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jolli1 [7]
1 year ago
6

Choose which statements are true about Pi. Check all that apply. Piis a whole number. Piis double the radius. Piis approximately

3.14. Pirepresents the ratio of the circumference to the diameter. Piis approximately StartFraction 22 over 7 EndFraction
Mathematics
2 answers:
Ludmilka [50]1 year ago
7 0

Answer:

Answer in explanation

Step-by-step explanation:

In this question, we would be examining the validity of some statements on the number π(pi)

π Is a whole number?

This is wrong, π is a fraction of 22 to 7 parts I.e 22/7

π Is double the radius?

This is wrong. It is the diameter that is double the radius

π Is approximately 3.14?

This is correct to an extent. The actual value in decimal is around 3.142857142857143 which makes the 3.14 somehow correct

π represents the ratio of the circumference of the circle to the diameter?

This is correct.

Mathematically, circumference C = π * diameter D

Hence C/D = π

π Is approximately 22/7?

This is correct. This is the ratio used for π

Viefleur [7K]1 year ago
3 0

Answer:

• Pi is approximately 3.14.

• Pi represents the ratio of the circumference to the diameter

• Pi is approximately 22/7

Step-by-step explanation:

From the options given:

A. Pi is a whole number:

Pi is equivalent to 3.141592654. Therefore, pi is not a whole number.

B. Pi is double the radius

Pi is not double the radius of a circle. Pi is a constant.

C. Pi is approximately 3.14.

In some cases, pi can be approximated as 3.14 instead of 3.141592654.

D. Pi represents the ratio of the circumference to the diameter.

Circumference of a circle, C = 2 × pi × radius

= 2 × pi × D/2 = pi × Diameter

Pi = circumference/Diameter

E. Pi is approximately 22/7

22/7 = 3.142857143

This is also a correct approximation.

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Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

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Now, find the margin of error M as such

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(a) The desired margin of error is $0.10.

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M = z*\frac{\sigma}{\sqrt{n}}

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0.1\sqrt{n} = 1.96*0.25

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(\sqrt{n})^{2} = (\frac{19.6*0.25}{0.1})^{2}

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(b) The desired margin of error is $0.06.

This is n when M = 0.06. So

M = z*\frac{\sigma}{\sqrt{n}}

0.06 = 1.96*\frac{0.25}{\sqrt{n}}

0.06\sqrt{n} = 1.96*0.25

\sqrt{n} = \frac{19.6*0.25}{0.06}

(\sqrt{n})^{2} = (\frac{19.6*0.25}{0.06})^{2}

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(c) The desired margin of error is $0.05.

This is n when M = 0.05. So

M = z*\frac{\sigma}{\sqrt{n}}

0.05 = 1.96*\frac{0.25}{\sqrt{n}}

0.05\sqrt{n} = 1.96*0.25

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Rounding up, 97

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