An airline gathers data on late departures and early arrivals over a month. It finds that the probability of a late departure is
2 answers:
Answer: P(late departure or early arrival) = 0.12 + 0.27 – 0.04
Step-by-step explanation:
Given : The probability of a late departure is 12 %t, the probability of an early arrival is 27%.
i.e. P(late departure)=0.12
P(an early arrival)=0.27
The probability of both a late departure and an early arrival is 4 percent.
P(late departure and early arrival) =0.04
Now, using formula the probability of union of two dependent events A and B:-
i.e. P(late departure or early arrival) = P(late departure)+P(an early arrival)-P(late departure and early arrival)
=0.12+0.27-0.0.04
Hence, the required equation : P(late departure or early arrival) = 0.12 + 0.27 – 0.04
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<h2>Therefore he took 40 gram of 
type solution and 10 gram of 
type solution.</h2>
Step-by-step explanation:
Given that , A pharmacist 13% alcohol solution another 18% alcohol solution .
Let he took x gram solution of type solution
and he took (50-x) gram of type solution.
Total amount of alcohol = gram
Total amount of solution = 50 gram
According to problem
⇔
⇔
⇔- 5x= 700 - 900
⇔5x = 200
⇔x = 40 gram
Therefore he took 40 gram of type solution and (50 -40)gram = 10 gram of
type solution.