Answer:
B. 5 and 1/4 percent
Step-by-step explanation:
Step one:
given
principal= $2460
time= 3 and 1/2 years= 3.5 years
SI= $452
Required
The rate
Step two:
we know that
SI= PRT/100
substituting our data we have
452= 2460*R*3.5/100
452=8610R/100
cross multiply
452*100= 8610R
divide both sides by 8610
45200/8610= R
R= 5.25%
R= 5 and 1/4 percent
<h2>
Answer:</h2>
Option: B is the correct answer.
The range of the function is:
B. 5 < y < ∞
<h2>
Step-by-step explanation:</h2>
Range of a function--
The range of a function is the set of all the values that is attained by the function.
By looking at the graph of the function we see that the function tends to 5 when x→ -∞ and the function tends to infinity when x →∞
Also, the function is a strictly increasing function.
This means that the function takes every real value between 5 and ∞ .
i.e. The range of the function is: (5,∞)
Hence, the answer is:
Option: B
The mileage from the Supermarket to the Library may be calculated using Pythagorean Theorem.
The coordinates of the Library are (7,10) and the coordinates of the Supermarket are (3,7).
So, the distance requested is √ [ (7-3)^2 + (10 - 7)^2 = √[ 4^2 + 3^2 = √ [16 + 9] =
= √25 = 5
So, he runs 5 miles.
And the reimbursement will be $0.50 / mile * 5 mile = $ 2.50.
Answer: option B) $ 2.50
Answer:
11.58%
Step-by-step explanation:
The initial volume if blood flowing through the artery is given by
To achieve a new volume of 155% (55% increase) of the initial volume, the new radius must be:
![V'= 1.55V\\1.55V=k(r')^4\\1.55kr^4 = k(r')^4\\(\sqrt[4]{1.55}*r)^4=(r')^4 \\(1.1158*r)^4=(r')^4 \\r'=1.1158*r](https://tex.z-dn.net/?f=V%27%3D%201.55V%5C%5C1.55V%3Dk%28r%27%29%5E4%5C%5C1.55kr%5E4%20%3D%20k%28r%27%29%5E4%5C%5C%28%5Csqrt%5B4%5D%7B1.55%7D%2Ar%29%5E4%3D%28r%27%29%5E4%20%5C%5C%281.1158%2Ar%29%5E4%3D%28r%27%29%5E4%20%5C%5Cr%27%3D1.1158%2Ar)
Since the new radius is 1.1158 times larger than the initial radius, the percentage increased is:
Answer:
75
Step-by-step explanation:
10 times 5 = 50
50 + 25 = 75
10 per hour
25 per party
