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Leona [35]
2 years ago
6

We hear a great deal about overpopulation, but if air and elbow room were not an issue, show that you could put the entire world

population of humans, 7 billion people, into a cube 1 mile x 1 mile x 1 mile. Assume, on average, people can fit into a box that is 7' tall, 2' wide and 1' deep.
Mathematics
1 answer:
Anna35 [415]2 years ago
8 0

Answer: The below explanation shows that we could put the entire population on the given box.

Step-by-step explanation:

Here, it is given that on average, people can fit into a box that is 7' tall, 2' wide and 1' deep.

That is, the approximate volume of the box in which a person can be fit = 7 × 2 × 1 = 14 cube feet

But, the given population of the world = 7 000,000,000

Thus, the total approximate volume of the 7 billion people =  14 × 7 000,000,000 = 98,000,000,000 cube feet

Also, it is given that, the volume of the given box = 1 mile x 1 mile x 1 mile = 5280^3 cube feet = 147197952000 cube feet.

Since, we can say that the entire population of the world can put the box

If total volume of the box / total volume of the population \geq 1

Here,   147197952000 / 98,000,000,000 = 1.5 > 1

Therefore, the entire population can be put in the box.


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Answer:

The answer in the procedure

Step-by-step explanation:

Let

A1 ------> the area of the first square painting

A2 ---->  the area of the second square painting

D -----> the difference of the areas

we have

A1=81x^{2}-90x-25

A2=25x^{2}+30x+9

case 1) The area of the second square painting is greater than the area of the first square painting

The difference of the area of the paintings is equal to subtract the area of the first square painting from the area of the second square painting

D=A2-A1

D=(25x^{2}+30x+9)-(81x^{2}-90x-25)

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case 2) The area of the first square painting is greater than the area of the second square painting

The difference of the area of the paintings is equal to subtract the area of the second square painting from the area of the first square painting

D=A1-A2

D=(81x^{2}-90x-25)-(25x^{2}+30x+9)

D=(56x^{2}-120x-34)

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