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Butoxors [25]
2 years ago
15

Marni and Mikela are playing a color-guessing game. Each player chooses two colors from a list of red (R), blue (B), green (G),

purple (P), and yellow (Y). A player then has three chances to correctly guess both the colors that the other player chose. The simulation of Marni’s guesses about Mikela’s colors are shown in the table. If Mickela’s colors are red and green, what is the experimental probability that Marni’s guesses are correct? Write the answer as a fraction in simplest form.
trials
1 PRB 2 YBG 3 GPR 4 RYP 5 RYG 6 GYB 7 RGP 8 GPR 9 RPG 10 BGP
Mathematics
2 answers:
Sladkaya [172]2 years ago
7 0

The answer should be 1/2.

Reptile [31]2 years ago
4 0

Answer:

The answer is 1/2!

Step-by-step explanation:

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The number of tickets purchased by an individual for Beckham College's holiday music festival is a uniformly distributed random
egoroff_w [7]

Answer:

The mean is 4.5 and the standard deviation is 1.44.

Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The mean of the uniform probability distribution is:

M = \frac{(a + b)}{2}

The standard deviation of the uniform probability distribution is:

S = \sqrt{\frac{(b-a)^{2}}{12}}

Uniformly distributed random variable ranging from 2 to 7.

This means that a = 2, b = 7.

So

M = \frac{(2 + 7)}{2} = 4.5

S = \sqrt{\frac{(b-a)^{2}}{12}} = \sqrt{\frac{(7 - 2)^{2}}{12}} = 1.44

The mean is 4.5 and the standard deviation is 1.44.

7 0
1 year ago
Question 1(Multiple Choice Worth 1 points)
kirza4 [7]

Answer:


Step-by-step explanation:


1. 8 days

2. C?

3. A

4. B

5. C

6.D

7.48

8. A

9. 1.69%

10. False


I have no clue if these are right i tried my best to get them right, if they are wrong I am incredibly sorry!

- SavageSavvy

5 0
1 year ago
To evaluate the effect of a treatment, a sample of n=8 is obtained from a population with a mean of μ=40 , and the treatment is
Westkost [7]

Answer:

Step-by-step explanation:

a)

Test statistic:

t=\frac{35-40}{\sqrt{\frac{32}{8} } }

t=-2.5

df=8-1=7

critical, t ,values=+/-2.365

here test statistic lie in rejection region,that why null hypothesis fails  

so Yes, its significant.

b)

Test statistic:

t=\frac{35-40}{\sqrt{\frac{72}{8} } }

t=-1.67

df=8-1=7

critical, t ,values=+/-2.365

c)

sample variability increases, therefore likelihood of rejecting the null hypothesis decreases.

5 0
1 year ago
Gina wants to save money for a holiday to bali at the end of the year. she estimates that if would cost her $2200 but she only h
inessss [21]
That's a funky problem... :/  I mean it would depend on how much she earns weekly. If she were working 40 hours each week and earning 10$ an hour then yes, she would have enough. Even is she were per say a student on a part time working 30 hours and earning 8$ per hour, she would still have enough.
6 0
1 year ago
Sue played four games of golf.
alisha [4.7K]

Answer:

Sue's scores for the four games in ascending order are: 97, 98, 98, 107

Step-by-step explanation:

Her modal score was 98.  The mode is found by using the number that appears most often.  This means that 98 has to appear at least two times out of the four scores.

Her range was 10.  The range is found by taking the highest score and subtracting it from the lowest score.  The highest score had to be greater than 98 and the lowest score had to be less than 98 since we know the mode was 98.

Her mean score was 100.  This mean is found by adding all the numbers together and then dividing by the total numbers listed.  Adding the four scores together and dividing by 4 will equal 100.

Used guess and test:

Highest Number, 98, 98, Lowest Number

107 - 97 = 10 (meets range requirement)

97 + 98 + 98 + 107 = 400

400/4 = 100 (meets the mean requirement)

7 0
1 year ago
Read 2 more answers
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