A bookcase is 2.3 metres tall and the height of each self is 34 cm how many shelf are there?

A process that produces bottles of shampoo, when operating correctly, produces bottles whose contents weight, on average, 20 oun

valentinak56 [21]

Answer:

a. Descriptive statistics for the sample.

n= 9

mean X[bar]= 20.36

median Me= 20.30

min: 19.70

max: 21.40

standad deviation S= 0.61

b. 95% Confidence interval [19.88; 20.83]

c. Decision: Support H₀

Step-by-step explanation:

Hello!

I don't have excel so I cannot install PHstat, I've used a statistic software called Infostat for the calculations.

There was a random sample of 9 bottles of shampoo taken to test if the process is operating correctly. If it is, the bottles should weight on average 20 ounces (this would be our study parameter)

The study variable is X: the weight of a bottle of shampoo.

X~N(μ;σ²)

a.

Descriptive statistics for the sample.

n= 9

mean X[bar]= 20.36

median Me= 20.30

min: 19.70

max: 21.40

standad deviation S= 0.61

b. 95% Confidence interval.

Since the variable has a normal distribution and the population variance is unknown, the statistic to use to construct this interval is the Students t:

X[bar] ± $t_{n-1; 1- \alpha /2}$ * (S/√n)

20.36 ± $t_{8; 0.975}$ * (0.61/√9)

[19.88; 20.83]

c. You have to test the hypothesis that the production is operating correctly, if it is so, then:

H₀: μ = 20

H₁: μ ≠ 20

α: 0.05

The statistic value is t $_{H0}$ = 1.74

p-value: 0.1198

When you use the p-value to decide on a statistical hypothesis, you should always contrast it with the level of significance using the following rule:

If p-value ≤ α, then you reject the null hypothesis.

If p-value > α, then you do not reject the null hypothesis.

Since the p-value is greater than the significance level, you do not reject the null hypothesis. This means that the average weight of the shampoo bottles is 20 ounces, i.e. the process is operating correctly.

I hope it helps!

5 0

1 year ago

In USA Today (Sept. 5, 1996), the results of a survey involving the use of sleepwear while traveling were listed as follows: Mal

Wewaii [24]

Answers:

a) 0.018.

b) 0.614.

c) 0.166.

d) 0.479

Explanations:

1) Table

----------------------Male ----------- Female ---------- Total

Underwear ----- 0.220 ---------- 0.024 ---------- 0.244

Nightgown ----- 0.002 ---------- 0.180 ------------ 0.182

Nothing --------- 0.160 ----------- 0.018 ------------ 0.178

Pajamas --------- 0.102 ---------- 0.073 ----------- 0.175

T-shirt ------------ 0.046 --------- 0.088 ------------ 0.134

Other --------------0.084 --------- 0.003 ------------ 0.087

2) Check that it is a table of relative frequencies:

total = 0.244 + 0.182 + 0.178 + 0.175 + 0.134 + 0.087 = 1 ⇒ indeed this is a table of relative frequencies.

That means that each data is a probabiilty.

3) Soluitions:

(a) What is the probability that a traveler is a female who sleeps in the nothing?

relative frequency of females that use nothing = 0.018

(b) What is the probability that a traveler is male?

Probability that a traveler is a male = relative frequency of males = 0.220 + 0.002 + 0.160 + 0.102 + 0.046 + 0.084 = 0.614

(c) Assuming the traveler is male, what is the probability that he sleeps in pajamas?

It is the relative frequency of the males that sleep in pajamas divided by the relative frequency of males = 0.102 / 0.614 = 0.166

(d) What is the probability that a traveler is male if the traveler sleeps in pajamas or a T-shirt?

It is the relative frequency of males that sleep in pajamas plus that of the males that sleep in T-shirt, divided the total relative frequency of travelers that sleep in pajamas or T-shirt

i) relative frequency of males that sleeps in pajamas plus that of the males that sleeps in T-shirt = 0.102 + 0.046 = 0.148

ii) relative frequency of travelers that sleep in pajamas or T-shirt = 0.102 + 0.046 + 0.073 + 0.088 = 0.309

iii) quotient = 0.148 / 0.309 = 0.479

5 0

2 years ago

Read 2 more answers

Last Sunday 1,675 people visited the amusement park. 56% of the visitors were adults, 16% were teenagers, and 28% were children

Ierofanga [76]

Answer:

56

Step-by-step explanation:

4 0