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-BARSIC- [3]
2 years ago
12

Joe's Painting charges $100 plus $20 per hour to paint the exterior of your home. Steve's Painting charges $120 plus $15 per hou

r to paint the exterior of your home. How many hours do Joe and Steve have to work for their models to be equal to each other? Which of the following systems is correct for this situation if "x" = hours worked and "y" = total income.
Mathematics
1 answer:
Tanzania [10]2 years ago
5 0

Joe's Painting: 20x + 100 = y

Steve's Painting: 15x + 120 = y

x = hours worked

y = total income

We can find when the two equations intersect by making them equal to each other. That means we put an equal sign in the middle. So, it would look something like this:

20x + 100 = 15x + 120

First, we have to move the 100 by subtracting it from both sides.

20x = 15x + 120 - (100)

20x = 15x + 20

Then, we need to move the 15x by subtracting it from both sides.

20 - (15x) = 20

5x = 20

Lastly, we need to divide 5 from both sides.

5x = 20/5

x = 4

Therefore, Joe and Steve would have to work for 4 hours in order for their models to be equal to each other.

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Which hyperbola has one focus point in common with the hyperbola (y+11)^2/(15^2)-(x-7)^2/(8^2)=1
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\bf \textit{hyperbolas, vertical traverse axis }\\\\
\cfrac{(y-{{ k}})^2}{{{ a}}^2}-\cfrac{(x-{{ h}})^2}{{{ b}}^2}=1
\qquad 
\begin{cases}
center\ ({{ h}},{{ k}})\\
vertices\ ({{ h}}, {{ k}}\pm a)
\end{cases}\\\\
-------------------------------\\\\
\cfrac{(y+11)^2}{15^2}-\cfrac{(x-7)^2}{8^2}=1\implies \cfrac{(y-(-11))^2}{15^2}-\cfrac{(x-7)^2}{8^2}=1\\\\
-------------------------------\\\\
c=\textit{distance from the center to either foci}\\\\
c=\sqrt{a^2+b^2}\implies c=\sqrt{15^2+8^2}\implies \boxed{c=17}

now, if you notice, the positive fraction, is the one with the "y" variable, and that simply means, the hyperbola traverse axis is over the y-axis, so it more or less looks like the picture below.

now, from the hyperbola form, we can see the center is at (7, -11), and that the "c" distance is 17.

so, from -11 over the y-axis, we move Up and Down 17 units to get the foci, which will put them at (7, -11-17) or (7, -28) and (7 , -11+17) or (7, 6)

5 0
2 years ago
Read 2 more answers
The scale factor of a room for a scale drawing is 2.3. The actual length of a wall in the room is 46 feet and the actual width o
dimaraw [331]

Answer:

There's two ways to solve this.

Step-by-step explanation:

First way:

Let's divide the width and length by 2.3.

46÷2.3=20

69÷2.3=30

20×30

600 ft²

Second Way:

Let's find the area of the actual room.

46×69

3,174 ft²

Let's find the scale drawing squared.

2.3²=5.29

3,174÷5.29

600 ft²

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2 years ago
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Now let the figure show a scale drawing of a park. The scale is 1 unit : 25 meters. What is the horizontal distance across the p
insens350 [35]

The question is missing the figure. So, the figure is attached below.

Answer:

C. 350 m

Step-by-step explanation:

Given:

Scale  is given as:

1 unit  : 25 meters

This means that 1 unit on the grid is equivalent to 25 meters in actual.

Now, from the figure, the horizontal distance across the park is 14 units.

1 unit = 25 meter

Now, we can find the actual distance using unitary method and thus multiplying 25 and 14 to get the actual distance across the park horizontally.

∴ 14 units = 25\times 14=350 meters.

Therefore, the horizontal distance across the park is 350 m in actual.

So, the correct option is option C.

7 0
2 years ago
A bag contains 15 15 red candies, 15 15 yellow candies, and 15 15 blue candies. what is the probability of randomly choosing two
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Based on my calculations, this would be 10%.
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He would get $40 and the correct graphs is c
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