Answer:
-73, -34, 0.5, 1.2, 23
Step-by-step explanation:
In Mathematics, the set of numbers are arranged in two ways. It means that the numbers can be arranged either in ascending order or descending order. If the numbers are arranged from the least to the greatest, then it is called ascending order. In this form, the numbers are in increasing order. The first number should be lesser than the second number.
If the numbers are arranged from the greatest to the least, then it is called descending order. In this form, the numbers are in decreasing form. The first number should be greater than the second number.
Also, read: Descending Order
Standard Form
<em>The standard form to represent the least to the greatest arrangement </em>of numbers is given by:
a < b < c < d < …..
Here,
a, b, c, d represent the numbers
Example: 2 < 5 < 7 < 8
Given inequality: 2y−x ≤ −6
Option-1 : (-3,0)
2×0 - (-3) = 0 + 3 = 3 > -6
Not satisfied
Option-2 : (6,1)
2×1 - 6 = 2 - 6 = -4 > -6
Not satisfied
Option-3 : (1, -4)
2×(-4) - 1 = -8 - 1 = -9 < -6
Satisfied.
Thus, (1, -4) is a solution.
Option-4 : (0, -3)
2×(-3) - 0 = -6 - 0 = -6 = -6
Satisfied.
Thus, (0, -3) is a solution.
Option-5 : (2, -2)
2×(-2) - 2 = -4 - 2 = -6 = -6
Satisfied.
Thus, (2, -2) is a solution.
Solutions are: (1, -4), (0, -3) , (2, -2)
Answer:
a) P(μ-k*σ≤ Y ≤ μ+k*σ ) ≥ 0.90
a= μ-3.16*σ , b= μ+3.16*σ
b) P(Y≥ μ+3*σ ) ≥ 0.90
b= μ+3*σ
Step-by-step explanation:
from Chebyshev's inequality for Y
P(| Y - μ|≤ k*σ ) ≥ 1-1/k²
where
Y = the number of fish that need be caught to obtain at least one of each type
μ = expected value of Y
σ = standard deviation of Y
P(| Y - μ|≤ k*σ ) = probability that Y is within k standard deviations from the mean
k= parameter
thus for
P(| Y - μ|≤ k*σ ) ≥ 1-1/k²
P{a≤Y≤b} ≥ 0.90 → 1-1/k² = 0.90 → k = 3.16
then
P(μ-k*σ≤ Y ≤ μ+k*σ ) ≥ 0.90
using one-sided Chebyshev inequality (Cantelli's inequality)
P(Y- μ≥ λ) ≥ 1- σ²/(σ²+λ²)
P{Y≥b} ≥ 0.90 → 1- σ²/(σ²+λ²)= 1- 1/(1+(λ/σ)²)=0.90 → 3= λ/σ → λ= 3*σ
then for
P(Y≥ μ+3*σ ) ≥ 0.90
Answer:
Step-by-step explanation:
$27.63 / 2 = $13.82
$13.82 * 0.20 = $2.76
$13.82 + $2.76 = $16.58
Answer:
Step-by-step explanation:
Given that a group of students estimated the length of one minute without reference to a watch or clock, and the times (seconds) are listed below.
Data set is as ollows:
70 79 38 63 44 23 62 61 67 50 61 70 94 87 65

H0: mu = 60 sec
Ha: mu not equals 60 sec
Mean diff = 2.27

Test statistic = 2.27/SE =0.4815
p value =0.6376
Since p>0.05, we accept null hypothesis
i.e. there is statistical evidence to say that students are reasonably good at estimating one minute