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2 years ago

What is the range of the function graphed below?

Mathematics

1 answer:

Xelga [282]2 years ago

8 0

<h2>Answer:</h2>

Option: B is the correct answer.

The range of the function is:

B. 5 < y < ∞

<h2>Step-by-step explanation:</h2>

Range of a function--

The range of a function is the set of all the values that is attained by the function.

By looking at the graph of the function we see that the function tends to 5 when x→ -∞ and the function tends to infinity when x →∞

Also, the function is a strictly increasing function.

This means that the function takes every real value between 5 and ∞ .

i.e. The range of the function is: (5,∞)

Hence, the answer is:

Option: B

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Answer:

Step-by-step explanation:

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2 years ago

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Answer:

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2 years ago

Read 2 more answers

Figure ABCD is transformed to obtain figure A'B'C'D': A coordinate grid is shown from negative 6 to 6 on both axes at increments

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Given:

Vertices of ABCD are A(-4,4), (-2,2), C(-2,-1) and D(-4,1).

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To find:

The sequence of transformations that changes figure ABCD to figure A'B'C'D'.

Solution:

Part A:

The figure ABCD reflected across the x-axis, then

$(x,y)\to (x,-y)$

Using this rule, we get

$A(-4,4)\to A_1(-4,-4)$

Similarly, the other points are $B_1(-2,-2),C_1(-2,1),D_1(-4,-1)$ .

Then figure translated 7 units right to get A'B'C'D'.

$(x,y)\to (x+7,y)$

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Similarly, the other points are $B'(5,-2), C'(5,1),D'(3,-1)$ .

Therefore, the figure ABCD reflected across the x-axis and then translated 7 units right to get A'B'C'D'.

Part B:

Reflection and translation are rigid transformation, it means shape and size of figures remains same after reflection and translation.

Therefore, the two figures congruent.

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2 years ago

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Korolek [52]

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where

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with $0\le u\le3$ and $0\le v\le2\pi$ .

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$\displaystyle\int_0^{2\pi}\cos^3v\,\mathrm dv=0$

$\displaystyle\int_0^{2\pi}\sin v\cos^3v\,\mathrm dv=0$

$\displaystyle\int_0^{2\pi}\sin^3v\,\mathrm dv=0$

$\displaystyle\int_0^{2\pi}\cos v\sin^3v\,\mathrm dv=0$

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2 years ago