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TEA [102]
1 year ago
6

Flying fish use their pectoral fins like airplane wings to glide through the air. Suppose a flying fish reaches a maximum height

of 5 ft after flying a horizontal distance of 33 ft. Write a quadratic function y=a(x-h)^2+k that models the flight path assuming the fish leaves the water at (0,0). Describe how the changing value of a,h, or k affects the flight path

Mathematics
2 answers:
GrogVix [38]1 year ago
7 0

The flight is in the shape of a parabola with a vertex 5 feet above the water and  1/2 * 33 = 16.5 feet horizontally from the point of leaving the water

y = a(x - h)^2 + k

where  (h,k)  is the vertex of the  parabola and here it is (5 , 16.5), so we have the function:-

y = a(x - 16.5)^2 + 5

when x = 0 y = 0  so

0 = a(-16.5)^2 + 5

which gives a = -0.018365

So our function for the flight path is

y = -0.018365(x - 16.5)^2 + 5     Answer



Vlad [161]1 year ago
3 0

Answer:

Equation: y= -0.00459*(x-33)^{2} + 5

Step-by-step explanation:

Using the value as height in axis y, and horizontal distance in axis x

y=a*(x-h)^{2}+k\\  h=33\\k=5\\y=a*(x-33)^{2}+5

X=0, Y=0

y=a*(x-33)^{2}+5\\ 0=a*(0-33)^{2}+5\\a=-\frac{5}{33^{2} } =-0.00459

In the figure can see the motion of the fish while flying like airplane

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High school students from track teams in the state participated in a training program to improve running times. Before the train
Nataly [62]

Answer:

b. The values X and Y are independent therefore, the mean is 34 seconds and the standard deviation is 50 seconds

Step-by-step explanation:

Subtraction between normal variables:

When two normal variables are subtracted, the mean is the difference of the means, while the standard deviation is the square root of the sum of the variances.

Before the training, the mean running time for the students to run a mile was 402 seconds with standard deviation 40 seconds.

This means that \mu_X = 402, \sigma_X = 40

After completing the program, the mean running time for the students to run a mile was 368 seconds with standard deviation 30 seconds.

This means that \mu_Y = 368, \sigma_Y = 30

Which of the following is true about the distribution of X-Y?

They are independent, so:

\mu = \mu_X - \mu_Y = 402 - 368 = 34

\sigma = \sqrt{\sigma_X^2+\sigma_Y^2} = \sqrt{40^2+30^2} = 50

This means that the correct answer is given by option b.

3 0
1 year ago
2 sandwiches and 3 croissants costs £11.
valentina_108 [34]

Answer:

The price of a sandwich is £2.5 and the price of a croissant is £2

Step-by-step explanation:

Let s be the number of sandwiches and c be the number of croissants

Then according to given statements the equations will be:

2s+3c = 11\ \ \ \ \ \ \ Eqn\ 1\\3s+6c =19.50\ \ \ Eqn\ 2

Multiplying equation 1 by 2 and subtracting equation 2 from the new equation

2(2s+3c) = 11*2\\4s+6c = 22

Now

4s+6c-(3s+6c) = 22-19.50\\4s+6c-3s-6c = 2.5\\s = 2.5

Putting s=2.5 in equation 1

2(2.5)+3c = 11\\5+3c = 11\\3c = 11-5\\3c = 6\\\frac{3c}{3} = \frac{6}{3}\\c = 2

Hence,

The price of a sandwich is £2.5 and the price of a croissant is £2

5 0
1 year ago
A square is constructed on side AD of quadrilateral ABCD such that FA lies on AB, as shown in the figure.
Elza [17]

Answer:  The co-ordinates of F are (4.4, -4.6) and the co-ordinates of D are (4.4, -1.4).

Step-by-step explanation:  Given that a square is constructed on side AD of quadrilateral ABCD such that FA lies on AB as shown in the figure. The co-ordinates of A are (6, -3) and the co-ordinates of B are (10, 1).

Also, AD : AB = 2 : 5 and the co-ordinates of the point E are (2.8, -3).

We are to select the correct co-ordinates of the points F and D.

Let, (a, b) are the co-ordinates of F and (c, d) are the co-ordinates of D.

Since ADEF is a square, so we have

AD = DE = EF = FA.

