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Montano1993 [528]
2 years ago
10

Which example illustrates the associative property of addition for polynomials? [(2x2 + 5x) + (4x2 – 4x)] + 5x3 = (2x2 + 5x) + [

(4x2 – 4x) + 5x3] [(2x2 + 5x) + (4x2 – 4x)] + 5x3 = [(4x2 – 4x) + (2x2 + 5x)] + 5x3 (2x2 + 5x) + [(4x2 – 4x) + 5x3] = (2x2 + 5x) + [5x3 + (4x2 – 4x)] [(2x2 + 5x) + (4x2 – 4x)] + 5x3 = [(5x + 2x2) + (–4x + 4x2)] + 5x3?
Mathematics
2 answers:
sertanlavr [38]2 years ago
4 0

Answer:

[(2x2 + 5x) + (4x2 – 4x)] + 5x3 =

(2x2 + 5x) + [(4x2 – 4x) + 5x3]

Step-by-step explanation:

arlik [135]2 years ago
3 0

Answer:

[(2x^2 + 5x) + (4x^2 – 4x)] + 5x^3 = (2x^2 + 5x) + [(4x^2 – 4x) + 5x^3]

Step-by-step explanation:

The associative property of addition states: (A +B) + C = A + (B + C).  That means, it doesn't matter which addition you make first, the final result remains the same. In this problem, A = (2x^2 + 5x), B = (4x^2 – 4x) and C = 5x^3. So, adding A to B and its result to C is the same as adding B to C and its result to A.

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How many terms are in the expression shown? <br><br> 2n + 5 – 3p + 4q<br><br> 1<br> 2<br> 3<br> 4
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Step-by-step explanation: A term can be a number, a variable, or a number times one or more variables.

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This means that there are <u>4</u> terms.

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Which expression is equivalent to x Superscript negative five-thirds? StartFraction 1 Over RootIndex 5 StartRoot x cubed EndRoot
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Option B : \frac{1}{\sqrt[3]{x^{5} } } is the expression equivalent to x^{-\frac{5}{3}

Explanation:

The given expression is x^{-\frac{5}{3}

Rewriting the expression x^{-\frac{5}{3} using the exponent rule, $a^{-b}=\frac{1}{a^{b}}$

Hence, we get,

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Simplifying, we get,

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Applying the rule, a^{\frac{1}{n}}=\sqrt[n]{a}

Thus, we have,

\frac{1}{\sqrt[3]{x^{5} } }

Now, we shall determine from the options that which expression is equivalent to x^{-\frac{5}{3}

Option A: \frac{1}{\sqrt[5]{x^{3} } }

The expression \frac{1}{\sqrt[5]{x^{3} } } is not equivalent to simplified expression  \frac{1}{\sqrt[3]{x^{5} } }

Thus, the expression \frac{1}{\sqrt[5]{x^{3} } } is not equivalent to x^{-\frac{5}{3}

Hence, Option A is not the correct answer.

Option B: \frac{1}{\sqrt[3]{x^{5} } }

The expression \frac{1}{\sqrt[3]{x^{5} } } is equivalent to the simplified expression  \frac{1}{\sqrt[3]{x^{5} } }

Thus, the expression \frac{1}{\sqrt[3]{x^{5} } } is equivalent to x^{-\frac{5}{3}

Hence, Option B is the correct answer.

Option C: -\sqrt[3]{x^5}

The expression -\sqrt[3]{x^5} is not equivalent to the simplified expression \frac{1}{\sqrt[3]{x^{5} } }

Thus, the expression -\sqrt[3]{x^5} is not equivalent to x^{-\frac{5}{3}

Hence, Option C is not the correct answer.

Option D: -\sqrt[5]{x^3}

The expression -\sqrt[5]{x^3} is not equivalent to the simplified expression \frac{1}{\sqrt[3]{x^{5} } }

Thus, the expression -\sqrt[5]{x^3} is not equivalent to x^{-\frac{5}{3}

Hence, Option D is not the correct answer.

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