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mezya [45]
2 years ago
14

The figure shown is often used to prove the Pythagorean theorem. Part of the proof is

Mathematics
1 answer:
mixas84 [53]2 years ago
7 0

Answer:

if you need hlep with any thing we can do a zoom if you now how to set it up.

Step-by-step explanation:

You might be interested in
a garden plot is to contain 240 sq. ft. if its length is to be 3 times its width,what should its dimensions be?
Nastasia [14]
W^2=80
W SQRT80
W=8.94 ANS.FOR THE WIDTH
L=3*8.94=26.83 ANS.FOR THE LENGTH
PROOF:
240=8.94*26.83
240=240

3 0
2 years ago
Dan bought a new computer for $900. Each year, the value of the computer decreased by 25% of the previous year’s value. At this
lys-0071 [83]

Answer:

$120.14

Step-by-step explanation:

This question is an example of a compound percentage decrease.

To work this out you would first need to convert the percentage of 25 into a decimal. You can do this by dividing the percentage of 25 by 100, this gives you 0.25. This is because percentages are out of 100.

The next step is to minus 0.25 from 1, this gives you 0.75. This is because we are working out the percentage decrease.

The final step is to multiply the amount of 900 by 0.75 to the power of 7, this gives you $120.14.

1) Divide 25 by 100.

25/100=0.25

2) Minus 0.25 from 1.

1-025=0.75

3) Multiply 900 by 0.75 to the power of 7.

900*0.75^7=120.14

8 0
2 years ago
The average annual amount American households spend for daily transportation is $6312 (Money, August 2001). Assume that the amou
lions [1.4K]

Answer:

(a) The standard deviation of the amount spent is $3229.18.

(b) The probability that a household spends between $4000 and $6000 is 0.2283.

(c) The range of spending for 3% of households with the highest daily transportation cost is $12382.86 or more.

Step-by-step explanation:

We are given that the average annual amount American households spend on daily transportation is $6312 (Money, August 2001). Assume that the amount spent is normally distributed.

(a) It is stated that 5% of American households spend less than $1000 for daily transportation.

Let X = <u><em>the amount spent on daily transportation</em></u>

The z-score probability distribution for the normal distribution is given by;

                          Z  =  \frac{X-\mu}{\sigma}  ~ N(0,1)

where, \mu = average annual amount American households spend on daily transportation = $6,312

           \sigma = standard deviation

Now, 5% of American households spend less than $1000 on daily transportation means that;

                      P(X < $1,000) = 0.05

                      P( \frac{X-\mu}{\sigma} < \frac{\$1000-\$6312}{\sigma} ) = 0.05

                      P(Z < \frac{\$1000-\$6312}{\sigma} ) = 0.05

In the z-table, the critical value of z which represents the area of below 5% is given as -1.645, this means;

                           \frac{\$1000-\$6312}{\sigma}=-1.645                

                            \sigma=\frac{-\$5312}{-1.645}  = 3229.18

So, the standard deviation of the amount spent is $3229.18.

(b) The probability that a household spends between $4000 and $6000 is given by = P($4000 < X < $6000)

      P($4000 < X < $6000) = P(X < $6000) - P(X \leq $4000)

 P(X < $6000) = P( \frac{X-\mu}{\sigma} < \frac{\$6000-\$6312}{\$3229.18} ) = P(Z < -0.09) = 1 - P(Z \leq 0.09)

                                                            = 1 - 0.5359 = 0.4641

 P(X \leq $4000) = P( \frac{X-\mu}{\sigma} \leq \frac{\$4000-\$6312}{\$3229.18} ) = P(Z \leq -0.72) = 1 - P(Z < 0.72)

                                                            = 1 - 0.7642 = 0.2358  

Therefore, P($4000 < X < $6000) = 0.4641 - 0.2358 = 0.2283.

(c) The range of spending for 3% of households with the highest daily transportation cost is given by;

                    P(X > x) = 0.03   {where x is the required range}

                    P( \frac{X-\mu}{\sigma} > \frac{x-\$6312}{3229.18} ) = 0.03

                    P(Z > \frac{x-\$6312}{3229.18} ) = 0.03

In the z-table, the critical value of z which represents the area of top 3% is given as 1.88, this means;

                           \frac{x-\$6312}{3229.18}=1.88                

                         {x-\$6312}=1.88\times 3229.18  

                          x = $6312 + 6070.86 = $12382.86

So, the range of spending for 3% of households with the highest daily transportation cost is $12382.86 or more.

8 0
2 years ago
Question: 2. Musah Stands At The Centre Of A Rectangular Field. He First Takes 50 Steps North, Then 25 Steps West And Finally 50
Iteru [2.4K]

Answer:

60.36 steps West from centre

85.36 steps North from centre

Step-by-step explanation:

<em>Refer to attached</em>

Musah start point and movement is captured in the picture.

  • 1. He moves 50 steps to North,
  • 2. Then 25 steps to West,
  • 3. Then 50 steps on a bearing of 315°. We now North is measured 0°

or 360°, so bearing of 315° is same as North-West 45°.

<em />

<em>Note. According to Pythagorean theorem, 45° right triangle with hypotenuse of a has legs equal to a/√2.</em>

<u />

<u>How far West Is Musah's final point from the centre?</u>

  • 25 + 50/√2 ≈ 60.36 steps

<u>How far North Is Musah's final point from the centre?</u>

  • 50 + 50/√2 ≈ 85.36 steps

7 0
1 year ago
David drove a distance of 187km, correct to 3 significant figures. He used 28 litres of petrol, correct to 2 significant figures
mote1985 [20]
David drove a distance (d) of 187km, to 3 significant figures. He used 28 litres of petrol (p), to 2 significant figures.
The petrol consumption (c) in km per litre is given by the formula: c= d/p
By considering bounds, work out the value of c, to a suitable degree of accuracy. You must show your working and give a reason for your answer. I'm not totally comfortable with sig figs, but I believe that the answer can only be expressed as accurately as least number of sig figs of any data used in the computations.....thus ....the answer should be rounded to 2 sig figs

So

187 / 28 = 6.67 ⇒ 6.7 km / L [rounded to 2 sig figs ].
8 0
2 years ago
Read 2 more answers
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