Given that

AD : AB = 2 : 5, so  FA : AB = 2 : 5.

That is, \left(\dfrac{c+4.4}{2},\dfrac{d-4.6}{2}\right)=\left(\dfrac{2.8+6}{2},\dfrac{-3-3}{2}\right)

We have, after applying the internal division formula that

\left(\dfrac{2\times 10+5\times a}{2+5},\dfrac{2\times 1+5\times b}{2+5}\right)=(6,-3)\\\\\\\Rightarrow \left(\dfrac{20+5a}{7},\dfrac{2+5b}{7}\right)=(6,-3)\\\\\\\Rightarrow \dfrac{20+5a}{7}=6,~~~~~\dfrac{2+5b}{7}=-3\\\\\\\Rightarrow 20+5a=42,~~~~\Rightarrow 2+5b=-21\\\\\\\Rightarrow 5a=22,~~~~~~~~~~\Rightarrow 5b=-23\\\\\\\Rightarrow a=4.4,~~~~~~~~~~~\Rightarrow b=-4.6.

So, the co-ordinates of F are (4.4, -4.6).

Now, since ADEF is a square, and the diagonals of a square bisect each other.

So, the mid-points of both the diagonals are same.

That is,

\textup{mid-point of DF}=\textup{mid-point of AE}\\\\\\\Rightarrow \left(\dfrac{c+4.4}{2},\dfrac{d-4.6}{2}\right)=\left(\dfrac{2.8+6}{2},\dfrac{-3-3}{2}\right)\\\\\\\Rightarrow \left(\dfrac{c+4.4}{2},\dfrac{d-4.6}{2}\right)=\left(\dfrac{8.8}{2},\dfrac{-6}{2}\right)\\\\\\\Rightarrow \dfrac{c+4.4}{2}=\dfrac{8.8}{2},~~~~~~\dfrac{d-4.6}{2}=-\dfrac{6}{2}\\\\\\\Rightarrow c+4.4=8.8,~~~~~\Rightarrow d-4.6=-6\\\\\Rightarrow c=4.4,~~~~~~~~~~~~\Rightarrow d=-1.4.

So, the co-ordinates of D are (4.4, -1.4).

Thus, the co-ordinates of F are (4.4, -4.6) and the co-ordinates of D are (4.4, -1.4).

7 0
2 years ago
Read 2 more answers
A function is expressed by the equation y=0.3x−6. For what value of the independent variable will the value of the function be e
Anna11 [10]

Answer:

0; 10; 20

Step-by-step explanation:

x is the independent variable

y is the dependent variable

y is dependent on x

a) For what value of the independent variable will the value of the function be equal to −6

y=0.3x−6

-6 = 0.3x-6

0=0.3x

x = 0

Therefore, if the independent variable is 0, the value of the function will be -6.

b) For what value of the independent variable will the value of the function be equal to −3

y=0.3x−6

-3 = 0.3x-6

0.3x = -3+6

0.3x = 3

x = 3/0.3

x = 10

Therefore, if the independent variable is 10, the value of the function will be -3.

c) For what value of the independent variable will the value of the function be equal to 0.

y=0.3x−6

0=0.3x-6

6 = 0.3x

x = 6/0.3

x = 20

Therefore, if the independent variable is 20, the value of the function will be 0.

7 0
1 year ago
Annabelle measures the sides of 15 right triangles and, based on her observations, she concludes that for any right triangle the
saul85 [17]

Answer: Annabelle is using  the a measure of central tendency defined as the Mode.

Step-by-step explanation: A measure of central tendency in its simplest definition is a single value or measure that can safely be used to represent all members belonging to an entire set of given data. Hence, as a good illustration, one figure can be used to confidently represent all other ninety nine figures where a set of one hundred figures were given.

The mean, median and mode are commonly accepted measures of central tendency.

The mode is the most frequently occurring value in a given set of data. As such, the modal value is statistically acceptable as a representative of the entire set of values or data.

If Annabelle measures the sides of 15 right triangles and based on her observations, she concludes that for any right  triangle the sum of the squares of the two legs is equal to the square of the hypotenuse, what she has done is taking the most frequently occurring value, and in her experiment, the most frequent of all observed data satisfies the Pythagorean Theorem.

That is why Annabelle can confidently make her assumption.

6 0
2 years ago
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