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2 years ago

Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s).

2 answers:

5 0

If $y=3x^2+30x+71$ , then
$y=3(x^2+10x)+71=3(x^2+2\cdot5x+25-25)+71$
$y=3((x+5)^2-25)+71=3(x+5)^2-75+71=3(x+5)^2-4$ . So, in the first gap you can write 5 and in the second you can write -4.
Since $(x+5)^2\ge 0$ , the minimum value of y is when $(x+5)^2=0$ . The solution of the last equation is x=-5 and then y=-4 -- these are numbers, which you can write in the third and fourth gaps.

nexus9112 [7]2 years ago

4 0

Answer:

Type the correct answer in the box. Use numerals instead of words. If necessary, use / for the fraction bar.

If a submarine dives 378 feet in 14 seconds, the average change in elevation is

feet per second.

Step-by-step explanation:

FOR PLATO TYPE "27"

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5.6e12 in standard form

german

To make 5.6e12 standard you simply move the decimal place right 12 times
5,600,000,000,000
5 Trillion 600 billion

5 0

2 years ago

Read 2 more answers

Lin has 13 coins in her pocket that equal 40 cents. All the coins are dimes, d, and pennies, p. Which combination of coins does

Luden [163]

To answer this question you should begin with the coin that has a higher value. If you start with the dime and then just add the correct number of pennies to total $0.40, you will see that you will need 3 dimes ($0.30) and 10 pennies ($0.10).

I used a guess and check strategy starting with 2 dimes.

7 0

2 years ago

Read 2 more answers

The first three terms of an arithmetic series are 6p+2, 4p²-10 and 4p+3 respectively. Find the possible values of p. Calculate t

Doss [256]

Answer:

First Case:

$\displaystyle p=\frac{5}{2}\text{ and } d=-2$

Second Case:

$\displaystyle p=-\frac{5}{4}\text{ and } d=\frac{7}{4}$

Step-by-step explanation:

We know that the first three terms of an arithmetic series are:

$6p+2, 4p^2-10, \text{ and } 4p+3$

Since this is an arithmetic sequence, each subsequent term is d more than the previous term, where d is our common difference.

Therefore, we can write the second term as;

$4p^2-10=(6p+2)+d$

And, likewise, for the third term:

$4p+3=(6p+2)+2d$

Let's solve for d for each of the equations.

Subtracting in the first equation yields:

$d=4p^2-6p-12$

And for the second equation:

$2d=-2p+1$

To avoid fractions, let's multiply the first equation by 2. Hence:

$2d=8p^2-12p-24$

Therefore:

$8p^2-12p-24=-2p+1$

Simplifying yields:

$8p^2-10p-25=0$

Solve for p. We can factor:

$8p^2+10p-20p-25=0$

Factor:

$2p(4p+5)-5(4p+5)=0$

Grouping:

$(2p-5)(4p+5)=0$

Zero Product Property:

$\displaystyle p_1=\frac{5}{2} \text{ or } p_2=-\frac{5}{4}$

Then, we can use the second equation to solve for d. So:

$2d_1=-2p_1+1$

Substituting:

$\begin{aligned} 2d_1&=-2(\frac{5}{2})+1 \\ 2d_1&=-5+1 \\ 2d_1&=-4 \\ d_1&=-2\end{aligned}$

So, for the first case, p is 5/2 and d is -2.

Likewise, for the second case:

$\begin{aligned} 2d_2&=-2(-\frac{5}{4})+1 \\ 2d_2&=\frac{5}{2}+1 \\ 2d_2&=\frac{7}{2} \\ d_2&=\frac{7}{4}\end{aligned}$

So, for the second case, p is -5/4, and d is 7/4.

By using the values, we can determine our series.

For Case 1, we will have:

17, 15, 13.

For Case 2, we will have:

-11/2, -15/4, -2.

8 0

1 year ago

Which product is positive?

Virty [35]

Answer:

(Negative two-fifths) (Negative StartFraction 8 over 9 EndFraction) (one-third) (StartFraction 2 over 7 EndFraction)

Step-by-step explanation:

(Negative two-fifths) (Negative StartFraction 8 over 9 EndFraction) (one-third) (StartFraction 2 over 7 EndFraction) = (-2/5)(-8/9)(1/3)(2/7)

Let's take the fraction and eliminate the negative sign because negative multiply negative= positive

(-2/5)(-8/9)(1/3)(2/7)= 32/945

4 0

2 years ago

Read 2 more answers

walnut grower estimates from past records that if 20 trees are planted per acre, then each tree will average 60 pounds of nuts p

laila [671]

Answer:

5 trees should be planted to maximize the yield per acre,

The maximum yield would be 1250

Step-by-step explanation:

Given,

The original number of trees per acre = 20,

Average pounds of nuts by a tree = 60,

Let x be the times of increment in number of trees,

So, the new number of trees planted per acre = 20 + x

∵ for each additional tree planted per acre, the average yield per tree drops 2 pounds,

So, the new number of pounds of nut = (60 - 2x)

Thus, the total yield per acre,

$Y(x) = (20+x)(60-2x)$

Differentiating with respect to t ( time ),

$Y'(x) = (20+x)(-2) + 60 - 2x = -40 - 2x + 60 - 2x = 20 - 4x$

Again differentiating with respect to t,

$Y''(x) = -4$

For maxima or minima,

$Y'(x) = 0$

⇒ 20 - 4x = 0

⇒ 20 = 4x

⇒ x = 5,

For x = 5, Y''(x) = negative,

Hence, Y(x) is maximum for x = 5,

And, maximum value of Y(x) = (20+5)(60 - 10) = 25(50) = 1250,

i.e. 5 trees should be planted to maximize the yield per acre,

and the maximum yield would be 1250 pounds

4 0

2 years ago