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erastovalidia [21]

2 years ago

10

Use the Financial database from "Excel Databases.xls" on Blackboard. Use Total Revenues, Total Assets, Return on Equity, Earning

s Per Share, Average Yield, and Dividends Per Share to predict the average P/E ratio for a company. Use Excel to perform a forward selection regression analysis. Assume a 5% level of significance. Based on your final model, what is the p-value from the test of the overall model? Write your answer as a number and round to 3 decimal places.

1 answer:

skad [1K]2 years ago

4 0

Answer:

Check the explanation

Step-by-step explanation:

Variable Name R2 squared value Adj R2 value

Earning Per Share 0.086535 0.077214

Earning Per Share,

Dividends per Share 0.103976 0.085501

Earning Per Share,

Dividends per Share,

Average Yield 0.180303 0.154687

Earning Per Share,

Dividends per Share,

Average Yield,

Return on Equity 0.183215 0.148824

Earning Per Share,

Dividends per Share,

Average Yield,

Return on Equity,

Total Assests 0.184669 0.141301

Earning Per Share,

Dividends per Share,

Average Yield,

Return on Equity,

Total Assets,

Total Revenues 0.187297 0.134865

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Whitney rolls a ball down a ramp that is 18 feet long if the ball rolls down 2 feet each second what integer represents the amou

Afina-wow [57]

Integer generally means number.

if s = seconds then

2s = 18

solve for s,

18/2 = 7

s = 7 seconds

8 0

2 years ago

Read 2 more answers

The point-slope form of the equation of a line that passes through points (8, 4) and (0, 2) is y – 4 = y minus 4 equals StartFra

Stels [109]

Answer:

Third option: $y= \frac{1}{4}x+2$

Step-by-step explanation:

<h3><em> The correct form of the exercise is: "The point-slope form of the equation of a line that passes through points (8, 4) and (0, 2) is $y -4 = \frac{1}{4}(x -8)$ . What is the slope-intercept form of the equation for this line?"</em></h3><h3><em /></h3>

<em> </em>The equation of the line in Slope-Intercept form is:

$y=mx+b$

Where "m" is the slope and "b" is the y-intercept.

Given the equation of the line in Point-Slope form:

$y -4 = \frac{1}{4}(x -8)$

You need to solve for "y" in order to write the given equation of the line in Slope Intercept form.

Then, this is:

$y -4 = \frac{1}{4}(x -8)\\\\y-4= \frac{1}{4}x-\frac{8}{4}\\\\y-4= \frac{1}{4}x-2\\\\y= \frac{1}{4}x-2+4\\\\y= \frac{1}{4}x+2$

You can identify that the slope "m" is:

$m=\frac{1}{4}$

And the y-interecept "b" is:

$b=2$

7 0

2 years ago

Read 2 more answers

What is the value of b in the equation (y Superscript b Baseline) Superscript 4 Baseline = StartFraction 1 Over y Superscript 24

shusha [124]

The value of b is -6.

Explanation:

The expression is $\left(y^{b}\right)^{4}=\frac{1}{y^{24}}$

To determine the value of b, we shall solve the expression.

Applying exponent rule, $\left(a^{b}\right)^{c}=a^{b c}$ , we get,

$y^{4b}=\frac{1}{y^{24}}$

Applying exponent rule, $\frac{1}{a^{b}}=a^{-b}$ , we have,

$y^{4b}=y^{-24}$

The expression is of the form, $a^{f(x)}=a^{g(x)}$ then $f(x)=g(x)$

Applying this rule, we get,

$4b=-24$

Dividing both sides by 4, we have,

$b=-6$

Hence, the value of b is -6.

4 0

2 years ago

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By what percentage did the median earnings of college degreed exceed that of high school degreed for 1973 for men (to the neares

kap26 [50]

Remark

I'm going to state what I think the question is saying. I'm having a little trouble figuring it out.

1. Both groups are from 1967.

2. Both groups are women?

It's actually clear, but I had to restate it to get it clear for me.

Solution

<em><u>Givens</u></em>

College: Women= 4400

H.School: Women = 3300

Solve

The base number is the high school women.

The difference is 4400 - 3300 = 1100

So the % = (1100/3300) * 100% = 33.3%

1973

I did this in the wrong order, but it will still give you the right answer.

The base number is again high school: 5600

Difference: 6600 - 5600 = 1000

% = (1000/5600) * 100% = 17.9

Comment

What this means is that if you take the % difference and multiply it by the smaller number you get the actual difference between the 2 groups. Put another way, for the 1973 group, the college women made 17.9 % more than the high school group. As an aside, there are lots of reasons for this and I'm not certain it is any longer true.

4 0

2 years ago

A car dealer recommends that transmissions be serviced at 30,000 miles. To see whether her customers are adhering to this recomm

salantis [7]

Answer:

No, the owners are not having their transmissions serviced at 30,000 miles.

Step-by-step explanation:

We are given that a car dealer recommends that transmissions be serviced at 30,000 miles.

The car dealer selects a random sample of 40 customers and finds that the average mileage of the automobiles serviced is 30,456. The standard deviation of the population is 1684 miles.

Let $\mu$ = <em>true average mileage of the automobiles serviced</em>.

So, Null Hypothesis, $H_0$ : $\mu$ = 30,000 miles {means that the owners are having their transmissions serviced at 30,000 miles}

Alternate Hypothesis, $H_A$ : $\mu\neq$ 30,000 miles {means that the owners are having their transmissions serviced at different than 30,000 miles}

The test statistics that will be used here is <u>One-sample z-test statistics</u> because we know about population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample average mileage serviced = 30,456 miles

$\sigma$ = population standard deviation = 1684 miles

n = sample of customers = 40

So, <u><em>the test statistics</em></u> = $\frac{30,456-30,000}{\frac{1684}{\sqrt{40} } }$

= 1.71

The value of z-statistics is 1.71.

<u>Also, the P-value of the test statistics is given by;</u>

P-value = P(Z > 1.71) = 1 - P(Z $\leq$ 1.71)

= 1 - 0.9564 = 0.0436

For the two-tailed test, the P-value is calculated as = 2 $\times$ 0.0436 = <u>0.0872</u>.

Since the P-value of our test statistics is less than the level of significance as 0.0872 < 0.10, so <u><em>we have sufficient evidence to reject our null hypothesis</em></u> as the test statistics will fall in the rejection region.

Therefore, we conclude that the owners are having their transmissions serviced at different than 30,000 miles.

4 0

2 years ago