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lukranit [14]
2 years ago
12

Caswell started studying how the number of branches on his tree grows over time. The relationship between the elapsed time ttt,

in years, since Caswell started studying the tree, and the number of its branches, N(t)N(t)N, left parenthesis, t, right parenthesis, is modeled by the following function: N(t)=15⋅(1.64)t3.4 Complete the following sentence about the rate of change in the number of branches.
Mathematics
2 answers:
ipn [44]2 years ago
8 0

Answer:

t =log(20) / 0.3 = 10*log(20) / log(1,000) - years - when the tree will have 100 branches.

Step-by-step explanation:

100 = 5 * 10^(0.3t), solve for t

Divide both sides by 5:

20 =10^(0.3t)

Take the log of both sides:

0.3t =log(20)

Divide both sides by 0.3:

Multiply the RHS by 10 / 10

t =log(20) / 0.3 = 10*log(20) / log(1,000) - years - when the tree will have 100 branches.

Sidana [21]2 years ago
4 0

Answer:

Step-by-step explanation:

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Jose and Maris work for different car dealerships. Jose earns a monthly salary of $3,500 plus a 6% commision on his sales, x. Ma
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Answer:

x>$25000

Step-by-step explanation:

4 0
2 years ago
Evaluate \dfrac14c+3d
Crank

Answer:  \frac{45}{2}

Step-by-step explanation:

<h3> The exercise is: " Evaluate \frac{1}{4}c + 3d when c = 6 and   d = 7</h3>

Given the following expression:

 \frac{1}{4}c + 3d

You can follow these steps in order to evaluate it:

 1. Substitute c = 6 and   d = 7 into the expression provided in the exercise:

  \frac{1}{4}(6) + 3(7)

2. Solve the multiplications. Remember that:

 \frac{a}{b}*\frac{c}{d}=\frac{ac}{bd}

Then:

 =\frac{6}{4} +21

3. Reduce the fraction. Notice that the numerator 6 and the denomiantor 4 can be both divided by 2. Then:

=\frac{3}{2} +21

4. Solve the addition:

=\frac{3}{2} +\frac{21}{1}

 Since the number 21 has a denominator 1, the Least Common Denominator is:

LCD=2

Then, the sum is:

=\frac{3+42}{2}=\frac{45}{2}

5 0
2 years ago
Read 2 more answers
Four pounds of bananas cost $1.96. how much does it cost per pound?
adelina 88 [10]
4 pounds = $1.96
1.96 / 4 = $0.49 
4 0
2 years ago
A sample statistic , such as x bar, that estimates the value of the corresponding population parameter is known as
Orlov [11]
A sample statistic , such as x bar, that estimates the value of the corresponding population parameter is known as a control chart.
6 0
2 years ago
After a number of complaints about its tech assistance, a computer manufacturer examined samples of calls to determine the frequ
icang [17]

Answer:

a) Upper Control Limit = 0.10

   Lower Control Limit = 0.01

b) The tech assistance process is stable and in control.

Step-by-step explanation:

Given - After a number of complaints about its tech assistance, a

            computer manufacturer examined samples of calls to determine

            the frequency of wrong advice given to callers. Each sample

            consisted of 100 calls.

SAMPLE             1   2   3   4   5   6   7   8   9  10 11 12 13 14 15 16

Number of errors 5  3   5   7   4   6   8   4   5    9   3   4   5   6   6   7

To find - a. Determine 95 percent limits.

              b. Is the tech assistance process stable (i.e., in control)

Proof -

z = 95% confidence interval

  = 1.96

⇒z = 1.96

Proportion of defects,P = total defectives/total observations

                                     = 0.0544

⇒P = 0.0544

Now,

Q = 1-P

   = 0.9456

⇒Q = 0.9456

Now,

Average sample size, N = 100

Standard deviation = \sqrt{\frac{P.Q}{N} }

                             = 0.0227

Now,

Upper Control Limit = P + z(Standard deviation)

        = 0.0988

⇒Upper Control Limit = 0.0988 ≈ 0.10

And

Lower Control Limit = P - z(Standard deviation )

       = 0.0099

⇒Lower Control Limit = 0.0099 ≈ 0.01

∴ we get

Upper Control Limit = 0.10

Lower Control Limit = 0.01

b.)

Now,

it is clear that the fraction defective values are wit in upper an lower control limits.

So, The tech assistance process is stable and in control.

5 0
2 years ago
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