Answer: a.) 40320
b.) 336
Step-by-step explanation:
since we have 8 possible positions, with 8 different candidates, then there are 8 possible ways of arranging the first position, 7 possible ways of arranging the Second position, 6 ways of arranging the 3rd position, 5 possible ways od arranging the 4th position, 4 possible ways of arranging the 5th position, 3 possible ways of arranging the 6th position, 2 possible ways of arranging the 7th position and just one way of arranging the 8th position since we have only one person left.
Hence, the Number of possible sample space for different 8 positions is by multiplying all the number of ways we have in our sample space which becomes:
8*7*6*5*4*3*2*1 = 40320.
b.) By the sample space we have, since we've been asked ti arrange for only the firat 3 positions, then we multiply just for the first 3ways of choosing the positions, this becomes:
8*7*6 = 336
2 inches wide
that means that the height of the large carton is 2 inches
find the volume of the carton
V=108 times volume of small box
V=108 times 1 times 2 time s3
V=648 in^2
height is 2
V=LWH
648=LW2 (note, this is not LW^2 but 2 times LW)
divie both sides by 2
324=LW
legnth of base is less than 36
div
we just need to find the values of legnth and width such that LW=324 and L<36 and that L or W is divisible by 3 (since each box is 3 inches long)
so lets factor 324
324=2*2*3*3*3*3
group them and find possible values for legnth and width less than 36 and divsible by 3
possible values
(L,W,H) possible values are
(27,12,2)
(18,18,2)
the possible dimentions are
27 by 12 by 2 or
18 by 18 by 2
Average acceleration: ( v - v o ) / Δ t
v = 0 m/s, v o = 20 m/s, Δ t = 3.5 s
a (average) = ( 0 m/s - 20 m/s )/3.5 s = - 20 m/s / 3.5 s =
= - 5.7142857 m/s² ≈ - 5.71 m/s²
1:4
when sugar=34
times 34 both sides
34*4=136
1:4=34:136
should use 136 cups of water
that is alot of water
that's a big feeder (8.5 gallons. the water alone weighs about 74.8lb)
should use 136 cups (wow)
Answer:
Step-by-step explanation:
Given is the probability distribution of a random variable X
X 4 5 6 7 Total
P 0.2 0.4 0.3 0.1 1
x*p 0.8 2 1.8 0.7 5.3
x^2*p 3.2 10 10.8 4.9 28.9
a) E(X) = Mean of X = sum of xp = 5.3

Std dev = square root of variance = 0.9
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b) For sample mean we have
Mean = 5.3
Variance = var(x)/n = 
c) 