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puteri [66]
2 years ago
9

In the diagram below, circle O is circumscribed about quadrilateral DEFG. What is the value of x?

Mathematics
2 answers:
Oxana [17]2 years ago
8 0

Answer:

61°

Step-by-step explanation:

earnstyle [38]2 years ago
5 0

Answer:

A. 61^{o}  

Step-by-step explanation:

We are told that circle O is circumscribed about quadrilateral DEFG.

Since we know that the opposite angles of quadrilateral inscribed inside a circle are supplementary.

Let us find value of x by equating the measure of x and its opposite angle with 180.

x+119^{o}=180^{o}

x=180^{o}-119^{o}

x=61^{o}

Therefore, the value of x is 61 degrees and option A is the correct choice.

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the average number of spectators at a football competition for the first five days was 3144.the attendance on the sixth day was
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2 years ago
When Ryan is serving at a restaurant, there is a 0.75 probability that each party will order drinks with their meal. During one
Triss [41]

Answer:

0.82 = 82% probability that at least one party will not order drinks

Step-by-step explanation:

For each party, there are only two possible outcomes. Either they will order drinks with their meal, or they will not. The probability of a party ordering drinks with their meal is independent of other parties. So the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

When Ryan is serving at a restaurant, there is a 0.75 probability that each party will order drinks with their meal.

This means that p = 0.75

During one hour, Ryan served 6 parties. Assuming that each party is equally likely to order drinks, what is the probability that at least one party will not order drinks?

6 parties, so n = 6.

Either all parties will order drinks, or at least one will not. The sum of the probabilities of these events is decimal 1. So

P(X = 6) + P(X < 6) = 1

We want P(X < 6). So

P(X < 6) = 1 - P(X = 6)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 6) = C_{6,6}.(0.75)^{6}.(0.25)^{0} = 0.18

P(X < 6) = 1 - P(X = 6) = 1 - 0.18 = 0.82

0.82 = 82% probability that at least one party will not order drinks

5 0
2 years ago
Read 2 more answers
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