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kap26 [50]
2 years ago
7

The soccer team collected $800 at a car wash fundraiser. They charged $5.00 for small vehicles and $10.00 for larger vehicles. T

he amount collected can be modeled by the equation 5x + 10y = 800, where x represents the number of small vehicles and y represents the number of larger vehicles. If the number of larger vehicles washed was 50, how many small vehicles were washed in total?
Mathematics
2 answers:
galina1969 [7]2 years ago
6 0

Answer:

Number of small vehicles washed were 60.

Step-by-step explanation:

Soccer team collected $800 by charging $5 for the small vehicles and $10 for larger vehicles.

Amount collected was modeled by the equation

5x + 10y = 800

Where x = Number of small vehicles

y = Number of larger vehicles

If y = 5 then we have to calculate the number of small vehicles washed.

By putting y = 50 in the equation,

5x + 10(50) = 800

5x + 500 = 800

5x = 800 - 500

5x = 300

x = \frac{300}{5}

x = 60

Therefore, number of small vehicles washed were 60.

Evgen [1.6K]2 years ago
3 0
Plug 50 into y and find x.

5x + 10 (50) = 800
5x + 500 = 800
5x = 800 - 500
5x = 300
x = 300 ÷ 5
x = 60
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Step-by-step explanation:

Given

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Step-by-step explanation:

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2 years ago
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Answer:

The probability that a defective ball bearing was manufactured on a Friday = 0.375

Step-by-step explanation:

Let the event of making a mistake = M

The event of making a precision ball bearing production on Monday = Mo

The event of making a precision ball bearing production on Tuesday = T

The event of making a precision ball bearing production on Wednesday = W

The event of making a precision ball bearing production on Thursday = Th

The event of making a precision ball bearing production on Friday = F

the conditional probability of making a manufacturing mistake in its precision ball bearing production is 4% on Tuesday, P(M|T) = 4% = 0.04

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and 12% on Friday = P(M|F) = 0.12

The Company manufactures an equal amount of ball bearings (20 %) on each weekday, Hence, the probability that a random precision ball bearing was made on a particular day of the week, is mostly the same for all the five working days.

P(Mo) = 0.20

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P(W) = 0.20

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The probability that a defective ball bearing was manufactured on a Friday = P(F|M)

P(F|M) = P(F n M) ÷ P(M)

P(F n M) = P(M n F)

P(M) = P(Mo n M) + P(T n M) + P(W n M) + P(Th n M) + P(F n M)

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P(T n M) = P(M|T) × P(T) = 0.04 × 0.20 = 0.008

P(W n M) = P(M|W) × P(W) = 0.04 × 0.20 = 0.008

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P(M) = P(Mo n M) + P(T n M) + P(W n M) + P(Th n M) + P(F n M)

P(M) = 0.016 + 0.008 + 0.008 + 0 008 + 0.024 = 0.064

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P(F n M) = P(M n F) = 0.024

P(M) = 0.064

P(F|M) = P(F n M) ÷ P(M) = (0.024/0.064) = 0.375

Hope this Helps!

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6 0
2 years ago
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