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2 years ago

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Ramina found the length of two pieces of ribbon to be 47.6 inches and 39.75 inches. Which is an effective estimation strategy fo

r finding the sum of the two lengths? Round 39.75 to 30 and 47.6 to 40, then add. Round 39.75 to 40 and 47.6 to 48, then add. Add 47.6 and 39.75, then round the answer. Subtract 39.75 from 47.6, then round the answer.

3 answers:

lukranit [14]2 years ago

7 0

Answer:

<h3>Add 47.6 and 39.75, then round the answer</h3>

Step-by-step explanation:

If Ramina found the length of two pieces of ribbon to be 47.6 inches and 39.75 inches, the effective strategy of finding the sum of the two lengths is to:

1) First is to add the two values together

47.6 + 39.75

= (47+0.6)+(39+0.75)

= (47+39)+(0.6+0.75)

= 86 + 1.35

= 87.35

2) Round up the answer to nearest whole number.

87.35 ≈ 87 (note that we couldn't round up to 88 because the values after the decimal point wasn't up to 5)

Option C is correct

pashok25 [27]2 years ago

5 0

Answer:

B. Round 39.75 to 40 and 47.6 to 48, then add.

Step-by-step explanation:

Guest1 year ago

0 0

add 47.6 to 48

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Suppose that the number of drivers who travel between a particular origin and destination during a designated time period has a

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Answer:

a) P(k≤11) = 0.021

b) P(k>23) = 0.213

c) P(11≤k≤23) = 0.777

P(11<k<23) = 0.699

d) P(15<k<25)=0.687

Step-by-step explanation:

a) What is the probability that the number of drivers will be at most 11?

We have to calculate P(k≤11)

$P(k\leq11)=\sum_0^{11} P(k$

$P(k=0) = 20^0e^{-20}/0!=1 \cdot 0.00000000206/1=0\\\\P(k=1) = 20^1e^{-20}/1!=20 \cdot 0.00000000206/1=0\\\\P(k=2) = 20^2e^{-20}/2!=400 \cdot 0.00000000206/2=0\\\\P(k=3) = 20^3e^{-20}/3!=8000 \cdot 0.00000000206/6=0\\\\P(k=4) = 20^4e^{-20}/4!=160000 \cdot 0.00000000206/24=0\\\\P(k=5) = 20^5e^{-20}/5!=3200000 \cdot 0.00000000206/120=0\\\\P(k=6) = 20^6e^{-20}/6!=64000000 \cdot 0.00000000206/720=0\\\\P(k=7) = 20^7e^{-20}/7!=1280000000 \cdot 0.00000000206/5040=0.001\\\\$

$P(k=8) = 20^8e^{-20}/8!=25600000000 \cdot 0.00000000206/40320=0.001\\\\P(k=9) = 20^9e^{-20}/9!=512000000000 \cdot 0.00000000206/362880=0.003\\\\P(k=10) = 20^{10}e^{-20}/10!=10240000000000 \cdot 0.00000000206/3628800=0.006\\\\P(k=11) = 20^{11}e^{-20}/11!=204800000000000 \cdot 0.00000000206/39916800=0.011\\\\$

$P(k\leq11)=\sum_0^{11} P(k$

b) What is the probability that the number of drivers will exceed 23?

We can write this as:

$P(k>23)=1-\sum_0^{23} P(k=x_i)=1-(P(k\leq11)+\sum_{12}^{23} P(k=x_i))$

$P(k=12) = 20^{12}e^{-20}/12!=8442485.238/479001600=0.018\\\\P(k=13) = 20^{13}e^{-20}/13!=168849704.75/6227020800=0.027\\\\P(k=14) = 20^{14}e^{-20}/14!=3376994095.003/87178291200=0.039\\\\P(k=15) = 20^{15}e^{-20}/15!=67539881900.067/1307674368000=0.052\\\\P(k=16) = 20^{16}e^{-20}/16!=1350797638001.33/20922789888000=0.065\\\\P(k=17) = 20^{17}e^{-20}/17!=27015952760026.7/355687428096000=0.076\\\\P(k=18) = 20^{18}e^{-20}/18!=540319055200533/6402373705728000=0.084\\\\$

$P(k=19) = 20^{19}e^{-20}/19!=10806381104010700/121645100408832000=0.089\\\\P(k=20) = 20^{20}e^{-20}/20!=216127622080213000/2432902008176640000=0.089\\\\P(k=21) = 20^{21}e^{-20}/21!=4322552441604270000/51090942171709400000=0.085\\\\P(k=22) = 20^{22}e^{-20}/22!=86451048832085300000/1.12400072777761E+21=0.077\\\\P(k=23) = 20^{23}e^{-20}/23!=1.72902097664171E+21/2.5852016738885E+22=0.067\\\\$

$P(k>23)=1-\sum_0^{23} P(k=x_i)=1-(P(k\leq11)+\sum_{12}^{23} P(k=x_i))\\\\P(k>23)=1-(0.021+0.766)=1-0.787=0.213$

c) What is the probability that the number of drivers will be between 11 and 23, inclusive? What is the probability that the number of drivers will be strictly between 11 and 23?

