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nignag [31]
2 years ago
9

In two or more complete sentences explain how you would set up and solve the following equation: Peter opened his account with $

910 and withdrew $40 per week. Marla opened her account with $470 and withdrew $20 weekly. In how many weeks will their accounts be equal?
Mathematics
1 answer:
Black_prince [1.1K]2 years ago
3 0
Peter will have $910 - $40 * x on his account, where x is the number of the weeks. Marla will have $470 - $20 * x.
910 - 40 x = 470 - 20 x
910 - 470 = 40 x - 20 x
440 = 20 x
x = 440 : 20
x = 22
910 - 40 * 22 = 910 - 880 = $30
470 - 20 * 22 = 470 - 440 = $30
Answer: Their accounts will be equal in 22 weeks ( both of them will have $30 ).
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Answer:

2.5

Step-by-step explanation:

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The data set below represents the ages of 36 executives. find the percentile that corresponds to an age of 4141 years old. 2828
solong [7]

Answer:

37th percentile.

Step-by-step explanation:

We have been given a data set that represents the ages of 36 executives. We are asked to find the percentile that corresponds to an age of 41 years.

28, 29, 29, 32, 32, 33, 34, 34, 34, 34, 37, 37, 38, 41, 41, 42, 45, 45, 47, 47, 47, 48, 50, 51, 53, 56, 56, 56, 61, 61, 62, 63, 64, 64, 65, 66.

Let us count the number of data points below and at 41.

We can see that the number of data points at and below 41 is 13.

We will use percentile formula to solve our given problem.

\text{Percentile rank of x}=\frac{\text{Number of values below x}}{\text{Total number of data points}}\times 100

\text{Percentile rank of 41}=\frac{13}{36}\times 100

\text{Percentile rank of 41}=0.361111\times 100

\text{Percentile rank of 41}=36.11\approx 37

Therefore, the percentile rank that corresponds to age of 41 years old is 37th percentile.  

8 0
2 years ago
HELP!!!! 2 dot plots. Both number lines go from 0 to 10. Plot 1 is titled fifth grade. There are 2 dots above 1, 3 above 2, 1 ab
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5th grade mean - 4.67

7th grade mean - 3.46

5th-grade median - 5

7th-grade median - 3.5

7 0
1 year ago
Read 2 more answers
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The position of an object in a video game is represented by an ordered pair. The coordinates of the ordered pair give the
Rudik [331]

Answer:

a. 457 pixels b. 229 pixels c. 114 pixels

Step-by-step explanation:

a. Using d = √[(x₂ - x₁)² + (y₂ - y₁)²] to find the distance apart of the coordinates (x₁, y₁) and (x₂, y₂) where (x₁, y₁) = (36, 315) and (x₂, y₂) = (410, 53).

So, d = √[(x₂ - x₁)² + (y₂ - y₁)²]

= √[(410 - 36)² + (53 - 315)²]

= √[374² + 262²]

= √[139,876 + 68,644]

= √208,520

= 456.64

= 457 pixels to the nearest pixel.

b. Since the players are d' distance apart, and moving at a same speed of v, if they approach each other, they meet at time t. So player A covers a distance of d = vt. For them to meet, player B approaches and covers a distance of d = d' - vt. So they meet when vt = d' - vt.

Solving this, we have

vt = d' - vt

vt + vt = d'

2vt = d'

t = d'/2v

Substituting t into d = vt, we have

d = vt

= v(d'/2v)

= d'/2

= 457/2

= 228.5

≅ 229 pixels  to the nearest pixel

c. Since the players are d' distance apart, and player A moves at a speed three times that of player B, if player B moves with speed v, then player A moves with speed 3v, as they approach each other, they meet at time t. So player A covers a distance of d = 3vt. For them to meet, player B approaches and covers a distance of d = d' - vt. So they meet when 3vt = d' - vt.

Solving this, we have

3vt = d' - vt

3vt + vt = d'

4vt = d'

t = d'/4v

Substituting t into d = vt, we have

d = vt

= v(d'/4v)

= d'/4

= 457/4

= 114.25

≅ 114 pixels to the nearest pixel

8 0
1 year ago
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