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Ksenya-84 [330]

2 years ago

14

Fido weighs 26 pounds more than Fifi. Fifi weighs 12 pounds less than Rover. If the sum of their weights is 71, how much does Fi

fi weigh?

1 answer:

crimeas [40]2 years ago

4 0

Answer: are their options?

Step-by-step explanation:

You might be interested in

Part A: Solve −np − 70 < 40 for n.

Trava [24]

Solve for n the first can be like:-NP<40+70. -NP<110 the second one can be like : 4w-7k =28. solve for k and then, -7k=28-4w divide both sides by -7 that equal to k =-4-4w

5 0

1 year ago

Shane and Abha earned a team badge that required their team to collect no less than 2000 cans for recycling. Abha collected 178

Katarina [22]

Answer:

$2x+178\geq 2000$

Step-by-step explanation:

Let, the number of cans collected by Shane = x.

So, the number of cans collected by Abha = x + 178.

Since, at least 2000 cans are required to be collected.

Thus, we have the inequality,

Number of cans by Shane + Number of cans by Abha ≥ 2000.

i.e. $x+(x+178)\geq 2000$

i.e. $2x+178\geq 2000$

Thus, the required inequality is $2x+178\geq 2000$ .

4 0

2 years ago

18. Manufacturers often package products in a way that uses the least amount of material One measure of the efficiency of a pack

Lemur [1.5K]

Answer:

a. $E=\frac{2h+2r}{rh}$

b.

E of first can = $E=\frac{2h+2r}{rh}$

E of second can = $E=\frac{h+2r}{rh}$

c. Yes

Step-by-step explanation:

The efficiency ratio is:

E = Surface Area / Volume

a.

We can write:

$E=\frac{S}{V}$

Where

S is surface area of cylinder

V is volume of cylinder

The formulas are:

S = $2\pi rh+2\pi r^2$

V = $\pi r ^2 h$

So, the <u>efficiency ratio (E) </u>is:

$E=\frac{2\pi rh+2\pi r^2}{\pi r^2 h}\\E=\frac{\pi r(2h+2r)}{\pi r(rh)}\\E=\frac{2h+2r}{rh}$

b.

The first can has radius "r" and height "h", so the efficiency ratio is:

$E=\frac{S}{V}\\E=\frac{2\pi rh+2\pi r^2}{\pi r^2 h}\\E=\frac{\pi r(2h+2r)}{\pi r(rh)}\\E=\frac{2h+2r}{rh}$

The second can has same height, "h", and twice radius, "2r", so the efficiency ratio becomes:

$E=\frac{S}{V}\\E=\frac{2\pi (2r)h+2\pi (2r)^2}{\pi (2r)^2 h}\\E=\frac{4\pi rh +8\pi r^2}{4\pi r^2h}\\E=\frac{4\pi r(h+2r)}{4\pi r(rh)}\\E=\frac{h+2r}{rh}$

c.

We now need to say if the company made a good decision or not.

If you look at both the Efficiency ratios above, you will see that the difference is in the numerator.

The first can has "2h"

The second can has "h"

The "2h" makes the numerator for the first can BIGGER than the "h" of the second can, so the Efficiency ratio of first can is thus, BIGGER.

We need smaller ratio.

So, 2nd can has indeed smaller ratio, so the company made a good decision.

6 0

2 years ago

Jim's work evaluating 2 (three-fifths) cubed is shown below. 2 (three-fifths) cubed = 2 (StartFraction 3 cubed Over 5 EndFractio

Blizzard [7]

Answer:

$2(\frac{3}{5}) ^{3}=2(\frac{3^3}{5^3})$ and not $2(\frac{3}{5}) ^{3}=2(\frac{3^3}{5})$

Step-by-step explanation:

Jim's work evaluating $2(\frac{3}{5}) ^{3}$ is shown:

$2(\frac{3}{5}) ^{3}=2(\frac{3^3}{5})=2(\frac{3X3X3}{5})=2(\frac{27}{5})=\frac{54}{5}$

If you look at the Second step, the exponent is taken over only the numerator. It should have been taken over both the numerator and denominator as shown below.

$2(\frac{3}{5}) ^{3}=2(\frac{3^3}{5^3})$

The correct workings therefore is:

$2(\frac{3}{5}) ^{3}=2(\frac{3^3}{5^3})=2(\frac{3X3X3}{5X5X5})=2(\frac{27}{125})=\frac{54}{125}$

7 0

2 years ago

Read 2 more answers

Graph the line y = kx +1 if it is known that the point M belongs to it: M(1,3)

tigry1 [53]

Answer:

$M(x,y) = (1,3)$ belongs to the line $y = 2\cdot x +1$ . Please see attachment below to know the graph of the line.

Step-by-step explanation:

From Analytical Geometry we know that a line is represented by this formula:

$y=k\cdot x + b$

Where:

$x$ - Independent variable, dimensionless.

$y$ - Dependent variable, dimensionless.

$k$ - Slope, dimensionless.

$b$ - y-Intercept, dimensionless.

If we know that $b = 1$ , $x = 1$ and $y = 3$ , then we clear slope and solve the resulting expression:

$k = \frac{y-b}{x}$

$k = \frac{3-1}{1}$

$k = 2$

Then, we conclude that point $M(x,y) = (1,3)$ belongs to the line $y = 2\cdot x +1$ , whose graph is presented below.

3 0

1 year ago