Answer:
Volume of the right pyramid = 288 m²
Step-by-step explanation:
Volume of the pyramid = 
From the ΔAOB,
By Pythagoras theorem,
AB² = AO² + OB²
(6√2)² = AO² + (6)²
72 = AO² + 36
AO = √(36) = 6 m
Since base of the pyramid is a square so area of the base = (Length × Width) = (side)²
Now volume of the pyramid = ![\frac{1}{3}[(Length)(width)]\times height](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B3%7D%5B%28Length%29%28width%29%5D%5Ctimes%20height)
= 
= 288 m²
Therefore, volume of the right pyramid is 288 m².

For these lines, let

.

And for these, let

.
Now,

The vertices of

in the x-y plane are (0, 2), (2/3, 10/3), (2, 2), and (4/3, 2/3). Applying

to each of these yields, respectively, (2, 2), (2, 4), (-2, 4), and (-2, 2), which are the vertices of a rectangle whose sides are parallel to the u-v plane.