Ask question

Ask question

All categories

2 years ago

12

Suppose that you are a manager of a clothing store and have just purchased 100 shirts for $15 each. After a month of selling the

shirts at the regular price, you plan to have a sale giving 30% of the original selling price. However ,you want to make a profit of $6 on each shirt at the sale price. What should you price the shirts at initially to ensure this?

2 answers:

Allisa [31]2 years ago

8 0

When you say "Plan to have a sale giving 30% of the original selling price", I suppose it's taking away 30%? So taking away 30% is like $15 - $4.5 = $10.50
Adding $6 more is $16.50.
If you're saying the manager is selling the price 30% of $15 then the price is $4.50 Plus the $6, it should be $10.50

So the answer should either be $16.50 or $10.50
Hope this helps! :)

Oduvanchick [21]2 years ago

6 0

He should set the original price at $27.30

You might be interested in

Use properties to rewrite the given equation. Which equations have the same solution as 2 3p-10.1 = 6.5p - 4 - 0.01p? Select two

SSSSS [86.1K]

2.3p - 10.1 = 6.5p - 4 - 0.01p

If we multiply this equation by 100 we have

230p - 1010 = 650p - 400 - p

So the right answer is this

7 0

2 years ago

Read 2 more answers

Round 645 to the nearest ten

Elena L [17]

645 rounded to the nearest 10 is 650, as 5 in the ones place rounds up.

6 0

2 years ago

Given that Ray E B bisects ∠CEA, which statements must be true? Select three options. m∠CEA = 90° m∠CEF = m∠CEA + m∠BEF m∠CEB =

FromTheMoon [43]

Answer:

Here is the question attached with.

$m\angle CEA =90 \ (deg)$

$m\angle BEF=135\ (deg)$

$\angle CEF$ is a straight line.

$\angle AEF$ is a right angled triangle.

Options $1,4,5,6$ are correct answers.

Step-by-step explanation:

⇒As $\ ray\ AE$ is ⊥ $FEC$ so it will forms right angled triangle then $m\angle CEA =90\ (deg)$ .

⇒Measure of $\angle BEF =135\ (deg)$ as $\angle BEF =\angle AEB +\angle AEF = (45+90)=135\ (deg)$ as $\angle AEB$ is the bisector of $\angle AEC$ ,meaning that $\angle AEB$ is half of $\angle AEC$ so $\angle AEB = 45\ (deg)$ .

⇒ $\angle CEF$ is a straight line as the angles measure over it is $180\ (deg)$ .

⇒Measure of $\angle AEF = 90\ (deg)$ from linear pair concept.

As $\angle CEA + \angle AEF = 180\ (deg)$ ,plugging the values of $m\angle CEA =90\ (deg)$ we have $\angle AEF = 90\ (deg)$ .

The other two options are false as:

$m\angle CEF=m\angle CEA + m\angle BEF = (90+135)=225$

it is exceeding $180\ (deg)$ whereas $\angle CEF$ is a

straight line.

And $m\angle CEB=2(m\angle CEA)$ is not true.

As $\angle CEA = 90\ (deg)$ and $\angle CEB=45\ (deg)$

So we have total $4$ answers.

The correct options are $1,4,5,6$ .

5 0

2 years ago

Read 2 more answers

If we were to make a poset of the form (A, |), where is the symbol for divisibility, which of the following sets A would yield a

Marrrta [24]

Answer:

IV. A+{1, 2, 3, 6, 12}

Step-by-step explanation:

The set of natural numbers form a poset number under relation of > or =. The discrete variables are used to form a poset. The symbols for divisibility in poset form are when an integer is divided by the variable without integer. The correct answer is therefore 4th option.

5 0

2 years ago

If each lap in a pool is 100 meters long, how many laps equal one mile? Round to the nearest tenth. (Hint: 1 foot ≈0.3048 meter)

aalyn [17]

If each lap in a pool is 100 meters long,how many laps equal one mile Round to the nearest tenth.(Hint:1 foot=0.3048 meter) 1 mile = 5280 ft lets do a ratio: 1ft/.3034m = x ft/100m the ft and meters sybols cancel, so 1/.3048 =x/100 so 100/.3038 = x = 329.164 so there are 329.164 ft for every 100 meters to find the number of laps to get to a mile which is 5280, do another ratio 329.164ft/100 m =5280 ft/xm the left side reduces to 3.29164 =5280/x you can compute this and see that 5280/3.29164 = 1604.064 meters 1604.064 meters *1 lap / 100m = 16.04064 laps are required to make a mile

7 0

2 years ago