/cm°C

4 0
1 year ago
A dealer bought 3 gross buttons at $.38 a dozen. He sold the buttons at 5 cents each. How much was his profit per gross?(12 doze
777dan777 [17]

Answer:

$2.64

Step-by-step explanation:

Selling them at 5 cents each ($0.05), he could sell 1 dozen buttons for

12 * $0.05 = $0.60

As he bought them at $0.38 per dozen, the profit per dozen would be

$0.60 - $0.38 = $0.22

As 12 dozen is 1 gross, the profit per gross would be

12 * $0.22 = $2.64

7 0
1 year ago
Read 2 more answers
Mateus’s bank issued an advertisement saying that 90\%90%90, percent of its customers are satisfied with the bank’s services. Si
densk [106]

Answer:

The probability of getting a sample with 80% satisfied customers or less is 0.0125.

Step-by-step explanation:

We are given that the results of 1000 simulations, each simulating a sample of 80 customers, assuming there are 90 percent satisfied customers.

Let \hat p = <u><em>sample proportion of satisfied customers</em></u>

The z-score probability distribution for the sample proportion is given by;

                                Z  =  \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, p = population proportion of satisfied customers = 90%

            n = sample of customers = 80

Now, the probability of getting a sample with 80% satisfied customers or less is given by = P( \hat p \leq 80%)

  P( \hat p \leq 80%) = P( \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } } \leq \frac{0.80-0.90}{\sqrt{\frac{0.80(1-0.80)}{80} } } ) = P(Z \leq -2.24) = 1 - P(Z < 2.24)

                                                                  = 1 - 0.9875 = <u>0.0125</u>

The above probability is calculated by looking at the value of x = 2.24 in the z table which has an area of 0.9875.

8 0
2 years ago
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