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Karolina [17]
2 years ago
10

We flip a fair coin five times. For every heads you pay me $1 and for every tails I pay you $1. Let X denote the my net winning

at the end of the flips. Find the possible values and the probability mass function of X.
Mathematics
1 answer:
TEA [102]2 years ago
8 0

Answer:

The probability mass of X is 0.03

Step-by-step explanation:

If we set the winning requirement of your heads and my tails then the occurring possibility of both is 1/2 or 0.5.

Hence let us make a graph and use the figures to calculate the all the probabilities of you getting a heads.

Where X represents the number of dollars won during the flip of the coin, probability of heads represent the chances of occurrence of the value and of winning the dollars.

The probability of winning start to drop as the winning amount increases.

       

     X                          0     1               2     3       4      5

Probability of Heads  0 0.50 0.25 0.13    0.06 0.03

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Roots can also be represented as indicies (exponents) and thus should be treated like them. For example, square root could also be written as exponent 1/2.

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2 years ago
James is the manager at an entertainment arena that draws an average 7,000 patrons per event. Each ticket taker can process 350
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Answer:

No. James didn't have enough ticket takers to process the average number of patrons hat usually attend the events.

He need to hire 2 more ticket taker (i.e 20 ticket takers) in order to process the average number of patrons hat usually attend the events.

Step-by-step explanation:

Given:

Average amount of patron per event= 7000

Each ticket taker can process = 350

Number of ticket takers hired = 18

We need to find the whether he hire enough to process the average number of patrons that usually attend the events.

Solution:

We will find the Average amount of patron ticket takers can process.

Now we can say that

Average amount of patron ticket takers can process is equal to Each ticket taker can process multiplied by Number of ticket takers hired.

framing in equation form we get;

Average amount of patron ticket takers can process = 350 \times 18 = 6300\ patrons

Hence With the required hires James cannot fully process the patrons usually attending the event.

To find how many ticket takers required we will divide average number of patrons with  Each ticket taker can process.

framing in equation form we get;

ticket takers required = \frac{7000}{350}=20

hence In order t process the the average number of patrons that usually attend the events James will require 20 ticket takers.

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<em>Hope it helps <3</em>

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