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Contact [7]
2 years ago
10

You want to order a pizza that costs $12.99 with no toppings. Each topping you choose costs $0.75. Which of these equations best

shows the pricing of the pizza?
Mathematics
2 answers:
Zielflug [23.3K]2 years ago
7 0
Pizza flat price is 12.99
each topping is 0.75

cost=pizza+toppings
toppings=number of topings (n) times cost per toping (0.75)
toppings=0.75n
so

cost=12.99+0.75n or
cost=0.75n+12.99
NNADVOKAT [17]2 years ago
3 0

Answer:

Pizza Price = 0.75 • Toppings + 12.99

Step-by-step explanation: i got this correct

You might be interested in
he temperature measured in Kelvin (K) is the temperature measured in Celsius (C) increased by 273.15. This can be modeled by the
PIT_PIT [208]
We have that
<span>K = C + 273.15
solve for C
subtract 273.15 both sides
K-273.15=C
C=K-273.15

the answer is
</span>C=K-273.15<span>


</span>
5 0
2 years ago
Read 2 more answers
Suppose that public opinion in a large city is 55% in favor of increasing taxes to support renewable energy and 45% against such
Harman [31]

Answer:

The approximate probability that more than 360 of these people will be against increasing taxes is P(Z> <u>0.6-0.45)</u>

                                              √0.45*0.55/600

The right answer is B.

Step-by-step explanation:

According to the given data we have the following:

sample size, h=600

probability against increase tax p=0.45

The probability that in a sample of 600 people, more that 360 people will be against increasing taxes.

We find that P(P>360/600)=P(P>0.6)

The sample proposition of p is approximately normally distributed mith mean p=0.45

standard deviation σ=√P(1-P)/n=√0.45(1-0.45)/600

If x≅N(u,σ∧∧-2), then z=(x-u)/σ≅N(0,1)

Now, P(P>0.6)=P(<u>P-P</u>   >     <u>0.6-0.45)</u>

                             σ          √0.45*0.55/600

=P(Z> <u>0.6-0.45)</u>

       √0.45*0.55/600

8 0
2 years ago
Suppose you roll a pair of honest dice. If you roll a total of 7 you win $22, if you roll a total of 11 you win $66, if you roll
JulijaS [17]

Answer:

The expected payoff for this game is -$1.22.

Step-by-step explanation:

It is given that a pair of honest dice is rolled.

Possible outcomes for a dice = 1,2,3,4,5,6

Two dices are rolled then the total number of outcomes = 6 × 6 = 36.

\{(1,1),(1,2),(1,3),(1,4),(1,5),(1,6),(2,1),(2,2),(2,3),(2,4),(2,5),(2,6),\\(3,1),(3,2),(3,3),(3,4),(3,5),(3,6),(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),\\(5,1),(5,2),(5,3),(5,4),(5,5),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)\}

The possible ways of getting a total of 7,

{ (1,6), (2,5), (3,4), (4,3), (5,2), (6,1) }

Number of favorable outcomes = 7

Formula for probability:

Probability=\frac{\text{Favorable outcomes}}{\text{Total outcomes}}

So, the possibility of getting a total of 7 = \frac{6}{36}=\frac{1}{6}

The possible ways of getting a total of 11,

{(5,6), (6,5)}

So, the probability of getting a total of 11 = \frac{2}{36} = \frac{1}{18}

Now, other possible rolls = 36 - 6 - 2 = 36 - 8 = 28,

So, the probability of getting the sum of numbers other than 7 or 11 = \frac{28}{36} = \frac{7}{9}

Since, for the sum of 7, $ 22 will earn, for the sum of 11, $ 66 will earn while for any other total loss is $11,

Hence, the expected value for this game is

\frac{1}{6}\times 22+\frac{1}{18}\times 66-\frac{7}{9}\times 11

\frac{11}{3}+\frac{11}{3}-\frac{77}{9}

\frac{22}{3}-\frac{77}{9}

\frac{66-77}{9}

-\frac{11}{9}

-1.22

Therefore the expected payoff for this game is -$1.22.

4 0
2 years ago
In each of Problems 5 through 10, verify that each given function is a solution of the differential equation.
WARRIOR [948]

Answer:

For First Solution: y_1(t)=e^t

y_1(t)=e^t is the solution of equation y''-y=0.

For 2nd Solution:y_2(t)=cosht

y_2(t)=cosht  is the solution of equation y''-y=0.

Step-by-step explanation:

For First Solution: y_1(t)=e^t

In order to prove whether it is a solution or not we have to put it into the equation and check. For this we have to take derivatives.

y_1(t)=e^t

First order derivative:

y'_1(t)=e^t

2nd order Derivative:

y''_1(t)=e^t

Put Them in equation y''-y=0

e^t-e^t=0

0=0

Hence y_1(t)=e^t is the solution of equation y''-y=0.

For 2nd Solution:

y_2(t)=cosht

In order to prove whether it is a solution or not we have to put it into the equation and check. For this we have to take derivatives.

y_2(t)=cosht

First order derivative:

y'_2(t)=sinht

2nd order Derivative:

y''_2(t)=cosht

Put Them in equation y''-y=0

cosht-cosht=0

0=0

Hence y_2(t)=cosht  is the solution of equation y''-y=0.

3 0
2 years ago
The area of a second soup can’s base is 5 pi inches squared. The can has a height of 10 inches. How would you use that informati
Ilia_Sergeevich [38]

Answer:

The amount of soup the can will hold is;

50π inches cubed = 157.08 inches cubed

Step-by-step explanation:

The amount of soup the can will hold is equal to the volume of the can.

Volume of the can = base area × height

Given;

Base Area = 5π inches squared

height = 10 inches

Volume of can = 5π × 10 = 50π inches cubed

The amount of soup the can will hold is;

50π inches cubed = 157.08 inches cubed

8 0
2 years ago
Read 2 more answers
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