Between 11 and 23 inclusive:

$P(11\leq k\leq23)=P(x\leq23)-P(k\leq11)+P(k=11)\\\\P(11\leq k\leq23)=0.787-0.021+ 0.011=0.777$

Between 11 and 23 exclusive:

$P(11< k$

d) What is the probability that the number of drivers will be within 2 standard deviations of the mean value?

The standard deviation is

$\mu=\lambda =20\\\\\sigma=\sqrt{\lambda}=\sqrt{20}= 4.47$

Then, we have to calculate the probability of between 15 and 25 drivers approximately.

$P(15$

$P(k=16) = 20^{16}e^{-20}/16!=0.065\\\\P(k=17) = 20^{17}e^{-20}/17!=0.076\\\\P(k=18) = 20^{18}e^{-20}/18!=0.084\\\\P(k=19) = 20^{19}e^{-20}/19!=0.089\\\\P(k=20) = 20^{20}e^{-20}/20!=0.089\\\\P(k=21) = 20^{21}e^{-20}/21!=0.085\\\\P(k=22) = 20^{22}e^{-20}/22!=0.077\\\\P(k=23) = 20^{23}e^{-20}/23!=0.067\\\\P(k=24) = 20^{24}e^{-20}/24!=0.056\\\\$

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The graph of f(x) = x6 – 2x4 – 5x2 + 6 is shown below.

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Answer:

There are two rational roots for f(x)

Step-by-step explanation:

We are given a function

$f(x) = x^6-2x^4-5x^2+6$

To find the number of rational roots for f(x).

Let us use remainder theorem that when

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Substitute 1 for x

f(1) = 1-2-5+6=0

Hence x=1 is one solution.

Let us try x=-1

f(-1) = 1-2-5+6 =0

So x =-1 is also a solution and x+1 is a factor

We can write f(x) by trial and error as

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A social scientist is interested in determining if there is a significant difference in the proportion of Republicans between tw

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Answer:

Given

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n = 200 families

Our conclusion goes as follows:

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If the point (4,-1) is a point on the graph of f then f

AlekseyPX

If the point (4,-1) is a point on the graph of y = f(x). The corresponding point on the graph of y = g(x) is: (4,-1/2), (2,-1), (-1,-1), (1,4), (4,-4), (-12,1)

$g(x) = \frac{1}{2} f(x)$ => (4,-1/2)
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$g(x) = f(-x)$ => (-1,-1)
$g(x) = f(4x)$ => (1,4)
$g(x) = 4f(x)$ => (4,-4)
$g(x) = -f(x)$ => (-12,1)

<h3>Further explanation </h3>

Dividing the function by 2 divides all the y-values by 2 as well. So to get the new point, we will take the y-value (-1) and divide it by 2 to get 2. Therefore, the new point is (4,-1/2)
Subtracting 2 from the input of the function makes all of the x-values increase by 2 (in order to compensate for the subtraction). We will need to add 2 to the x-value (4) to get 2. Therefore, the new point is (2,-1)
Making the input of the function negative will multiply every x-value by 1. To get the new point, we will take the x-value (4) and multiply it by -1 to get. Therefore, the new point is (-1,-1)
Multiplying the input of the function by 4 makes all of the x-values be divided by 4 (in order to compensate for the multiplication). We will need to divide the x-value (4) by 4 to get 1. Therefore, the new point is (1,4)
Multiplying the whole function by 4 increases all y-values by a factor of 4 , so the new y-value will be 4 times the original value (4) or -4. Therefore, the new point is (4,-4)
Multiplying the whole function by -1 also multiplies every y-value by -1, so the new y-value will be -1 times the original value (-1). or 1. Therefore, the new point is (-12,1)

<h3>Learn more</h3>

Learn more about corresponding point brainly.com/question/10218370
Learn more about point on the graph brainly.com/question/11297347
Learn more about the graph brainly.com/question/11534295

<h3>Answer details</h3>

Grade: 9

Subject: mathematics

Chapter: corresponding point

Keywords: corresponding point, the graph, point on the graph

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