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Karolina [17]
2 years ago
10

We flip a fair coin five times. For every heads you pay me $1 and for every tails I pay you $1. Let X denote the my net winning

at the end of the flips. Find the possible values and the probability mass function of X.
Mathematics
1 answer:
TEA [102]2 years ago
8 0

Answer:

The probability mass of X is 0.03

Step-by-step explanation:

If we set the winning requirement of your heads and my tails then the occurring possibility of both is 1/2 or 0.5.

Hence let us make a graph and use the figures to calculate the all the probabilities of you getting a heads.

Where X represents the number of dollars won during the flip of the coin, probability of heads represent the chances of occurrence of the value and of winning the dollars.

The probability of winning start to drop as the winning amount increases.

       

     X                          0     1               2     3       4      5

Probability of Heads  0 0.50 0.25 0.13    0.06 0.03

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The dye dilution method is used to measure cardiac output with 3 mg of dye. The dye concentrations, in mg/L, are modeled by c(t)
Lemur [1.5K]

Answer:

Cardiac output:F=0.055 L\s

Step-by-step explanation:

Given : The dye dilution method is used to measure cardiac output with 3 mg of dye.

To Find : Find the cardiac output.

Solution:

Formula of cardiac output:F=\frac{A}{\int\limits^T_0 {c(t)} \, dt} ---1

A = 3 mg

\int\limits^T_0 {c(t)} \, dt =\int\limits^{10}_0 {20te^{-0.06t}} \, dt

Do, integration by parts

[\int{20te^{-0.6t}} \, dt]^{10}_0=[20t\int{e^{-0.6t} \,dt}-\int[\frac{d[20t]}{dt}\int {e^{-0.6t} \, dt]dt]^{10}_0

[\int{20te^{-0.6t}} \, dt]^{10}_0=[\frac{-20te^{-0.6t}}{0.6}+\frac{20}{0.6}\int {e^{-0.6t} \,dt]^{10}_0

[\int{20te^{-0.6t}} \, dt]^{10}_0=[\frac{-20te^{-0.6t}}{0.6}+\frac{20e^{-0.6t}}{(0.6)^2}]^{10}_{0}

[\int{20te^{-0.6t}} \, dt]^{10}_0=[\frac{-200e^{-6}}{0.6}+\frac{20e^{-6}}{(0.6)^2}]+\frac{20}{(0.60^2}

[\int{20te^{-0.6t}} \, dt]^{10}_0=\frac{20(1-e^{-6}}{(0.6)^2}-\frac{200e^{-6}}{0.6}

[\int{20te^{-0.6t}} \, dt]^{10}_0\sim {54.49}

Substitute the value in 1

Cardiac output:F=\frac{3}{54.49}

Cardiac output:F=0.055 L\s

Hence Cardiac output:F=0.055 L\s

4 0
2 years ago
The price per night for a hotel room is different at three different hotels.
Damm [24]
I think you meant it to be not repeating 3 times so
You do 192/3 is 60*3= 180 leaving you with 12 which is 4*3. So 64 is A
Then it’s 300/5 which is 60
455/7. So first see, if I multiply 7 by 60 is it over or under. If it’s over then B is the least and if it is less then C is the least. So 7 *60 is 420
C Being greater, b costs least per night
4 0
2 years ago
Clarissa helps her mom put the 200-Newton lawn mower in the back of her mom’s truck. They lift the mower up from the ground to t
Mice21 [21]

Answer:

220 N * m or 220 J

Step-by-step explanation:

We have that the work formula would be the applied force multiplied by the distance traveled, that is:

W = F * d

In this case the F is 200 N and the distance is 1.1 meters, therefore we replace:

W = 200 * 1.1

W = 220 N * m = 220 J

Therefore the work carried out by Clarissa and her mom is 200 joules.

6 0
2 years ago
(b) we often read that iq scores for large populations are centered at 100. what percent of these 78 students have scores above
ss7ja [257]
As IQ scores for extensive populaces are focused at 100, the mean = 100. 
There ought to be around half scores above or underneath the mean score since mean and middle is about a similar when the populace is substantial. 
P(x > 100) = P( z> (100 - 100)/sd ) = P(z > 0)= 0.5 
The number of the student who has scored over 100 = 0.5 x 78 = 39 Therefore the answer is 39 students. 
4 0
2 years ago
Edmund fills his gas tank on Monday morning an then drives ten miles total for work each day of the work week. With a full tank
timama [110]

Answer:

50 miles.

Step-by-step explanation:

Edmund fills his gas tank on Monday morning an then drives ten miles total for work each day of the work week.

With a full tank of gas he can drive 100 miles.

Question asked:

How many miles can he drive on the weekend, before he he fills up again?

Solution:

With full tank he can drive a total distance = 100 miles

Each day of the work week, he drives = 10 miles

Total miles, he drive in whole work week (Monday - Friday) = 10\times5=50\ miles

<em>Now, to find that many miles he can drive on the weekend (Saturday and Sunday), we will subtract total miles, he drive in whole work week from the total distance, he can drive with full tank of gas:-</em>

100 - 50 = 50 miles.

Therefore, he can drive 50 miles on the weekend, before he he fills up again.

4 0
2 years ago
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