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RUDIKE [14]
1 year ago
6

You are planning to take a group of friends to the movies for your birthday. The local movie theater charges $12.99 per person.

When you check the company's website, you find that they also offer a special group rate. The group rate is only $8.99 per person but also includes a $20 reservation fee in addition to the cost per person. What is the maximum number of people that could attend your party in order for the individual admission rate to be a better deal?
Mathematics
2 answers:
aleksley [76]1 year ago
7 0
13 times 4 is 52
9 times 4 is 36 plus the 20 it takes for reservation
So the maximum amount would be 4
NNADVOKAT [17]1 year ago
3 0

Answer:

Answer is C 6 people

Step-by-step explanation:

I just took the USATEST prep quiz

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what is the distance around a triangle that has sides measuring 2 1/8 feet, 3 1/2 feet, and 2 1/2 feet?
Vlad1618 [11]
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Clive surveyed a random sample of underclassmen and seniors in his school about which change they would most like to see in this
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12 seniors of 25 total seniors voted for candid pictures, so it would be

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Margaret took a trip to Italy. She had to convert US dollars to euros to pay for her expenses there. At the time she was traveli
creativ13 [48]
The conversion rate US dollars to Euros is represented with the function:
E(n)=0.72n
n- number of dollars
E(n) - Euros as a function of US dollars

The conversion rate Euros to Dirhams is :
D(x)=5.10x
x- number of Euros
D(x)- Dirhams as a function of Euros

<span>We are trying to find D(x) in terms of n.
D(x) = 5.10x
x can be rewritten as E(n)
D(x) = 5.10(E(n))
D(x) = 5.10(E(n))
D(x) = 5.10(0.72n)
D(x) = 3.672n </span>

According to this the following statement is true:
A) <span>(D x E)(n) = 5.10(0.72n)</span>
8 0
2 years ago
A company produces precision 1 meter (1000 mm) rulers. the actual distribution of lengths of the rulers produced by this company
pogonyaev

Let X be the length of rulers. X follows Normal distribution with mean μ and standard deviation σ = 0.02. A sample of size n=4 is drawn from population and sample mean m=1000. We have to find 90% confidence interval for population mean μ.

Here population standard deviation is given to us so we will use z confidence interval for mean. It is given as

(Sample mean - Margin of error , Sample mean + Margin of error)

Where margin of error for z confidence interval is

ME = σ \frac{z_{\alpha/2}}{\sqrt{n}}

Where σ = population standard deviation = 0.02

n= sample size =4

z_{\alpha/2} = Critical z score value for given confidence level

We have to find here 90% confidence interval so confidence level c= 0.9

α = 1 -c =1-0.9 = 0.1

z_{\alpha/2} = z_{0.1/2} = z_{0.05}

Here we have to find z score value such that area below it is -z is 0.05 and above z is 0.05

Using excel function to find z score value

=NORM.S.INV(0.05) = -1.645

For calculating confidence interval we consider positive z score value which is 1.645

So the margin of error is

ME = \frac{0.02 * 1.645}{\sqrt{4}}

ME = 0.01645

90% confidence interval for mean is

(Sample mean - ME, Sample mean+ME)

1000- 0.01645, 1000+0.01645

(1000.01645, 999.9836)

Rounding interval upto 3 decimal places

(1000.016, 999.984)

90% confidence interval for population mean is (1000.016, 999.984)

7 0
1 year ago
Consider a limousine that gets m(v)= (120 - 2v) / 5 miles per gallon at speed v , whose chauffeur is paid $15/hour, and gas cost
DENIUS [597]

Answer:

(17.5 / 120 - 2v) + (15 / v)

Step-by-step explanation:

Given : m(v)= (120 - 2v) / 5 miles per gallon at speed v ,

chauffeur is paid $15/hour

gas cost = $3.5/gallon.

Gasoline cost per mile :

Cost per gallon = $3.5

Cost per gallon * 1/(m(v))

$3.5 * 1 / (120 - 2v) / 5

$3.5 * 5 / 120 - 2 v

= 17.5 / 120 - 2v

Time = distance / speed

Chauffeur cost = 15 per hour / v

Hence ;

Total cost :

Cost of gasoline + Cost of chauffeur

(17.5 / 120 - 2v) + (15 / v)

8 0
1 year ago
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