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TEA [102]
1 year ago
6

Flying fish use their pectoral fins like airplane wings to glide through the air. Suppose a flying fish reaches a maximum height

of 5 ft after flying a horizontal distance of 33 ft. Write a quadratic function y=a(x-h)^2+k that models the flight path assuming the fish leaves the water at (0,0). Describe how the changing value of a,h, or k affects the flight path

Mathematics
2 answers:
GrogVix [38]1 year ago
7 0

The flight is in the shape of a parabola with a vertex 5 feet above the water and  1/2 * 33 = 16.5 feet horizontally from the point of leaving the water

y = a(x - h)^2 + k

where  (h,k)  is the vertex of the  parabola and here it is (5 , 16.5), so we have the function:-

y = a(x - 16.5)^2 + 5

when x = 0 y = 0  so

0 = a(-16.5)^2 + 5

which gives a = -0.018365

So our function for the flight path is

y = -0.018365(x - 16.5)^2 + 5     Answer



Vlad [161]1 year ago
3 0

Answer:

Equation: y= -0.00459*(x-33)^{2} + 5

Step-by-step explanation:

Using the value as height in axis y, and horizontal distance in axis x

y=a*(x-h)^{2}+k\\  h=33\\k=5\\y=a*(x-33)^{2}+5

X=0, Y=0

y=a*(x-33)^{2}+5\\ 0=a*(0-33)^{2}+5\\a=-\frac{5}{33^{2} } =-0.00459

In the figure can see the motion of the fish while flying like airplane

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Answer:

t=\frac{669-634}{\frac{732}{\sqrt{1700}}}=1.971    

p_v =2*P(t_{(1699)}>1.971)=0.049  

If we compare the p value and the significance level given \alpha=0.1 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is different from 634 at 10% of signficance.

Step-by-step explanation:

Data given and notation  

\bar X=669 represent the sample mean

s=732 represent the sample standard deviation

n=1700 sample size  

\mu_o =68 represent the value that we want to test

\alpha=0. represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is different from 634, the system of hypothesis would be:  

Null hypothesis:\mu = 634  

Alternative hypothesis:\mu \neq 634  

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{669-634}{\frac{732}{\sqrt{1700}}}=1.971    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=1700-1=1699  

Since is a two sided test the p value would be:  

p_v =2*P(t_{(1699)}>1.971)=0.049  

Conclusion  

If we compare the p value and the significance level given \alpha=0.1 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is different from 634 at 10% of signficance.

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