The answer
ellipse main equatin is as follow:
X²/ a² + Y²/ b² =1, where a≠0 and b≠0
for the first equation: <span>x = 3 cos t and y = 8 sin t
</span>we can write <span>x² = 3² cos² t and y² = 8² sin² t
and then </span>x² /3²= cos² t and y²/8² = sin² t
therefore, x² /3²+ y²/8² = cos² t + sin² t = 1
equivalent to x² /3²+ y²/8² = 1
for the second equation, <span>x = 3 cos 4t and y = 8 sin 4t we found
</span>x² /3²+ y²/8² = cos² 4t + sin² 4t=1
Answer:
(2,1)
Step-by-step explanation:
We can see that the given triangle.
The coordinates of A are (-1,5) .
The coordinates of B are (-1,-3).
The coordinates of C are (5,-3).
Distance formula: 
AB=
units
BC=
units
AC=
units
Pythagoras theorem:


Therefore, 
When a triangle satisfied the Pythagoras theorem then, the triangle is right triangle.
Hence, the given triangle is a right triangle.
We know that circum-center of right triangle is the mid point of hypotenuse.
Mid-point formula:
Using this formula then, we get
Mid-point of hypotenuse AC is given by

Hence, the circum-center of triangle is (2,1).
Answer:
Step-by-step explanation:
A)
y=−2x+4
y-int:
y=−2*0+4
y=4
x-int:
0=−2x+4
2x=4
x=2
(2,4)
B)
2x+3y=6
y-int:
2*0+3y=6
3y=6
y=2
x-int:
2x+3*0=6
2x=6
x=3
(3,2)
C)
1.2x+2.4y=4.8
y-int:
1.2*0+2.4y=4.8
2.4y=4.8
24y=48
y=2
x-int:
1.2x+2.4*0=4.8
1.2x=4.8
12x=48
x=4
(4,2)
The LCM would be 14.. your textbook would be really helpful