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grigory [225]
2 years ago
15

What are the steps for using a compass and straightedge to construct a square? Drag and drop the steps in order from start to fi

nish.
1.Construct a line perpendicular to line m through point F. Label a point on this line as point G.
2.Use a straightedge to draw line m and label a point on the line as point F.
3.Without changing the compass width, place the compass point on point H and draw an arc in the interior of ∠HFK .
4.Use the straightedge to draw JH¯¯¯¯¯ and JK¯¯¯¯¯.
5.With the compass open to the desired side length of the square, place the compass point on point F and draw an arc on line m and an arc on FG←→ . Label the points of intersection as points H and K.
6.Keeping the same compass width, place the compass on point K and draw an arc in the interior of ∠HFK to intersect the previously drawn arc. Label the point of intersection as point J.

Mathematics
2 answers:
Mazyrski [523]2 years ago
5 0

For those of you who are doin the test rn here are the answers to all of them. Hope this helps! ;) I did the quiz

Aleks04 [339]2 years ago
3 0
<span>The steps for using a compass and straightedge to construct a square are given as follows:

1. </span><span>Use a straightedge to draw line m and label a point on the line as point F

2. </span><span>Construct a line perpendicular to line m through point F. Label a point on this line as point G.

3. </span><span>With the compass open to the desired side length of the square, place the compass point on point F and draw an arc on line m and an arc on FG←→ . Label the points of intersection as points H and K.

4. </span><span>Without changing the compass width, place the compass point on point H and draw an arc in the interior of ∠HFK.

5. </span><span>Keeping the same compass width, place the compass on point K and draw an arc in the interior of ∠HFK to intersect the previously drawn arc. Label the point of intersection as point J.

6. </span><span>Use the straightedge to draw JH¯¯¯¯¯ and JK¯¯¯¯¯.
</span>
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You have just timed a person doing a hair cut for the first time. It took 50 minutes. What unit improvement factor learning curv
Sladkaya [172]

Answer: C. 70 percent

Step-by-step explanation:

Given, Time for the first unit = 50 minutes

Time for the second unit = 35 minutes

The unit improvement factor learning curve = (The time for the second unit) ÷ (time for the first unit) x 100.

So, The unit improvement factor learning curve  = 35÷ 50 × 100 = 70 percent.

Hence, the correct option is "C. 70 percent".

3 0
2 years ago
Rework problem 28 from section 3.1 of your text, involving the inspection of refrigerators on an assembly line. You should still
sergeinik [125]
Event: Probability: A. Too much enamel 0.18 B. Too little enamel 0.24 C. Uneven application 0.33 D. No defects noted 0.47 


let P(AC) = x, P(BC) = y, then P(A) + P(B) + P(C) - (x+y) = 1-0.47 = 0.53 x+y = 0.22 
3. The probability of paint defects that results to <span>an improper amount of paint and uneven application? </span>
 P(A U B U C) = 0.53 

4. <span>the probability of a paint defect that results to</span>
<span>the proper amount of paint, but uneven application?</span>
P(C) - P(AC) - P(BC) = 0.47 - 0.22 = 0.25 


A and B are disjoint so P(ABC) = 0, but you can have P(AC) and P(BC). you can't compute these separately here, but you can compute P(AC) + P(BC). By the way, P(AC) eg is just an abbreviated version of P(A∩C).
3 0
2 years ago
Sierra is selling bracelets to raise money for the Language Club at school. Each bracelet with yellow beads sells for $5. Each b
matrenka [14]

Answer:

Correct answer is:

5y+6r=660\\y=2r+8

Step-by-step explanation:

Given that Number of bracelets with yellow beads is represented by y

Each bracelet with yellow beads is sold for $5.

Total money raised by bracelets with yellow beads = Number of bracelets sold \times Money raised by sale of one such bracelet = 5y

Also Given that Number of bracelets with Orange beads is represented by r

Each bracelet with orange beads is sold for $6.

Total money raised by bracelets with orange beads = Number of bracelets sold \times Money raised by sale of one such bracelet = 6r

Given that total money raised by sale of both type of bracelets is $660.

so, the first equation becomes:

5y+6r=660 ....... (1)

It is also given that "<em>The number of bracelets with yellow beads that Sierra sold is 8 more than twice the number of bracelets with orange beads</em>"

\Rightarrow r =2r+8 ...... (2)

So, by equation (1) and (2), the system of equations is:

5y+6r=660\\y=2r+8

5 0
2 years ago
How do you use a number line to solve 235+123
Novosadov [1.4K]
<span>Number line refers to a mathematical process of solving the equation with the use of lines.
=> 235 + 123
Starting from 0 you count 1 up to 235. Then starting from 235 you additionally count another 123.
Then from zero start counting the total number to the line you stopped when adding 123 to 235.

This simply equals to
=> 235 + 123
=> 358.
Pls. see attached image for illustration of number line.</span>Answer here

6 0
2 years ago
Brad wants to buy flowers for his friend with $15. The daisies are $1 each and the roses are $3 each. He buys 3 more daisies tha
melisa1 [442]
D + 3r = 15
d = r + 3

r + 3 + 3r = 15
4r + 3 = 15
4r = 15 - 3
4r = 12
r = 12/4
r = 3 ....he bought 3 roses, at $ 3 per rose = $ 9 <==

d = r + 3
d = 3 + 3
d = 6....he bought 6 daisies, at $ 1 per daisy = $ 6
6 0
2 years ago
Read 2 more answers
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