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nordsb [41]
1 year ago
12

A group of students randomly exit the school bus after returning from a field trip. You want to calculate the probability of two

specific students leaving the bus first. Are the events independent or dependent? Why?
Mathematics
2 answers:
lara31 [8.8K]1 year ago
8 0

Dependent because the outcome of the first event affects the outcome of the second event.



Lilit [14]1 year ago
7 0
Dependant because one event cannot happen without the other taking place
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9x9x9x9x7x7 index notation
azamat

Answer:

321,489 is the answer I got

Step-by-step explanation:

(sorry if wrong/incorrect!)

6 0
2 years ago
Meghan says the difference between the least amount of time it takes a student to say the alphabet and the greatest amount of th
kupik [55]

Answer:

67 eghan says the difference between the least amount of time it takes a student to say the alphabet and the greatest amount

Step-by-step explanation:

4 0
2 years ago
Body armor provides critical protection for law enforcement personnel, but it does affect balance and mobility. The article "Imp
yKpoI14uk [10]

Answer:

No, there is not enough evidence to support the claim that true average task time with armor is less than 2 seconds.

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that true average task time with armor is less than 2 seconds.

Then, the null and alternative hypothesis are:

H_0: \mu=2\\\\H_a:\mu< 2

The significance level is 0.01.

The sample has a size n=52.

The sample mean is M=1.95.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=0.2.

The estimated standard error of the mean is computed using the formula:

s_M=\dfrac{s}{\sqrt{n}}=\dfrac{0.2}{\sqrt{52}}=0.028

Then, we can calculate the t-statistic as:

t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{1.95-2}{0.028}=\dfrac{-0.05}{0.028}=-1.803

The degrees of freedom for this sample size are:

df=n-1=52-1=51

This test is a left-tailed test, with 51 degrees of freedom and t=-1.803, so the P-value for this test is calculated as (using a t-table):

P-value=P(t

As the P-value (0.039) is bigger than the significance level (0.01), the effect is not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that true average task time with armor is less than 2 seconds.

3 0
2 years ago
The course length of the Boston Marathon is about 4.2×104 meters. The course length of the Iditarod Trail Invitational ultra-mar
GREYUIT [131]

Answer:

The ultra-marathon Idita Rod Trail is about 38 times longer than the Boston Marathon.

Step-by-step explanation:

Let

x -----> the length of the Boston Marathon in meters

y -----> the  length of the Idita rod Trail Invitational ultra-marathon in meters

we have

x=4.2*10^4\ m

y=1.6*10^6\ m

we know that

To find out how many times as long is the course of the Idita rod Trail ultra-marathon as that of the Boston Marathon, divide the length of the Idita rod Trail Invitational ultra-marathon by the length of the  Boston Marathon

so

\frac{y}{x}

\frac{x}{y}=\frac{1.6*10^6}{4.2*10^4}

Remember that

To divide two numbers in scientific notation, divide their coefficients and subtract their exponents

\frac{1.6*10^6}{4.2*10^4}=\frac{1.6}{4.2}*(10^{6-4})=0.381*(10^{2})=38.1

therefore

The ultra-marathon Idita Rod Trail is about 38 times longer than the Boston Marathon.

5 0
2 years ago
It is claimed that 55% of marriages in the state of California end in divorce within the first 15 years. A large study was start
kykrilka [37]

Answer:

0.0045 = 0.45% probability that less than two of them ended in a divorce

Step-by-step explanation:

For each marriage, there are only two possible outcomes. Either it ended in divorce, or it did not. The probability of a marriage ending in divorce is independent of any other marriage. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

55% of marriages in the state of California end in divorce within the first 15 years.

This means that p = 0.55

Suppose 10 marriages are randomly selected.

This means that n = 10

What is the probability that less than two of them ended in a divorce?

This is

P(X < 2) = P(X = 0) + P(X = 1)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{10,0}.(0.55)^{0}.(0.45)^{10} = 0.0003

P(X = 1) = C_{10,1}.(0.55)^{1}.(0.45)^{9} = 0.0042

P(X < 2) = P(X = 0) + P(X = 1) = 0.0003 + 0.0042 = 0.0045

0.0045 = 0.45% probability that less than two of them ended in a divorce

8 0
1 year ago
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