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worty [1.4K]
2 years ago
13

​You'd like to estimate the proportion of the 12,152 full-time undergraduate students at a university who are foreign students.

You poll a random sample of 50 ​students, of whom 7 are from foreign countries. Unknown to ​you, the proportion of all undergraduate students who are foreign students is 0.06.
Let X denote a random variable for which x=1 denotes foreign students and x=0 denotes students from the U.S. Complete parts​ (a) through​ (c).

a. Describe the data distribution.

The data distribution consists of ( )​1's (denoting a foreign ​student) and ( )0's (denoting a student from the​ U.S.).

b. Describe the population distribution.

The population distribution consists of the​ x-values of the population of 12,152 full-time undergraduate students at the​university, ( )​% of which are​ 1's (denoting a foreign​ student) and ( )% of which are​ 0's (denoting a student from the​ U.S.).

c. Find the mean and standard deviation of the sampling distribution of the sample proportion for a sample of size 50.

The mean is ( )

The standard deviation is ( )​(Round to four decimal places as​needed.)

Explain what this sampling distribution represents.

The sampling distribution represents the probability distribution of the ( ) proportion of foreign students in a random sample of ( )students. In this​case, the sampling distribution is approximately normal with a mean of ( ) and a standard deviation of ( )
Mathematics
1 answer:
Minchanka [31]2 years ago
5 0

Answer:

a) The data distribution consists of ( 7 )​1's (denoting a foreign ​student) and ( 43 )0's (denoting a student from the​ U.S.).

b) The population distribution consists of the​ x-values of the population of 12,152 full-time undergraduate students at the​university, ( 6 )​% of which are​ 1's (denoting a foreign​ student) and ( 94 )% of which are​ 0's (denoting a student from the​ U.S.).

c) The mean is ( 0.06 )

The standard deviation is ( 0.0336 )

The sampling distribution represents the probability distribution of the ( sample ) proportion of foreign students in a random sample of ( 50 ) students. In this​ case, the sampling distribution is approximately normal with a mean of ( 0.06 ) and a standard deviation of ( 0.0336 )

Step-by-step explanation:

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The function f(t) represents the cost to connect to the Internet at an online gaming store. It is a function of t, the time in m
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Answer:

<u>The correct answer is D. Any amount of time over an hour and a half would cost $10.</u>

Step-by-step explanation:

f (t), when t is a value between 0 and 30

The cost is US$ 0 for the first 30 minutes

f (t), when t is a value between 30 and 90

The cost is US$ 5 if the connection takes between 30 and 90 minutes

f (t), when t is a value greater than 90

The cost is US$ 10 if the connection takes more than 90 minutes

According to these costs, statements A, B and C are incorrect. The connection doesn't cost US$ 5 per hour like statement A affirms, the cost of the connection isn't US$ 5 per minute after the first 30 minutes free as statement B affirms and neither it costs US$ 10 for every 90 minutes of connection, as statement C affirms. <u>The only one that is correct is D, because any amount of time greater than 90 minutes actually costs US$ 10.</u>

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2 years ago
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You need at least $485 to go on a trip to New York City. You already have $100 saved for the trip. You decide to save an additio
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The entire trip costs 485 dollars. She has a hundred, and you are looking for the number of weeks needed to save for the trip.

Step one
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35w + 100 ≥ 485

Step two
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Since we don't have choices, we can't eliminate those that are wrong.

If I had to guess I would say it was something that looked like
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Answer:

The probability is 0.31

Step-by-step explanation:

To find the probability, we will consider the following approach. Given a particular outcome, and considering that each outcome is equally likely, we can calculate the probability by simply counting the number of ways we get the desired outcome and divide it by the total number of outcomes.

In this case, the event of interest is  choosing 3 laser printers and 3 inkjets. At first, we have a total of 25 printers and we will be choosing 6 printers at random. The total number of ways in which we can choose 6 elements out of 25 is \binom{25}{6}, where \binom{n}{k} = \frac{n!}{(n-k)!k!}. We have that \binom{25}{6} = 177100

Now, we will calculate the number of ways to which we obtain the desired event. We will be choosing 3 laser printers and 3 inkjets. So the total number of ways this can happen is the multiplication of the number of ways we can choose 3 printers out of 10 (for the laser printers) times the number of ways of choosing 3 printers out of 15 (for the inkjets). So, in this case, the event can be obtained in \binom{10}{3}\cdot \binom{15}{3} = 54600

So the probability of having 3 laser printers and 3 inkjets is given by

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