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Tamiku [17]
2 years ago
15

Andy has the following series of displacements: 3 m to the right; 4 m to the left; 5 m to the right; and 2 m to the left. What i

s his distance traveled?
Mathematics
2 answers:
Rus_ich [418]2 years ago
8 0

Answer:

14 meters

Step-by-step explanation:

Remember that distance is the total ground covered by the movement of the person that is covering that movement, in this example we just need to add all of the displacement that he does and that would be the distance since Andy actually walked all of that:

3 meters + 4 meters + 5 meters + 2 meters= 14 meters

So the total distance voered by Andy was 14 meters.

Zinaida [17]2 years ago
7 0

Answer:

The distance traveled is 2 m to the right

Step-by-step explanation:

Let's consider positive right displacements and negative left displacements

so

we have

3 m to the right -----> +3

4 m to the left -------> -4

5 m to the right -----> +5

2 m to the left -----> -2

Adds the number to determine the distance traveled

+3-4+5-2=+2

The distance traveled is 2 m to the right

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It would be 50 because the 5 is in the tens spot
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2 years ago
Read 2 more answers
Orange M&M’s: The M&M’s web site says that 20% of milk chocolate M&M’s are orange. Let’s assume this is true and set
SOVA2 [1]

Answer:

The correct option is (A).

Step-by-step explanation:

Let <em>X</em> = number of orange  milk chocolate M&M’s.

The proportion of orange milk chocolate M&M’s is, <em>p</em> = 0.20.

The number of candies in a small bag of milk chocolate M&M’s is, <em>n</em> = 55.

The event of an milk chocolate M&M being orange is independent of the other candies.

The random variable <em>X</em> follows a Binomial distribution with parameter <em>n</em> = 55 and <em>p</em> = 0.20.

The expected value of a Binomial random variable is:

E(X)=np

Compute the expected number of orange  milk chocolate M&M’s in a bag of 55 candies as follows:

E(X)=np

         =55\times 0.20\\=11

It is provided that in a randomly selected bag of milk chocolate M&M's there were 14 orange ones, i.e. the proportion of orange milk chocolate M&M's in a random bag was 25.5%.

This proportion is not surprising.

This is because the average number of orange milk chocolate M&M’s in a bag of 55 candies is expected to be 11. So, if a bag has 14 orange milk chocolate M&M’s it is not unusual at all.

All unusual events have a very low probability, i.e. less than 0.05.

Compute the probability of P (X ≥ 14) as follows:

P(X\geq 14)=\sum\limits^{55}_{x=14}{{55\choose x}0.20^{x}(1-0.20)^{55-x}}

                 =0.1968

The probability of having 14 or more orange candies in a bag of milk chocolate M&M’s is 0.1968.

This probability is quite larger than 0.05.

Thus, the correct option is (A).

4 0
2 years ago
Juanita rolls a number cube x times. For which value of x are the experimental probability and the theoretical probability most
vekshin1

Answer:

1,000

Step-by-step explanation:

The more rolls you make, the closer the experimental and theoretical probabilities get closer together

6 0
2 years ago
According to a human modeling​ project, the distribution of foot lengths of women is approximately Normal with a mean of 23.3 ce
Yakvenalex [24]

Answer:

26.11% of women in the United States will wear a size 6 or​ smaller

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 23.3, \sigma = 1.4

In the United​ States, a​ woman's shoe size of 6 fits feet that are 22.4 centimeters long. What percentage of women in the United States will wear a size 6 or​ smaller?

This is the pvalue of Z when X = 22.4. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{22.4 - 23.3}{1.4}

Z = -0.64

Z = -0.64 has a pvalue of 0.2611

26.11% of women in the United States will wear a size 6 or​ smaller

8 0
2 years ago
Dante's Mom wants to build a fence around their yard. Here are the measurements of the yard. What are the measurements of the mi
timama [110]

Answer:

(a)The missing measurements are 9 feet and 16\frac{1}{4}$ feet.

(b)Therefore, the length of the fence is  97\frac{1}{2}$ feet

Step-by-step explanation:

The diagram of the yard is attached below.

(a)I have labeled the missing dimensions of the yard as x and y.

Therefore:

y+8\frac{1}{4}=17 \frac{1}{4}\\y=17 \frac{1}{4}-8\frac{1}{4}\\y=9$ feet

Similarly:

x+15\frac{1}{4}=31\frac{1}{2}\\x=31\frac{1}{2}-15\frac{1}{4}\\x=31-15+\frac{1}{2}-\frac{1}{4}\\x=16+\frac{1}{4}\\x=16\frac{1}{4}$ feet

The missing measurements are 9 feet and 16\frac{1}{4}$ feet.

(b)Length of the Fence

The fence is rectangular shaped with:

Length = 31\frac{1}{2}$ feet

Width = 17 \frac{1}{4}$ feet

Perimeter of a Rectangle = 2(L+W)

Therefore, the length of the fence

=2(31\frac{1}{2}+17 \frac{1}{4})\\=2(31+17+\frac{1}{2}+ \frac{1}{4})\\=2(48+ \frac{3}{4})\\=96+\frac{3}{2}\\=97\frac{1}{2}$ feet

8 0
2 years ago
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