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Rzqust [24]
2 years ago
10

32​% of U.S. adults say they are more likely to make purchases during a sales tax holiday. You randomly select 10 adults. Find t

he probability that the number of adults who say they are more likely to make purchases during a sales tax holiday is​ (a) exactly​ two, (b) more than​ two, and​ (c) between two and​ five, inclusive
Mathematics
1 answer:
Lorico [155]2 years ago
8 0

Answer:

A.  21.06%

B. 66.88%

C. 81.56%

Step-by-step explanation:

There are two possible answer for the question asked, yes(more likely to make purchases) or no. The probability for a random adults answer yes to the question is 32% so the probability that the adults answer no is 68%.

(a) exactly​ two

There is only one case for this question, 2 people say yes and 8 people say no. The calculation for this problem will be:

2P10 * P(yes)^2 * P(no)^8= 10!/2!8!* 32%^2  * 68%^8 = 0.21066= 21.06%

(b) more than​ two

There are a lot of case for more than two, its easier to find out the negation of the probability which is "two or less". Case that fulfill "two or less" will be: 2 yes and 8 no

1 yes and 9 no

0 yes and 10 no

The calculation for the negation will be:

~P(X)= 0P10 * P(yes)^0 * P(no)^10   +   1P10 * P(yes)^1 * P(no)^9   +  2P10 * P(yes)^2 * P(no)^8  =

10!/0!10!* 32%^0  * 68%^10    +   10!/1!9!* 32%^1  * 68%^9   +   10!/2!8!* 32%^2  * 68%^8

0.02113 + 0.09947 + 0.21066  =  0.33126= 33.12%

Since its the negation, you need to subtract 1 with the negation

P(X)= 1 - ~P(X)

P(X)= 1 - 33.12%= 66.88%

(c) between two and​ five, inclusive

Same formula as above, but the case is:

2 yes and 8 no

3 yes and 7 no

4 yes and 6 no

5 yes and 5 no

The calculation will be:

2P10 * P(yes)^2 * P(no)^8 + 3P10 * P(yes)^3 * P(no)^7 + 4P10 * P(yes)^4 * P(no)^6 + 5P10 * P(yes)^5 * P(no)^5 =

10!/2!8!* 32%^2  * 68%^8    +   10!/3!7!* 32%^3  * 68%^7   +   10!/4!6!* 32%^4  * 68%^6  +  10!/5!5!* 32%^5  * 68%^5

0.21066 + 0.26435 + 0.21770 + 0.1229= 0.81561= 81.56%

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Answer:

There are 11550 possible selections

Step-by-step explanation:

Given

Men = 7

Women = 11

Required

How many ways can 4 men and 4 women be selected

The keyword in the question is SELECTION and it means COMBINATION;

So, number of selection is:

Number = Men * Women

Number = ^7C_4 * ^{11}C_4

This gives

Number = \frac{7!}{(7-4)!4!} * \frac{11!}{(11-4)!4!}

Number = \frac{7!}{3!4!} * \frac{11!}{7!4!}

Number = \frac{7 * 6 * 5 * 4!}{3!4!} * \frac{11 * 10 * 9 * 8 * 7!}{7!4!}

Number = \frac{7 * 6 * 5}{3!} * \frac{11 * 10 * 9 * 8}{4!}

Number = \frac{7 * 6 * 5}{3 * 2 * 1} * \frac{11 * 10 * 9 * 8}{4 * 3 * 2 * 1}

Number = \frac{7 * 6 * 5}{6} * \frac{11 * 10 * 9 * 8}{4 * 3 * 2 * 1}

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Number = 7 * 5 * \frac{7920}{24}

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Number = 11550

Hence;

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Barry also looks into the cost of repaying an easy access loan for $1000. The up-front cost of the loan is $3 for every $20 borr
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Barry has to pay back $1150

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We can set up an equation to help solve this problem

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Answer:

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Step-by-step explanation:

From the given information;

A political polling agency wants to take a random sample of registered voters and ask whether or not they will vote for a certain candidate.

A random sample is usually an outcome of any experiment that cannot be predicted before the result.

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