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masya89 [10]
1 year ago
9

What is the following quotient? 3 sqrt 8 / 4 sqrt 6

Mathematics
2 answers:
Stells [14]1 year ago
7 0

Answer:

The correct option is D) \frac{\sqrt{3}}{2}

Step-by-step explanation:

We need to find out the quotient of  \frac{3\sqrt{8}}{4\sqrt{6}}

=\frac{3\sqrt{8}}{4\sqrt{6}}

Rewrite the above expression;

=\frac{3\times2 \sqrt{2}}{4\sqrt{6}}

=\frac{6\sqrt{2}}{4\sqrt{6}}

Cancel out the common term from numerator and denominator,

=\frac{3\sqrt{2}}{2\sqrt{6}}

=\frac{3\sqrt{2}}{2\sqrt{2}\times \sqrt{3}}

=\frac{3}{2\sqrt{3}}

Multiply numerator and denominator with \sqrt{3}

=\frac{3\sqrt{3}}{2\sqrt{3}\sqrt{3}}

=\frac{3\sqrt{3}}{2\times 3}

=\frac{3\sqrt{3}}{6}

=\frac{\sqrt{3}}{2}

Therefore, the correct option is D) \frac{\sqrt{3}}{2}

miv72 [106K]1 year ago
6 0
For this case we have the following expression:
 3sqrt (8) / 4sqrt (6)
 Rewriting we have:
 3sqrt (2 * 4) / 4sqrt (6)
 3 * 2sqrt (2) / 4sqrt (6)
 6sqrt (2) / 4sqrt (6)
 3sqrt (2) / 2sqrt (6)
 3sqrt (2) / (2sqrt (2) sqrt (3))
 3 / (2sqrt (3))
 3sqrt (3) / (3 * 2)
 sqrt (3) / (2)
 Answer:
 
the following quotient is:
 D.sqrt 3/2
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5 0
1 year ago
What value of x would make KM ∥ JN?
stepan [7]

Answer:

x = 10

Step-by-step explanation:

By the converse of the side-splitter theorem, if \dfrac{JK}{KL}= \dfrac{NM}{ML} , then KM ∥ JN.

Substitute the expressions into the proportion:

\dfrac{x-5}{x}= \dfrac{x-3}{x+4}

Cross-multiply:

(x – 5)(x+4) = x(x – 3).

Distribute:

x(x) + x(4) - 5(x) - 5(4) = x(x) + x(-3).

Multiply and simplify:

x^2 +4x- 5x - 20 = x^2-3x\\-x-20=-3x\\$Collect like terms$\\-x+3x=20\\2x=20\\$Divide both sides by 2\\x=10

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4 0
1 year ago
Combine to create an equivalent expression -n + (-4) - (-4n) +6
Sav [38]

Answer: The answer is 3n + 2

Step-by-step explanation: You will have to combine like terms:

=−n + −4 + 4n + 6

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3 0
2 years ago
One box of crackers costs $1.75. The crackers are advertised as “3 boxes for $5.25.” Which proportion can be used to represent t
Daniel [21]
A.  1/1.75 = 3/5.25 


Ignore this part I'm just trying to get at least 20 characters.
5 0
2 years ago
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A jet flying at 123 m/s banks to make a horizontal circular turn. The radius of the turn is 3810 m, and the mass of the jet is 2
aev [14]

Answer:

The magnitude of the necessary lifting force is 7.95N

Step-by-step explanation:

Force = mv^2/r

mass (m) = 2.00105kg, velocity (v) = 123m/s, radius (r) = 3810m

Force = 2.00105×123^2/3810 = 30273.89/3810 = 7.95N

7 0
1 year ago
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