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neonofarm [45]
2 years ago
10

The Dot plot shows the salaries for the employees that two small companies before a new company head is hired on each company se

lect all the statements that must be true
A. the mean and the medium values of salary shown in the Dot plot for company 2 are the same.

B.the standard deviation of salary is shown in the Dot plot for company 2 is greater than the standard deviation of salaries at company 1.

C. the median values of salary shown in the dot plots for the two companies are about the same.

D.the median value of salaries at company one will remain unchanged after a company head is hired to have a salary of $500,000 (Five Hundred thousand dollars)

E.the new company head with a salary of $500,000 will affect the mean value for salaries accompany to more than the median value for salaries at company 2 more then the median value for salaries at company 2.​

Mathematics
1 answer:
Dmitry_Shevchenko [17]2 years ago
8 0

Answer:

D

Step-by-step explanation:

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Suppose you have 20 coins that total $3.00. Some coins are nickels and some are quarters. Which of the following pairs of equati
kap26 [50]

Answer:

Step-by-step explanation:

n + q = 20

.05n + .25q = 3.00

5n + 25q = 300

 n + q = 20

5n + 25q = 300

-5n - 5q = -100

20q = 200

q = 10 quarters

n + 10 = 20

n = 10 nickels

(10 nickels, 10 quarters)

5 0
2 years ago
On Monday, the closing value of a share of stock in Company ABC, was 74.01. On Tuesday, it closed at 73.67, and on Wednesday, it
Elenna [48]

Answer:

957.71

Step-by-step explanation:

Given: On Monday, the closing value of a share of stock in Company ABC, was 74.01. On Tuesday, it closed at 73.67, and on Wednesday, it closed at 74.32. On Thursday, the change in stock value was -1.48. And, on Friday, Company ABC's stock gained 0.89points.

To Find: One shareholder owns 13shares of Company ABC's stock. What was the total value of their stock in this company at the close of Tuesday.

Solution:

Closing value of Shares of company ABC on Monday =74.01

Closing value of Shares of company ABC on Tuesday =73.67

Closing value of Shares of company ABC on Wednesday =74.32

on Thursday change in stock value was -1.48

Closing value of Shares of company ABC on Thursday =72.84

on Friday comapny's stock gained 0.89 points

Closing value of Shares of company ABC on Friday =73.73

As one shareholder owns 13 shares of company

Total value of shares on Tuesday is

                         =\text{number of shares}\times\text{closing stock value on tuesday}

                         =13\times73.67

                         =957.71

Hence total value of shareholder's share on close of Tuesday is 957.71

6 0
2 years ago
Read 2 more answers
Suppose we have two thermometers. One thermometer is very precise but is delicate and heavy (X). We have another thermometer tha
makvit [3.9K]

Answer:

Step-by-step explanation:

(a)   H0: μ_D=0

      Ha: μ_D ≠ 0

b) Find attached the solution

(c)  By technology,

p - value = 0.4437

Hence, the p-value is 0.4437

8 0
2 years ago
Ricardo has a square hot tub. He wants to build a square pool next to it that is a dilation of the hot tub using a scale factor
PilotLPTM [1.2K]

Answer:

The length of one side of the hot tub is 4.8ft

Step-by-step explanation:

Given

Shape: Square

k = 5 -- scale factor

B'C' = 24

Required

Side length of ABCD (the hot tub)

From the question, we understand that

ABCD \to D_5 \to A'B'C'D  ABCD dilated by 5 to A'B'C'D

This implies that:

BC * 5 = B'C' i.e. the sides of ABCD is multiplied by 5 to get A'B'C'D

So, we have:

BC * 5 = 24

Divide by 5

BC = 4.8

5 0
1 year ago
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Let the sample space be S = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}. Suppose the outcomes are equally likely. Compute the probability of
Crazy boy [7]

Answer:

The probability is 3/5

Step-by-step explanation:

Given,

Sample space, S = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10},

⇒ n(S) = 10,

Odd numbers less than 7 = 1, 2, 3, 4, 5 and 6

i.e. E = {1, 2, 3, 4, 5, 6}

⇒ n(E) = 6,

\because \text{Probability}=\frac{\text{Favourable outcomes}}{\text{Total outcomes}}

So, the probability of the event E,

P(E) =\frac{n(E)}{n(S)}

=\frac{6}{10}

=\frac{3}{5}

5 0
2 years ago
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