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2 years ago

9

Kent has two similar cylindrical pipes, Pipe A and Pipe B. The radius of Pipe A is 6 cm, and the radius of Pipe B is 2 cm. What

is the ratio of the
volume of Pipe A to the volume of Pipe B?
A)3:1
B)6:2
C)27:1
D)9:3

1 answer:

Alchen [17]2 years ago

7 0

Answer: C)27:1

Step-by-step explanation:

Given, Kent has two similar cylindrical pipes, Pipe A and Pipe B. The radius of Pipe A is 6 cm, and the radius of Pipe B is 2 cm.

Volume of cylinder = $\pi r^2h$ , where r= radius and h = height.

Also, If two figures are similar then ratio of volume is equal to the cube of any dimension .

The ratio of the volume of Pipe A to the volume of Pipe B is given by :-

$\dfrac{\text{Volume of pipe A}}{\text{Volume of pipe B}}=\dfrac{6^3}{2^3}\\\\=\dfrac{216}{8}=\dfrac{27}{1}$

Thus, the ratio of the volume of Pipe A to the volume of Pipe B = 27:1

So, the correct option is C)27:1.

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Let the coordinate of the points W, V and R are $(x_1,y_1), (x_2,y_2),$ and $(x_s,y_s)$ respectively.

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~P(X)= 0P10 * P(yes)^0 * P(no)^10 + 1P10 * P(yes)^1 * P(no)^9 + 2P10 * P(yes)^2 * P(no)^8 =

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