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Korolek [52]
1 year ago
15

What is 27 players for 12 spots expressed as a rate?

Mathematics
1 answer:
Anika [276]1 year ago
4 0

Answer:

9 p 4 s

Step-by-step explanation:

That's the answer.

You might be interested in
Which statement is true about the graphs of the two lines y = x + 2 and y = x ? The lines are perpendicular to each other becaus
o-na [289]
The lines y=x+2 and y=x are parallel, because they have the same slope.
6 0
2 years ago
Read 2 more answers
During April of 2013, Gallup randomly surveyed 500 adults in the US, and 47% said that they were happy, and without a lot of str
Brilliant_brown [7]

Answer:

number of successes

                 k  =  235

number of failure

                 y  = 265

The   criteria are met    

A

    The sample proportion is  \r p  =  0.47

B

    E =4.4 \%

C

What this mean is that for N number of times the survey is carried out that the which sample proportion obtain will differ from  the true population proportion will not  more than 4.4%

Ci  

   r =  0.514 = 51.4 \%

 v =  0.426 =  42.6 \%

D

   This 95% confidence interval  mean that the the chance of the true    population proportion of those that are happy to be exist within the upper   and the lower limit  is  95%

E

  Given that 50% of the population proportion  lie with the 95% confidence interval  the it correct to say that it is reasonably likely that a majority of U.S. adults were happy at that time

F

 Yes our result would support the claim because

            \frac{1}{3 } \ of  N    < \frac{1}{2}  (50\%) \ of \  N  , \ Where\ N \ is \ the \  population\ size

Step-by-step explanation:

From the question we are told that

     The sample size is  n  = 500

     The sample proportion is  \r p  =  0.47

 

Generally the number of successes is mathematical represented as

             k  =  n  *  \r p

substituting values

             k  =  500 * 0.47

            k  =  235

Generally the number of failure  is mathematical represented as

           y  =  n  *  (1 -\r p )

substituting values

           y  =  500  *  (1 - 0.47  )

           y  = 265

for approximate normality for a confidence interval  criteria to be satisfied

          np > 5  \ and  \ n(1- p ) \ >5

Given that the above is true for this survey then we can say that the criteria are met

  Given that the confidence level is  95%  then the level of confidence is mathematically evaluated as

                       \alpha  = 100 - 95

                        \alpha  = 5 \%

                        \alpha  =0.05

Next we obtain the critical value of  \frac{\alpha }{2} from the normal distribution table, the value is

                 Z_{\frac{ \alpha }{2} } =  1.96

Generally the margin of error is mathematically represented as  

                E =  Z_{\frac{\alpha }{2} } *  \sqrt{ \frac{\r p (1- \r p}{n} }

substituting values

                 E =  1.96 *  \sqrt{ \frac{0.47 (1- 0.47}{500} }

                 E = 0.044

=>               E =4.4 \%

What this mean is that for N number of times the survey is carried out that the proportion obtain will differ from  the true population proportion of those that are happy by more than 4.4%

The 95% confidence interval is mathematically represented as

          \r p  - E <  p  <  \r p  + E

substituting values

        0.47 -  0.044 <  p  < 0.47 +  0.044

         0.426 <  p  < 0.514

The upper limit of the 95% confidence interval is  r =  0.514 = 51.4 \%

The lower limit of the   95% confidence interval is  v =  0.426 =  42.6 \%

This 95% confidence interval  mean that the the chance of the true population proportion of those that are happy to be exist within the upper and the lower limit  is  95%

Given that 50% of the population proportion  lie with the 95% confidence interval  the it correct to say that it is reasonably likely that a majority of U.S. adults were happy at that time

Yes our result would support the claim because

            \frac{1}{3 }  < \frac{1}{2}  (50\%)

 

3 0
1 year ago
D(-3+x)=kx+9 solve for x
Gnesinka [82]

d(-3 + x) = kx + 9

  • Distribute d inside the parentheses.

-3d + dx = kx + 9

  • Subtract kx from both sides.

-3d + dx - kx = 9

  • Add 3d to both sides.

dx - kx = 9 + 3d

  • Factor x out of dx - kx.

x(d - k) = 9 + 3d

  • Divide both sides by d - k.

x = \frac{9+3d}{d-k}

  • If you want to simplify this even more, factor 3 out of the numerator.
<h3>x = \frac{3(d + 3)}{d-k}</h3>
5 0
2 years ago
If a certain number is increased by 5 one half of the result is three-fifths of the excess of 61 over the number find the number
PSYCHO15rus [73]

Answer:

= 391/11

Let say number = N

a certain number is increased by 5

= N + 5

,one-half of the result

= (N + 5)/2

Three -fifths of the excess of 61 over the number.

= (3/5)(61 - N)

Equating both

(N + 5)/2  = (3/5)(61 - N)

multiplying by 10 both sides

=> 5(N + 5) = 6(61 - N)

=> 5N + 25 = 366 - 6N

=> 11N = 391

=> N = 391/11

Step-by-step explanation:

8 0
1 year ago
Use Lagrange multipliers to find three positive numbers whose sum is 210 and whose product is maximum. (Enter your answers as a
nalin [4]

Answer: the three positive numbers are; 70, 70, 70

Step-by-step explanation:

Given that sum is equal = 210

Lets ( x, y, z ) be the three positive numbers

such that

x + y + z = 210

what is the maximum of xyz

take f(x,y,z) = xyz

Q(x,y,z) = 0

x + y + z -210 = 0

consider the function

F(x,y,z) = f(x,y,z) + λQ(x,y,z)

F = xyz + λ(x+y+z-210)

dF/dx = 0 ⇒ yz + λ(1) = 0 ⇒ λ = -yz   ..............equ(1)

dF/dy = 0 ⇒ xz + λ(1) = 0 ⇒ λ = -xz.................equ(2)

dF/dz = 0 ⇒ xy + λ(1) = 0 ⇒ λ = -xy...............equ(3)

Now

equ(1)/equ(2) ⇒ λ/λ = -yz/-xz ⇒ x = +y

equ(1)/equ(3) ⇒ λ/λ = - yz/-xy ⇒ x = +z

⇒ y = z = x

by substitution

x + y + z = 210

x + x + x = 210

3x = 210

x = 210/3 = 70

∴ x, y, z = 70, 70 ,70

MAXIMUM

∛xyz = 70  { when x = y = z = 70}

7 0
1 year ago
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